Department of Electrical Engineering
University of Arkansas
ELEG 3124 SYSTEMS AND SIGNALS
Ch. 5 Laplace Transform
Dr. Jingxian Wu
wuj@uark.edu
2
OUTLINE
Introduction
Laplace Transform
Properties of Laplace Transform
Inverse Laplace Transform
Applications of Laplace Transform
3
INTRODUCTION
Why Laplace transform?
Frequency domain analysis with Fourier transform is extremely
useful for the studies of signals and LTI system.
Convolution in time domain Multiplication in frequency
domain.
Problem: many signals do not have Fourier transform
0),()exp()( = atuattx
)()( ttutx =
Laplace transform can solve this problem
It exists for most common signals.
Follow similar property to Fourier transform
It doesn’t have any physical meaning; just a mathematical tool
to facilitate analysis.
Fourier transform gives us the frequency domain
representation of signal.
4
OUTLINE
Introduction
Laplace Transform
Properties of Laplace Transform
Inverse Lapalace Transform
Applications of Fourier Transform
5
LAPLACE TRANSFORM: BILATERAL LAPLACE TRANSFORM
Bilateral Laplace transform (two-sided Laplace transform)
,)exp()()(
+
= dtsttxsX
B
is a complex variable
s is often called the complex frequency
Notations:
: a function of time t x(t) is called the time domain signal
a function of s is called the s-domain signal
S-domain is also called as the complex frequency domain
js +=
)()( sXtx
B
js +=
)]([)( txLsX
B
=
:)(sX
B
)(sX
B
Time domain v.s. S-domain
LAPLACE TRANSFORM
Time domain v.s. s-domain
: a function of time t x(t) is called the time domain signal
a function of s is called the s-domain signal
S-domain is also called the complex frequency domain
By converting the time domain signal into the s-domain, we can
usually greatly simplify the analysis of the LTI system.
S-domain system analysis:
1. Convert the time domain signals to the s-domain with the
Laplace transform
2. Perform system analysis in the s-domain
3. Convert the s-domain results back to the time-domain
6
)(tx
:)(sX
B
)(sX
B
7
Example
Find the Bilateral Laplace transform of
)()exp()( tuattx =
Region of Convergence (ROC)
The range of s that the Laplace transform of a signal converges.
The Laplace transform always contains two components
The mathematical expression of Laplace transform
ROC.
LAPLACE TRANSFORM: BILATERAL LAPLACE TRANSFORM
8
Example
Find the Laplace transform of
)()exp()( tuattx =
LAPLACE TRANSFORM: BILATERAL LAPLACE TRANSFORM
9
Example
Find the Laplace transform of
)()exp(4)()2exp(3)( tuttuttx +=
LAPLACE TRANSFORM: BILATERAL LAPLACE TRANSFORM
10
LAPLACE TRANSFORM: UNILATERAL LAPLACE TRANSFORM
Unilateral Laplace transform (one-sided Laplace transform)
+
=
0
)exp()()( dtsttxsX
:The value of x(t) at t = 0 is considered.
Useful when we dealing with causal signals or causal systems.
Causal signal: x(t) = 0, t < 0.
Causal system: h(t) = 0, t < 0.
We are going to simply call unilateral Laplace transform as
Laplace transform.
0
+
=
0
)exp()()( dtsttxsX
11
Example: find the unilateral Laplace transform of the
following signals.
1.
Atx =)(
2.
)()( ttx
=
LAPLACE TRANSFORM: UNILATERAL LAPLACE TRANSFORM
12
Example
3.
)2exp()( tjtx =
4.
)2sin()( ttx =
5.
)2cos()( ttx =
LAPLACE TRANSFORM: UNILATERAL LAPLACE TRANSFORM
LAPLACE TRANSFORM: UNILATERAL LAPLACE TRANSFORM
13
14
OUTLINE
Introduction
Laplace Transform
Properties of Laplace Transform
Inverse Lapalace Transform
Applications of Fourier Transform
15
PROPERTIES: LINEARITY
Linearity
If
Then
The ROC is the intersection between the two original signals
)()(
11
sXtx
)()(
22
sXtx
)()()()(
2121
sbXsaXtbxtax ++
Example
Find the Laplace transfrom of
)()exp( tubtBA +
16
PROPERTIES: TIME SHIFTING
Time shifting
If and
Then
The ROC remain unchanged
)()( sXtx
)exp()()()(
000
stsXttuttx
0
0
t
17
PROPERTIES: SHIFTING IN THE
s
DOMAIN
Shifting in the s domain
If
Then
)()exp()()(
00
ssXtstxty =
Example
Find the Laplace transform of
)()cos()exp()(
0
tutatAtx
=
)Re(s
)()( sXtx
)Re()Re(
0
ss +
18
PROPERTIES: TIME SCALING
Time scaling
If
Then
)()( sXtx
1
}Re{
as
a
s
X
a
atx
1
)(
1
}Re{
s
Example
Find the Laplace transform of
)()( atutx =
19
PROPERTIES: DIFFERENTIATION IN TIME DOMAIN
Differentiation in time domain
If
Then
)()( sGtg
)0()(
)(
gssG
dt
tdg
Example
Find the Laplace transform of
),(sin)(
2
tuttg =
)0()0()0()(
)(
)1()2(1
nnnn
n
n
gsggssGs
dt
tgd
0)0( =
g
)0(')0()(
)(
2
2
2
gsgsGs
dt
tgd
20
PROPERTIES: DIFFERENTIATION IN TIME DOMAIN
Example
Use Laplace transform to solve the differential equation
,0)(2)('3)('' =++ tytyty
3)0( =
y
1)0(
'
=
y

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Department of Electrical Engineering University of Arkansas
ELEG 3124 SYSTEMS AND SIGNALS
Ch. 5 Laplace Transform Dr. Jingxian Wu wuj@uark.edu 2 OUTLINEIntroductionLaplace Transform
Properties of Laplace Transform
Inverse Laplace Transform
Applications of Laplace Transform 3 INTRODUCTION
Why Laplace transform?
– Frequency domain analysis with Fourier transform is extremely
useful for the studies of signals and LTI system.
• Convolution in time domain ➔ Multiplication in frequency domain.
– Problem: many signals do not have Fourier transform
x(t) = exp(at)u(t), a  0 x(t) = ( tu t)
– Laplace transform can solve this problem
• It exists for most common signals.
• Follow similar property to Fourier transform
• It doesn’t have any physical meaning; just a mathematical tool to facilitate analysis.
– Fourier transform gives us the frequency domain representation of signal. 4 OUTLINEIntroductionLaplace Transform
Properties of Laplace Transform
Inverse Lapalace Transform
Applications of Fourier Transform 5
LAPLACE TRANSFORM: BILATERAL LAPLACE TRANSFORM
Bilateral Laplace transform (two-sided Laplace transform) X (s) =
x(t) exp(−st)dt, s =  +  j B +− – s =  +  j is a complex variable
s is often called the complex frequency – Notations: X (s) = [ L x(t)] B
x(t)  X (s) B
Time domain v.s. S-domain
x(t) : a function of time t → x(t) is called the time domain signal
X (s) : a function of s → X (s) B is called the s-domain signal B
– S-domain is also called as the complex frequency domain 6 LAPLACE TRANSFORM
Time domain v.s. s-domain
x(t): a function of time t → x(t) is called the time domain signal
X (s) : a function of s → X (s) is called the s-domain signal B B
• S-domain is also called the complex frequency domain
– By converting the time domain signal into the s-domain, we can
usually greatly simplify the analysis of the LTI system. – S-domain system analysis:
• 1. Convert the time domain signals to the s-domain with the Laplace transform
• 2. Perform system analysis in the s-domain
• 3. Convert the s-domain results back to the time-domain 7
LAPLACE TRANSFORM: BILATERAL LAPLACE TRANSFORMExample
– Find the Bilateral Laplace transform of
x(t) = exp(−at)u(t)
Region of Convergence (ROC)
– The range of s that the Laplace transform of a signal converges.
– The Laplace transform always contains two components
• The mathematical expression of Laplace transform • ROC. 8
LAPLACE TRANSFORM: BILATERAL LAPLACE TRANSFORMExample
– Find the Laplace transform of x(t) = −exp(−at)u( t − ) 9
LAPLACE TRANSFORM: BILATERAL LAPLACE TRANSFORMExample
– Find the Laplace transform of x(t) = 3exp( 2
t)u(t) + 4exp(t)u( t − ) 10
LAPLACE TRANSFORM: UNILATERAL LAPLACE TRANSFORM
Unilateral Laplace transform (one-sided Laplace transform)
X (s) = + x(t()ex e p( x −st)dt +−0 – −
0 :The value of x(t) at t = 0 is considered.
– Useful when we dealing with causal signals or causal systems.
• Causal signal: x(t) = 0, t < 0.
• Causal system: h(t) = 0, t < 0.
– We are going to simply call unilateral Laplace transform as Laplace transform. 11
LAPLACE TRANSFORM: UNILATERAL LAPLACE TRANSFORM
Example: find the unilateral Laplace transform of the following signals. – 1. x t ( ) = A
– 2. x(t) =  (t) 12
LAPLACE TRANSFORM: UNILATERAL LAPLACE TRANSFORMExample – 3. (
x t) = exp( j2t)
– 4. x(t) = cos(2t) – 5.
x(t) = sin( 2t) 13
LAPLACE TRANSFORM: UNILATERAL LAPLACE TRANSFORM 14 OUTLINEIntroductionLaplace Transform
Properties of Laplace Transform
Inverse Lapalace Transform
Applications of Fourier Transform 15 PROPERTIES: LINEARITYLinearity – 
x (t)  X (s) If x (t) X (s) 1 1 2 2 – Then
ax (t) + bx (t)  aX (s) + bX (s) 1 2 1 2
The ROC is the intersection between the two original signals • Example
– Find the Laplace transfrom of A + B exp( bt − )u(t) 16
PROPERTIES: TIME SHIFTINGTime shifting – If x (t)  X (s and ) t  0 0 – Then (
x t t )u(t t )  X (s) exp( st − ) 0 0 0 The ROC remain unchanged 17
PROPERTIES: SHIFTING IN THE s DOMAIN
Shifting in the s domain Re(s)   –  If x(t) X (s)
– Then y(t) = (
x t) exp(s t)  X (s s )
Re(s)   + Re(s ) 0 0 0 • Example
– Find the Laplace transform of (
x t) = Aexp( at
− )cos( t)u(t) 0 18
PROPERTIES: TIME SCALINGTime scalings   If
x(t)  X (s) Re{ } 1 – Then 1  s x(at)  X   Re{ } s   a 1 aa  • Example
– Find the Laplace transform of x(t) = u(at) 19
PROPERTIES: DIFFERENTIATION IN TIME DOMAIN
Differentiation in time domain – If
g(t)  G(s) – Then
dg(t)  sG(s) g(0− − ) dt 2 d g(t) 2
s G(s) − sg(0−) − g'(0−) 2 dt n
d g(t)  nsG(s) n 1− − s g(0−) (n−2) −− sg (0− ) (n− ) 1 − g (0− ) n dtExample – 2 −
Find the Laplace transform of g(t) = sin t  u(t), g(0 ) = 0 20
PROPERTIES: DIFFERENTIATION IN TIME DOMAINExample
– Use Laplace transform to solve the differential equation ' −
y''(t) + 3y'(t) + 2y(t) = , 0 0 ( − y ) = 3 y (0 ) = 1