Chapter 14 - Square Testing - Statistics for Business | Trường Đại học Quốc tế, Đại học Quốc gia Thành phố HCM

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Chapter 14 - Square Testing - Statistics for Business | Trường Đại học Quốc tế, Đại học Quốc gia Thành phố HCM

Chapter 14 - Square Testing - Statistics for Business | Trường Đại học Quốc tế, Đại học Quốc gia Thành phố HCM được sưu tầm và soạn thảo dưới dạng file PDF để gửi tới các bạn sinh viên cùng tham khảo, ôn tập đầy đủ kiến thức, chuẩn bị cho các buổi học thật tốt. Mời bạn đọc đón xem!

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Statistics for Business | Chapter 14: Chi - Square Test s
1
STATISTICS FOR BUSINESS [IUBA]
CHAPTER 14
CHI - SQUARE TESTING
CHI – SQUARE TESTING PROCESS
STEP 01: Deter mine the nu ll and alt ernat ive hypotheses
STEP 02: Deter mine t he expected counts and observed counts of data points in
dif fer ent cells.
STEP 03: Compute the test stat istic value (based on the difference between the
observed and the expected; Hint : Establishing a t able) and the critical value
(based on t he level of significance and chi – square distr ibution).
STEP 04: Compare the test st atistic value wit h the crit ical value and make a decision.
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Statistics for Business | Chapter 14: Chi - Square Test s
2
PART I
A CHI – SQUARE TEST FOR GOODNESS OF FIT
CHI-SQUARE TESTING PROCESS
STEP 01: Deter mine the nu ll and alt ernat ive hypotheses
: The probabilit ies of occurrence of event s
,
, …,
are given by
the specif ied probabilit ies
,
, …,
: The probabilities of the event s not the
stated in t he null
hypothesis
STEP 02: Deter mine the observed counts and the expected counts
(
= 
)
of data
points in different cells.
STEP 03: Compute the test stat istic value and the critical value
The test stat ist ic value (based on the difference between the observed and
the expect ed):

=
(
)

Hint : Establishing a table
The crit ical value (based on the level of significance
(
)
):

=
,
STEP 04: Compare the test st atistic value wit h the crit ical value and make a decision.
Based on the level of significance,
+ We can reject t he null hypothesis
if

>

+ We cannot reject t he null hypothesis
if

<

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Statistics for Business | Chapter 14: Chi - Square Test s
3
Example 14.01: Case of Chi – Square Testing for Goodness of Fit
PROBLEM
In a biology laborat ory t he m ating of t w o red -eyed fruit flies yielded = 576 offspring, am ong
which were red-eyed, were brow n-eyed, w ere scarlet -eyed, and w ere w hit e-eyed. 338 102 112 24
Use t hese dat a t o test , wit h = 0.05, the hypot hesis that t he rat io among t he offspring would be
9: 3: 3: 1, respect ively.
SOLUTION
= 4,  = k 1 = 4 1 = 3
Let be the event t hat off-springs are red-eyed.
(
)
(
)
be the event t hat off-springs are brow n-eyed.
(
)
be the event t hat off-springs are scarlet -eyed.
(
)
be the event t hat off-springs are whit e-eyed.
: The four off-springs are equally preferred; t hat is, t he probabilit ies of choosing any of the off-
springs are equal 9: 3: 3: 1
: Not all four off-spr ings are equally preferred; t hat is, the probabilities of choosing any of t he
off -spr ings are not equal 9: 3: 3: 1
9
:
3
:
3
:
1
=
9
16
:
3
16
:
3
:
1
16
=
=
576
×
9
16
=
324
=
=
576
×
3
16
=
108
=
=
576
×
3
16
=
108
=
=
576
×
1
=
36
TABLE: Observed Count s (wit h t he expected counts shown in parentheses)
Red-eyed Brow n-eyed Scarlet -eyed Whit e-eyed
(
)
(
)
(
)
(
)
338
102
112
24
(
324
)
(
108
)
(
108
)
(
36
)
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Statistics for Business | Chapter 14: Chi - Square Test s
4
TABLE: Com puting the Value of the Chi-Square St at ist ic

(
)
(
)
/
Red-eyed
(
)
338 324 14 196 0.60
Brow n-eyed
(
)
102 108 -6 36 0.33
Scarlet -eyed
(
)
112 108 4 16 0.15
Whit e-eyed
(
)
24 36 -12 144 4.00
Tot al 5.09
The t est statist ic value: The critical value for
=
0
.
:

=
(
)
=
5
.

=
,
.

=
7
.
815
Thus, at 0.05 level of signif icance, we cannot reject
because

<

(5.086 < 7.815)
that means the rat io among t he offspring would be 9:3:3:1.
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Statistics for Business | Chapter 14: Chi - Square Test s
5
PART II
A CHI – SQUARE TEST FOR INDEPENDENCE
CHI-SQUARE TESTING PROCESS
STEP 01: Deter mine the nu ll and alt ernat ive hypotheses
: The two classificat ion var iables are independent of each ot her
: The tw o classificat ion var iables ar e not independent
STEP 02: Deter mine the observed counts and the expected counts
(
= 
)
of data
points in different cells.
STEP 03: Compute the test stat istic value and the critical value
The test stat ist ic value (based on the difference between the observed and
the expect ed):

= 


/



Hint : Establishing a table
The crit ical value (based on the level of significance
(
)
):

=
(,
[(  ) ( )])
STEP 04: Compare the test st atistic value wit h the crit ical value and make a decision.
Based on the level of significance,
+ We can reject t he null hypothesis
if

>

+ We cannot reject t he null hypothesis
if

<

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Statistics for Business | Chapter 14: Chi - Square Test s
6
Example 14.02: Case of Chi – Square Testing for Independence
PROBLEM
A m arket ing firm w ant s t o test t he dependence bet w een t he regions of Vietnam (Nort hern, Centre,
Southern) and t he habit of spending money (<50%, 50 -80% and >80% income). They conducted a
survey t o 2,000 people in Vietnam :
Regions
Northern Cent er Southern
Habit of
Spending
<50% incom e 203 290 155
50-80% income 266 226 215
>80% incom e 209 154 282
Conduct the test t hat t he habits are independent t o region, using a level of signif icance of 5%.
SOLUTION
H
: The regions of Vietnam and the habit of spending money are independent of each other.
H
: The regions of Viet nam and t he habit of spending money are not independent.
Table: Cont ingency Table of t he regions of Viet nam versus the habit of spending money – Observed
Counts (with the expected count s shown in parent heses).
Regions
Tot al
Northern
Cent er
Southern
(row)
Habit of
Spending
< 50%
Incom e
203
290
155
648
(219.67)
(217.08)
(211.25)
50 - 80%
Incom e
266
226
215
707
(239.67)
(236.85)
(230.48)
> 80%
Incom e
209
154
282
645
(218.66)
(216.08)
(210.27)
Tot al
(column)
678
670
652
2,000
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Statistics for Business | Chapter 14: Chi - Square Test s
7
Table: Com puting of Value of the Chi – Square Stat istic
Habit of
Spending
Regions
O

E

O

E

O

E

O

E

/
E

< 50%
Incom e
Northern
203
219.67
-
16.67
277.89
1.27
Cent er
290
217.08
72.92
5,317.33
24.49
Southern
155
211.25
-
56.25
3,164.06
14.98
50 - 80%
Incom e
Northern
266
239.67
26.33
693.27
2.89
Cent er
226
236.85
-
10.85
117.72
0.50
Southern
215
230.48
-
15.48
239.63
1.04
> 80%
Incom e
Northern
209
218.66
-
9.66
93.32
0.43
Cent er
154
216.08
-
62.08
3,853.93
17.84
Southern
282
210.27
71.73
5,145.19
24.47
Tot al
(column)
2,000
2,000
87.90
The chi – square test stat istic value for independence is
X
= O

E

/ E



= 87.90
Thus t he t est stat istic value is too large
(
X
= 87.90
)
, w e can strongly reject at all level of H
significance. It means t hat based on the Chi Square t esting for independence, w e have enough
evidence to prove that the regions of Vietnam and the habit of spending m oney are independent of
each ot her.
| 1/7

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International University IU
STATISTICS FOR BUSINESS [IUBA] CHAPTER 14 CHI - SQUARE TESTING
CHI – SQUARE TESTING PROCESS STEP 01:
Det er mine t he nu ll and alt ernat ive hypo t heses STEP 02:
Det er mine t he expect ed coun t s and obser ved count s of dat a point s in dif fer ent cells. STEP 03:
Com put e t he t est st at ist ic value (based o n t he dif ference bet w een t he
obser ved and t he expect ed ; Hint : Est ab lishin g a t able) and t he cr it ical value
(based on t he level of signif icance and chi – squar e dist r ibut ion). STEP 04:
Com pare t he t est st at ist ic value w it h t he cr it ical value and m ake a decision. sts e T re a u q i - S h : C 4 r 1 te ap h C ss | e sin u r B s fo istic tat S
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International University IU PART I
A CHI – SQUARE TEST FOR GOODNESS OF FIT
CHI-SQUARE TESTING PROCESS STEP 01:
Det er mine t he nu ll and alt ernat ive hypo t heses
: The probabilities of occurrence of events , ,…, are given by
t he specif ied pr obabilit ies ,,…,
: The probabilities of the  events not the  stated in the null hypot hesis STEP 02:
Det er mine t he observed count s and t he expect ed count s (  = ) of data point s in dif ferent cells. STEP 03:
Com put e t he t est st at ist ic value and t he crit ical value
The t est st at ist ic value (based o n t he dif fer ence bet w een t he obser ved and t he expect ed): stse (  T   − )   =  reau  q
Hint : Est ablishing a t able i - S h : C
The cr it ical value (based on t he level of significance ( 4 )): r 1   te
 = , ap h C STEP 04:
Com pare t he t est st at ist ic value w it h t he cr it ical value and m ake a decision. ss | e
Based on t he level of signif icance, sin u
+ W e can reject t he null hypot hesis   >  r B  if   s fo
+ W e cannot reject t he null hypot hesis   
 if  <  istic tat S
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International University IU
Example 14.01: Case of Chi – Square Testing for Goodness of Fit PROBLEM
In a biology laborat ory t he m at ing of t w o red -eyed fruit flies yielded  = 576 offspring, among
w hich
338 w ere red-eyed, 102 w ere brow n-eyed, 112 w ere scarlet -eyed, and 24 w ere w hit e-eyed.
Use t hese dat a t o t est , w it h  = 0.05, the hypot hesis t hat the rat io among the offspring w ould be
9: 3: 3: 1, respect ively. SOLUTION
 = 4,  = k − 1 = 4 − 1 = 3 Let
( ) be the event that off-springs are red-eyed.
( ) be the event that off-springs are brown-eyed.
( ) be the event that off-springs are scarlet-eyed.
( ) be the event that off-springs are white-eyed.
: The four off-springs are equally preferred; that is, the probabilities of choosing any of the off- springs are equal 9: 3: 3: 1 
: Not all four off-springs are equally preferred; t hat is, the probabilities of choosing any of the
off -spr ings are not equal 9: 3: 3: 1 sts e T 9 3 3 1 re a 9: 3: 3: 1 = : : : u 16 16 16 16 q i - S 9 3 h  =  = 576 × = 324  = 108 16  =  = 576 × 16 : C 4  3 1  =  = 576 × = 108  =  = 576 × = 36 r 1 16 16 te ap h C
TABLE: Observed Count s (w it h t he expect ed count s show n in parent heses) ss | e Red-eyed Brow n-eyed Scarlet -eyed Whit e-eyed sin ( ) ( ) ( ) ( ) u 338 102 112 24 r B ( 324) ( 108) ( 108) ( 36) s fo istic tat S
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TABLE: Com put ing t he Value of t he Chi-Square St at ist ic     −  (  − )
( − ) /  Red-eyed ( ) 338 324 14 196 0.60 Brow n-eyed (  ) 102 108 -6 36 0.33 Scarlet -eyed ( ) 112 108 4 16 0.15 Whit e-eyed ( ) 24 36 -12 144 4.00 Tot al 5.09 The t est st at ist ic value:
The crit ical value f or  = 0.05 :    
 =  ( − )   = 5.09
 = ,. = 7.815  
Thus, at 0.05 level of signif icance, w e cannot reject   
 because  <  (5.086 < 7.815)
t hat means t he rat io am ong t he of fspring w ould be 9:3:3:1. sts e T re a u q i - S h : C 4 r 1 te ap h C ss | e sin u r B s fo istic tat S
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International University IU PART II
A CHI – SQUARE TEST FOR INDEPENDENCE
CHI-SQUARE TESTING PROCESS STEP 01:
Det er mine t he nu ll and alt ernat ive hypo t heses
: The two classification variables are independent of each other
: The two classification variables are not independent STEP 02:
Det er mine t he observed count s and t he expect ed count s (  = ) of data point s in dif ferent cells. STEP 03:
Com put e t he t est st at ist ic value and t he crit ical value
The t est st at ist ic value (based o n t he dif fer ence bet w een t he obser ved and t he expect ed):    =
   − /  sts   e T re
Hint : Est ablishing a t able a u q
The cr it ical value (based on t he level of significance ( ) ): i - S h  =  : C 
( ,[( ) () ]) 4 r 1 STEP 04:
Com pare t he t est st at ist ic value w it h t he cr it ical value and m ake a decision. te ap h
Based on t he level of signif icance, C ss |
+ W e can reject t he null hypot hesis   >  e  if   sin u
+ W e cannot reject t he null hypot hesis   
 if  <  r B s fo istic tat S
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Example 14.02: Case of Chi – Square Testing for Independence PROBLEM
A m arket ing firm w ant s t o t est t he dependence bet w een t he regions of Viet nam (Nort hern, Cent re,
Sout hern) and t he habit of spending m oney (<50%, 50 -80% and >80% incom e). They conduct ed a
survey t o 2,000 people in Viet nam : Regions Nort her n Cent er Sout hern <50% incom e 203 290 155 Habit of 50-80% income 266 226 215 Spending >80% incom e 209 154 282
Conduct t he t est t hat t he habit s are independent t o region, using a level of signif icance of 5%. SOLUTION
H: The regions of Vietnam and the habit of spending money are independent of each other.
H: The regions of Vietnam and the habit of spending money are not independent.
Table: Cont ingency Table of t he regions of Viet nam versus t he habit of spending m oney – Observed
Count s (w it h t he expect ed count s show n in parent heses). sts e T Regions Tot al re a u Nort her n Cent er Sout hern (row ) q i - S < 50% 203 290 155 648 h : C 4 Incom e (219.67) (217.08) (211.25) r 1 te 50 - 80% 266 226 215 707 ap Habit of h Spending C Incom e (239.67) (236.85) (230.48) ss | e > 80% 209 154 282 645 sin u Incom e (218.66) (216.08) (210.27) r B s fo Tot al (colum n) 678 670 652 2,000 istic tat S
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Table: Com put ing of Value of t he Chi – Square St at ist ic Habit of Regions O E O − E O Spending  − E
O− E/ E Nort her n 203 219.67 -16.67 277.89 1.27 < 50% Cent er 290 217.08 72.92 5,317.33 24.49 Incom e Sout hern 155 211.25 -56.25 3,164.06 14.98 Nort her n 266 239.67 26.33 693.27 2.89 50 - 80% Cent er 226 236.85 -10.85 117.72 0.50 Incom e Sout hern 215 230.48 -15.48 239.63 1.04 Nort her n 209 218.66 -9.66 93.32 0.43 > 80% Cent er 154 216.08 -62.08 3,853.93 17.84 Incom e Sout hern 282 210.27 71.73 5,145.19 24.47 Tot al (colum n) 2,000 2,000 87.90 sts e
The chi – square t est st at ist ic value for independence is T re a   u q X 
 =  O − E/ E = 87.90 i - S   h : C  4
Thus t he t est st at ist ic value is t oo large ( X = 87.90), we can strongly reject H at all level of  r 1
significance. It m eans t hat based on t he Chi – Square t est ing for independence, w e have enough te
evidence t o prove t hat t he regions of Viet nam and t he habit of spen ding m oney are independent of ap h each ot her. C ss | e sin u r B s fo istic tat S
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