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International University – HCMC 
Econometrics with Financial Application 
Vietnam National University – HCMC 
International University – HCMC   
Econometrics with Financial Application  International University  HOMEWORK CHAPTER 6  SCHOOL OF BUSINESS      Question 1: 
You obtain the following sample autocorrelations and partial autocorrelations for a sample of 
100 observations from actual data:  Lag  1  2  3  4  5  6  7  8  ACF  0.420  0.104  0.032  -0.206  -0.138  0.042  -0.018  0.074  PACF  0.632  0.381  0.268  0.199  0.205  0.101  0.096  0.082 
Can you identify the most appropriate time series process for this data? 
Using the Ljung-Box Q* test to determine whether the first three autocorrelation coefficients 
taken together are jointly significantly different from zero.  Answer:      Single test:      𝐻 :𝜏 = 0 
Econometrics with Financial Application_S2_2022-23_G01 Dr  Using confidential interval    Nguyen Phuong Anh 
0.42 > 0.196 => Reject 𝐻 :𝜏  = 0   
-0.196 < 0.104 < 0.196 => Not reject 𝐻 :𝜏  = 0   
-0.196 < 0.032 < 0.196 => Not reject 𝐻 :𝜏  = 0 
-0.206 < 0.196 => Reject 𝐻 : 𝜏  = 0  Seq.  Full name  Student ID  Contribution 
-0.196 < -0.138 < 0.196 => Not reject 𝐻 : 𝜏 = 0  1  Trương Phúc An  BABAIU20526  100% 
-0.196 < 0.042 < 0.196 => Not reject 𝐻 :𝜏  = 0 
-0.196 < -0.018 < 0.196 => Not reject 𝐻 : 𝜏 = 0  2  Nguyễn Hoàng Bảo Hân  BAFNIU19077  100% 
-0.196 < 0.074 < 0.196 => Not reject 𝐻 :𝜏  = 0 
Since only 𝜏 ≠ 0 𝑎𝑛𝑑 𝜏 
≠ 0 => 𝐴𝐶𝐹 = 0 𝑎𝑓𝑡𝑒𝑟 4 𝑙𝑎𝑔𝑠  3  Hồ Thế Phong  BAFNIU19141  100%    |𝜏 | = 0.643      |𝜏 | = 0.381    |𝜏 | = 0.268  Page 1 of 5   
This shows that PACF is slowly decaying to 0   
International University – HCMC 
Econometrics with Financial Application  Page 2 of 5  0.68   
→ 𝐴𝑅𝑀𝐴 𝑖𝑠 𝑖𝑛𝑣𝑒𝑟𝑡𝑖𝑏𝑙𝑒 
• MA is more suitable. Since ACF = 0 after 4 lags, we use MA (4).  Page 3 of 5  Ljung-box formula:      𝐻 : 𝜏 = 𝜏 = 𝜏  = 0 (𝑚 = 3) 
International University – HCMC 
Econometrics with Financial Application 
• Test statistic Q* compared with CV from 2 (3)  • Question 3:   CV=7.815  •
Considering the following 3 models that a researcher suggests might be a reasonable model of 
 𝑄∗ = 𝑇 × (𝑇 + 2) ∑    stock market prices: 
• 𝑄∗ = 19.4 > 𝐶𝑉 => 𝑄∗ 𝑏𝑒𝑙𝑜𝑛𝑔𝑠 𝑡𝑜 𝑡ℎ𝑒 𝑟𝑒𝑗𝑒𝑐𝑡𝑖𝑜𝑛 𝑟𝑒𝑔𝑖𝑜𝑛  i) 𝑦 = 0.7𝑢  + 𝑢 
• 𝑅𝑒𝑗𝑒𝑐𝑡 𝐻 : 𝜏 = 𝜏 = 𝜏  = 0  j) 𝑦 = 0.4𝑦  + 𝑢 
• The first three autocorrelation coefficients taken together are jointly  k) 𝑦 = 2𝑦  + 𝑢 
significantly different from zero Question 2: 
a) What classes of model are these examples of? 
b) Are these models stationary? 
Considering the following ARMA process: 
c) Calculate the autocorrelation coefficients for the process (i) and (j) up to lag 2.    𝑦 = 2.1 + 1.5𝑦  + 0.68𝑢  + 𝑢  Answer: 
Determine whether the MA part of the process is invertible. 
a) i is MA. While j and k is AR. 
Determine whether the AR part of the process is stationary. 
b) Since MA is always stationary => i is stationary    𝑗) 𝑦 = 0.4𝑦  + 𝑢  Answer: 
↔ 𝑦 = 0.4𝐿𝑦 + 𝑢 (1 − 
ARMA (1, 1) model is stationary when AR part is stationary  0.4𝐿)𝑦 = 𝑢    𝑦 = 2.1 + 1.5𝑦  (𝐴𝑅(1)) 
𝛷(𝑍) = 0 ↔ 1 − 0.4𝑍 = 0    𝑦 − 1.5𝑦  = 2.1 + 0.68𝑢  + 𝑢  1 
𝑦 − 1.5𝐿𝑦 = 2.1 + 0.68𝐿𝑢 + 𝑢  → 𝑍 = 
 > 1 → 𝑜𝑢𝑡𝑠𝑖𝑑𝑒 𝑢𝑛𝑖𝑡 𝑐𝑖𝑟𝑐𝑙𝑒 → 𝑆𝑡𝑎𝑡𝑖𝑜𝑛𝑎𝑟𝑦 
(1 − 1.5𝐿)𝑦 = 2.1 + (0.68𝐿 + 1)𝑢  0.4    𝑘) 𝑦 = 2𝑦  + 𝑢 
(1 − 1.5𝐿)𝑦 = 𝛷(𝐿), (0.68𝐿 + 1)𝑢 = 𝜃(𝐿) 
↔ 𝑦 = 2𝐿𝑦 + 𝑢 (1 − 
𝛷(𝑍) = 0 ↔ 1 − 1.5𝑍 = 0  2𝐿)𝑦 = 𝑢  1  → 𝑍 = 
 < 1 → 𝑖𝑛𝑠𝑖𝑑𝑒 𝑢𝑛𝑖𝑡 𝑐𝑖𝑟𝑐𝑙𝑒 → 𝐴𝑅 𝑝𝑎𝑟𝑡 𝑖𝑠 𝑛𝑜𝑡 𝑠𝑡𝑎𝑡𝑖𝑜𝑛𝑎𝑟𝑦 
𝛷(𝑍) = 0 ↔ 1 − 2𝑍 = 0  1.5 
𝜃(𝐿) = 0 ↔ 0.68𝑍 + 1 = 0 
→ 𝑍 = < 1 → 𝑖𝑛𝑠𝑖𝑑𝑒 𝑢𝑛𝑖𝑡 𝑐𝑖𝑟𝑐𝑙𝑒 → 𝑁𝑜𝑡 𝑠𝑡𝑎𝑡𝑖𝑜𝑛𝑎𝑟𝑦  1  → |𝑍| = 
 > 1 → 𝑜𝑢𝑡𝑠𝑖𝑑𝑒 𝑢𝑛𝑖𝑡 𝑐𝑖𝑟𝑐𝑙𝑒 → 𝑀𝐴 𝑝𝑎𝑟𝑡 𝑖𝑠 𝑖𝑛𝑣𝑒𝑟𝑡𝑖𝑏𝑙𝑒   
International University – HCMC 
Econometrics with Financial Application 
c) 𝐴𝑅(1): 𝑦 = 0.4𝑦  + 𝑢 + 0 × 𝑦      Yule-Walker system      𝜏  = 𝛷 + 𝜏 × 0 = 0.4    i) 𝑦 = 0.7𝑢  + 𝑢 𝑀𝐴(1)    𝛾   
𝜏 = , 𝛾 = 𝑉𝑎𝑟(𝑦 )    𝛾   
(𝑖) → 𝐸(𝑦 ) = 𝐸(0.7𝑢  + 𝑢 )  Page 4 of 5      Page 5 of 5 
= 0.7𝐸(𝑢 ) + 𝐸(𝑢 )   
(𝑖) → 𝑉𝑎𝑟(𝑦 ) = 𝐶𝑜𝑣(𝑦 , 𝑦 ) 
= 𝐸[(𝑦 − 0)(𝑦 − 0)]    = 𝐸[(0.7𝑢  + 𝑢 )(0.7𝑢  + 𝑢 )]    = 𝐸[(0.7 𝑢  + 𝑢  + 1.4𝑢  𝑢 )]  = (0.7 + 1)𝑉𝑎𝑟𝑢  = (0.7 + 1)𝜎 𝑢   
(𝑖) → 𝛾 = 𝐶𝑜𝑣(𝑦 , 𝑦  )    = 𝐸[(𝑦 − 0)(𝑦  − 0)]    = 𝐸[(0.7𝑢  + 𝑢 )(0.7𝑢  + 𝑢  )]  = 𝐸[(0.7 𝑢  𝑢  + 𝑢 𝑢  + 1.4𝑢  )]  = 1.4𝜎 𝑢  .  .  Then 𝜏 = =   
Similarly, 𝜏 = = 𝐶𝑜𝑣 𝑦 ,𝑦  = =0  𝑉𝑎𝑟 𝑦𝑡 
For MA (1), ACF = 0 after q lags.