Trắc nghiệm Mạng máy tính - Mạng máy tính | Trường Đại học Khoa học Tự nhiên, Đại học Quốc gia Thành phố Hồ Chí Minh
1.How manny layers does the TCP/IP model have?
=> 4
2. How manny layers does the OSI model have?
=>7
3.From the bottom, what is the fourth layer of the OSI model?
=> Transport
4.from the bottom, what is the fist layer of the TCP/NC model?
=> Network Access
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Môn: Mạng máy tính (CSC)
Trường: Trường Đại học Khoa học tự nhiên, Đại học Quốc gia Thành phố Hồ Chí Minh
Thông tin:
Tác giả:
Preview text:
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CHAPTER 1 – REVIEW CHAPTER 1
- How manny layers does the TCP/IP model have?
=> 4
- How manny layers does the OSI model have?
=>7
- From the bottom, what is the fourth layer of the OSI model?
=> Transport
- from the bottom, what is the fist layer of the TCP/NC model?
=> Network Access
- In the OSI model, can the Network layer interact directly with the Data Link layer? (e.g, sending data, getting data)
=> No
- which organization owns this logo?
=> Internet Engineering Task Force
- wWhat is the maximum size of a TCP/IP packet in default?
=>512 Bytes
- What is the information of 1, 2, 3, and 4?
=> 1: TCP header; 2: IP header; 3: Frame header; 4: Frame trailer
- What does this sentence describe?
"It is the overall effective transmission rate, taking into account things like transmission overhead, protocol inefficiencies, and perhaps even competing for traffic."
=> throughput
- What does this sentence describe?
"It is the amount of usable data delivered to the receiving application."
=> Goodput
- About the Propagation delay, when the interface sends a packet on a 2000 km cable with a propagation speed of 200 m/µsec (= 200 km/ms, about 2/3 the speed of light), the first bit will not arrive at the destination until X ms later.
What is the value of X?
=>10
- The basic of "Forwarding table" is the pair of:
=> <destination, next_hop>
- What is the type of this network?
=> Loop
- What does "802.11" mention?
=> Wi-Fi standard
- Which company produced the connection card, which has the MAC address of "18-60-24-85- 0F-22"?
=> Hewlett Packard
- What is the IP network address in this figure?
=> 192.168.10.0
- The IP layer handles the packet as:
=> Connectionless
- The transport layer handles the packet as:
=> Connection-Oriented
CHAPTER 1 – Q2 – IP FOEWARDING
- Finish the R1's forwarding table. (slide 50) Please answer with format:
<network_address>/<Prefix Mask>:<Interface>,<network_address>/<Prefix Mask>:<Interface>,...,<network_address>/<Prefix Mask>:<Interface
Note:
- The entries need to be in the order of the network name (Net1, Net2,...,Net5)
- Do not add SPACE to the answer.
Ex: 192.168.1.0/24:F1,192.168.2.0/24:F2,192.168.3.0/24:F3
=>
192.168.2.0/24:F1,172.16.1.0/24:F1,10.0.1.0/24:F1,10.0.2.0/24:F1
- Finish the R2's forwarding table.
=> 192.168.1.0/24:F1,172.16.1.0/24:F1,10.0.1.0/24:F1,10.0.2.0/24:F1
- Finish the R3's forwarding table
=> 192.168.1.0/24:F1,192.168.2.0/24:F1,10.0.1.0/24:F1,10.0.2.0/24:F1
- Finish the R4's forwarding table
=> 192.168.1.0/24:F1,192.168.2.0/24:F1,172.16.1.0/24:F1,10.0.2.0/24:F1
- Finish the R5's forwarding table
=> 192.168.1.0/24:F2,192.168.2.0/24:F3,172.16.1.0/24:F4,10.0.1.0/24:F1
CHAPTER 4 – Q1 – FRAGMENTATION
- PC sends to Server an IPv4 packet with the size of 1500 Bytes. The MTU of the links is configured as the Figure.
What is the size of the original payload?
=>
1480
- At R1, how many fragments will be sent (to R2)?
=> 3
- At R2, how many fragments will be sent (to R3)?
=> 5
- At R3, how many fragments will be sent (to R4)?
=> 7
- At R1, what is the value of the FragOffset of the fragments? Note:
- Enter the answer with the format of ....,...,...,....
- Please do not add any space to the answer.
- Ex: 0,500,1000
=> 0,91,182 ; 0,728,1456
- At R2, what is the value of the FragOffset of the fragments? Note:
- Enter the answer with the format of ....,...,...,....
- Please do not add any space to the answer.
- Ex: 0,500,1000
=> 0,60,91,151,182 0,480,728,1208,1456
- At R2, what is the value of the FragOffset of the fragments? Note:
- Enter the answer with the format of ....,...,...,....
- Please do not add any space to the answer.
- Ex: 0,500,1000
=> 0,60,91,151,182 0,480,728,1208,1456
- At R3, what is the value of the FragOffset of the fragments? Note:
- Enter the answer with the format of ....,...,...,....
- Please do not add any space to the answer.
- Ex: 0,500,1000
=> 0,35,60,91,126,151,182 0,280,480,728,1008,1208,1456
- At R4, what is the value of the FragOffset of the fragments?
=> 0,35,60,91,126,151,182 0,280,480,728,1008,1208,1456
- At R1, what is the value of the MoreFragment of the fragments?
=> 1,1,0
- At R2, what is the value of the MoreFragment of the fragments?
=> 1,1,1,1,0
- At R3, what is the value of the MoreFragment of the fragments?
=> 1,1,1,1,1,1,0
- At R4, what is the value of the MoreFragment of the fragments?
=> 1,1,1,1,1,1,0
IP SUBNET
Give you the IP network 172.16.0.0/16.
Let dividing it into 32 subnets having the same number of hosts.
- How many useable IP addresses (can assign to the device) in each subnet?
=> 2046
- What is the 15th subnet?
=> 172.16.112.0/21
- What is the broadcast address of subnet 20?
=> 172.16.159.255
- What is the first useable IP address of subnet 25?
=> 172.16.192.1
IP SUBNETING 2
We have the network address of 172.16.0.0/16.
Divide the network address into several subnets and each subnet reserves to 1000 hosts.
- How many subnets are there?
=> 64
- What is the 50th subnet?
=> 172.16.196.0/22
- What is the first configurable IP address of the subnet 15?
=> 172.16.56.1
- What is the broadcast address of the subnet 7?
=> 172.16.27.255
ADVANCED IP SUBNETING
We have the network topology below.
The request for the number of host of each network following:
- Subnet 1: 2000 hosts
- Subnet 2: 100 hosts
- Subnet 3: 500 hosts
- Subnet 4: 1000 hosts
- Subnet 5: 2 hosts
- Subnet 6: 2 hosts
Use the VLSM method to divide the IP network of 172.16.0.0 to achieve the above request.
1.
Enter the IP network address of the Subnet 1 as the answer
=> 172.16.0.0/21
- Enter the IP network address of the Subnet 2 as the answer:
=> 172.16.14.0/25
- Enter the IP network address of the Subnet 3 as the answer:
=> 172.16.12.0/23
- Enter the IP network address of the Subnet 4 as the answer:
=> 172.16.8.0/22
- Enter the IP network address of the Subnet 5 as the answer:
=> 172.16.14.128/30
- Enter the IP network address of the Subnet 6 as the answer:
=> 172.16.14.132/30
- Enter the IP broadcast address of the Subnet 1 as the answer:
=> 172.16.7.255
- Enter the IP broadcast address of the Subnet 2 as the answer:
=> 172.16.14.127
- Enter the IP broadcast address of the Subnet 3 as the answer:
=> 172.16.13.255
CHAPTER 4 – REVIEW CHAPTER 4B
- What is the IPv4 loopback address?
=> 127.0.0.0
- A non-router host with multiple non-loopback network interfaces is often called:
=> Multihomed
- What protocol does the host use to look up the LAN address (e.g., MAC address)?
=> ARP
- When a client wants to get a new IP address from the DHCP server, what is the last packet that the client sends to the DHCP server?
=> DHCPREQUEST
- There are ten (10) tandemly arranged routers among the Source (called host A) and the Sink (called host B). If the host A uses the "tracert" command to print the route to host B, what is the largest value that TTL can reach?
=> 11
- As an administrator, you have to divide the network address 172.16.0.0/16 to 5 subnets with the requirement:
- Subnet 1 needs 100 hosts
- Subnet 2 needs 500 hosts
- Subnet 3 needs 50 hosts
- Subnet 4 needs 2 hosts
- Subnet 5 needs 2 hosts
Add the text to the answer with the format of "<Subnet 1>+<Subnet 2>+<Subnet 3>+<Subnet 4>+<Subnet 5>" (No space allowed)
=> 172.16.2.0/25+172.16.0.0/23+172.16.2.128/26+172.16.2.192/30+172.16.2.196/30
- Continue the Q.6, what is the 25-th IP address of the 3-rd subnet?
=> 172.16.2.153
CHAPTER 5 – Q1 EUI – 64
1. "72-61-39-D2-99-BE" is the:
=> Modification address (Locally use) 2. "18-60-24-85-0F-22" is the:
=> Burned-in-address (Universal use)
- What is the type of the MAC address of "01-00-5E-40-07-07"?
=> Multicast
- What is the type of the MAC address of "FF-FF-FF-FF-FF-FF"?
=> Broadcast
- Convert "00-1A-7D-DA-71-15" to Ipv6 Interface Identifier using EUI-64 method.
=> 02-1A-7D-FF-FE-DA-71-15
CHAPTER 5 – REVIEWING CHAPTER 5
- How many bit for IPv6?
=> 128
- How many bytes for the default IPv6 header?
=> 40
- Does IPv6 have a header checksum?
=> NO
- Shorten the IPv6 following below: 1843:0F01:0000:0022:0000:0000:0000:00FA
=> 1843:F01:0:22::FA
- Convert the MAC address to IPv6 host prefix (64 bits) using EUI-64. FC:99:47:75:CE:E0
=> FE99:47FF:FE75:CEE0
- [Multiple choices] What parameters will be used in the secure hashing method to specify the IPv6 interface identification?
=> Net_Iface
=> IPv6 address prefix
=> Host-specific secret key
- The IPv6 network prefix will be contained in message:
=> Router Advertisement
- How IPv6 host can ask for the MAC address of the specific IPv6 address?
=> Neighbor Solicitation
- Can IPv6 subnet with the network prefix larger than 64 bit?
=> YES
- Which host address assignment option to ask for all IPv6 information from IPv6 DHCP?
=> Option