Bài tập tổ hợp và xác suất – Diệp Tuân

Tài liệu gồm 214 trang, được biên soạn bởi thầy giáo Diệp Tuân, phân dạng và tuyển chọn các bài tập trắc nghiệm chuyên đề tổ hợp và xác suất trong chương trình Đại số và Giải tích 11 chương 2.

Môn:

Toán 11 3.3 K tài liệu

Thông tin:
214 trang 1 năm trước

Bình luận

Vui lòng đăng nhập hoặc đăng ký để gửi bình luận.

Bài tập tổ hợp và xác suất – Diệp Tuân

Tài liệu gồm 214 trang, được biên soạn bởi thầy giáo Diệp Tuân, phân dạng và tuyển chọn các bài tập trắc nghiệm chuyên đề tổ hợp và xác suất trong chương trình Đại số và Giải tích 11 chương 2.

86 43 lượt tải Tải xuống
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Tổ HợpXác Suất
1
Lớp Toán Thầy-Diệp Tn Tel: 0935.660.880
A. THUYT
I. Quy tc cng
1. Định nghĩa: Xét mt công vic
H
.
Gi s
H
k
phương án
12
, ,...,
k
H H H
thc hin công vic
H
.
Nếu có
cách thc hiện phương án
1
H
,
2
m
cách thc hiện phương án
2
H
,..,
k
m
cách thc hiện phương án
k
H
và mi cách thc hiện phương án
i
H
không trùng vi
bt kì cách thc hiện phương án
j
H
(
; , 1,2,...,i j i j k
)
thì có
12
...
k
m m m
cách thc hin công vic
H
.
2. Công thc quy tc cng
Nếu các tp
12
, ,...,
n
A A A
đôi một ri nhau.
Khi đó:
1 2 1 2
... ...
nn
A A A A A A
3. Ví d minh ha.
Ví dụ 1. Giả sử bạn muốn mua một áo mi cỡ
hoặc cỡ
40.
Áo cỡ
5
màu khác nhau, áo
cỡ
40
4
màu khác nhau. Hỏi có bao nhiêu sự lựa chọn (về màu áo và cỡ áo)?
A.
9.
B.
5.
C.
4.
D.
1.
Lời giải.
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
dụ 2. Một người
4
cái quần khác nhau,
6
cái áo khác nhau,
3
chiếc cà vạt khác nhau. Để chọn
một cái quần hoặc một cái áo hoặc một cái cà vạt thì số cách chọn khác nhau là:
A.
13.
B.
72.
C.
12.
D.
30.
Lời giải.
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
Theo quy tắc cộng có:
m
1
+
m
2
+
m
x
+...+
m
k
(
)
cách
m
k
cách chọn
m
x
cách chọn
m
2
cách chọn
Hành động k
Hành động x
Hành động 2
m
1
cách chọn
Hành động 1
Hoàn thành
Công việc
§BI 1. HAI QUY TC ĐẾM
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Tổ Hợp và Xác Suất
2
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
dụ 3. Trên bàn
8
cây bút chì khác nhau,
6
cây bút bi khác nhau
10
cuốn tập khác nhau.
Một học sinh muốn chọn một đồ vật duy nhất hoặc một cây bút chì hoặc một cây bút bi hoặc một
cuốn tập thì số cách chọn khác nhau là:
A.
480.
B.
24.
C.
48.
D.
60.
Lời giải.
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
dụ 4. Trong một trường THPT, khối
11
280
học sinh nam
325
học sinh nữ. Nhà trường
cần chọn một học sinh ở khối
11
đi dự dạ hội của học sinh thành phố. Hỏi nhà trường có bao nhiêu
cách chọn?
A.
45.
B.
280.
C.
325.
D.
605.
Lời giải.
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
dụ 5. Một trường THPT được cử một học sinh đi dự trại toàn quốc. Nhà trường quyết định
chọn một học sinh tiên tiến lớp
11A
hoặc lớp
12 .B
Hỏi nhà trường bao nhiêu cách chọn, nếu
biết rằng lớp
11A
31
học sinh tiên tiến và lớp
12B
22
học sinh tiên tiến?
A.
31.
B.
9.
C.
53.
D.
682.
Lời giải.
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
Ví dụ 6. Trong một hộp chứa sáu quả cầu trắng được đánh số từ
1
đến
6
ba quả cầu đen được
đánh số
7, 8, 9.
Có bao nhiêu cách chọn một trong các quả cầu ấy?
A.
27.
B.
9.
C.
6.
D.
3.
Lời giải.
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Tổ HợpXác Suất
3
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
Ví dụ 7. Giả sử từ tỉnh
A
đến tỉnh
B
thể đi bằng các phương tiện: ô tô, tàu hỏa, tàu thủy hoặc
máy bay. Mỗi ngày có
10
chuyến ô tô,
5
chuyến tàu hỏa,
3
chuyến tàu thủy và
2
chuyến máy bay.
Hỏi có bao nhiêu cách đi từ tỉnh
A
đến tỉnh
B
?
A.
20.
B.
300.
C.
18.
D.
15.
Lời giải.
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
Ví dụ 8. Trong một cuộc thi tìm hiểu về đất nước Việt Nam, ban tổ chức công bố danh sách các đề
tài bao gồm:
8
đề tài về lịch sử,
7
đề tài về thiên nhiên,
10
đề tài về con người
6
đề tài về văn
hóa. Mỗi thí sinh được quyền chọn một đề tài. Hỏi mỗi thí sinh có bao nhiêu sự lựa chn đề tài?
A.
20.
B.
3360.
C.
31.
D.
30.
Lời giải.
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
II. Quy tc nhân.
1. Định nghĩa:
Gi s mt công vic
H
bao gm
k
công đoạn
12
, ,...,
k
H H H
.
Công đoạn
1
H
cách thc hin,
công đoạn
2
H
2
m
cách thc hiện,…,
công đoạn
k
H
k
m
cách thc hin.
Khi đó công việc H có th thc hin theo
12
. ...
k
m m m
cách.
2. Công thc quy tc nhân
Nếu các tp
12
, ,...,
n
A A A
đôi một rời nhau. Khi đó:
1 2 1 2
... . .....
nn
A A A A A A
.
m
k
cách
m
1
cách
Hành động k
Công việc
Hoàn thành
Hành động 1
Theo quy tắc nhân ta có:
m
1
x
m
k
(
)
cách
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Tổ Hợp và Xác Suất
4
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
dụ 9. Có 3 kiểu mặt đồng hồ đeo tay (vuông, tròn, elip) và 4 kiểu dây (kim loại, da, vải và nhựa).
Hỏi có bao nhiêu cách chọn một chiếc đồng hồ gồm một mặt và một dây?
A. 4. B. 7. C. 12. D. 16.
Lời giải.
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
dụ 10. Một người 4 cái quần, 6 cái áo, 3 chiếc vạt. Để chọn mỗi thứ một món thì bao
nhiều cách chọn bộ
''
quần-áo-cà vạt
''
khác nhau?
A.
13.
B.
72.
C.
12.
D.
30.
Lời giải.
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
dụ 11. Một thùng trong đó có
12
hộp đựng bút màu đỏ,
18
hộp đựng bút màu xanh. Số cách khác
nhau để chọn được đồng thời một hộp màu đỏ, một hộp màu xanh là?
A.
13.
B.
12.
C.
18.
D.
216.
Lời giải.
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
Ví dụ 12. Trên bàn
8
cây bút chì khác nhau,
6
cây bút bi khác nhau
10
cuốn tập khác nhau.
Số cách khác nhau để chọn được đồng thời một cây bút chì, một cây bút bi và một cuốn tập.
A.
24.
B.
48.
C.
480.
D.
60.
Lời giải.
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Tổ HợpXác Suất
5
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
dụ 13. Một hoa
5
hoa hồng trắng,
6
hoa hồng đỏ
7
hoa hồng vàng. Hỏi mấy cách
chọn lấy ba bông hoa có đủ cả ba màu.
A.
240.
B.
210.
C.
18.
D.
120.
Lời giải.
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
dụ 14. Một người vào cửa hàng ăn, người đó chọn thực đơn gồm một món ăn trong năm món,
một loại quả tráng miệng trong năm loại quả tráng miệng một nước uống trong ba loại nước
uống. Có bao nhiêu cách chọn thực đơn.
A.
25.
B.
75.
C.
100.
D.
15.
Lời giải.
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
Ví dụ 15. Trong một trường THPT, khối
11
280
học sinh nam
325
học sinh nữ. Nhà trường
cần chọn hai học sinh trong đó có một nam và một nữ đi dự trại hè của học sinh thành phố. Hỏi nhà
trường có bao nhiêu cách chọn?
A.
910000.
B.
91000.
C.
910.
D.
625.
Lời giải.
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
dụ 16. Một đội học sinh giỏi của trường THPT, gồm
5
học sinh khối
12,
4
học sinh khối
11,
3
học
sinh khối
10.
Số cách chọn ba học sinh trong đó mỗi khối có một em?
A.
12.
B.
220.
C.
60.
D.
3.
Lời giải.
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Tổ Hợp và Xác Suất
6
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
Ví dụ 17.
10
cặp vợ chồng đi dự tiệc. Tổng số cách chọn một người đàn ông một người đàn
bà trong bữa tiệc phát biểu ý kiến sao cho hai người đó không là vợ chồng?
A.
100.
B.
91.
C.
10.
D.
90.
Lời giải.
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
Ví d 18. An muốn qua nhà Bình để cùng Bình đến chơi nhà Cường. Từ nhà An đến nhà Bình có
4
con đường đi, từ nhà nh tới nhà Cường
6
con đường đi. Hỏi An bao nhiêu cách chọn đường
đi đến nhà Cường?
A.
6.
B.
4.
C.
10.
D.
24.
Lời giải.
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
dụ 19. Các thành phố A, B, C, D được nối với nhau bởi các con đường như hình vẽ. Hỏi bao
nhiêu cách đi từ A đến D mà qua B và C chỉ một lần?
A. 9. B. 10. C. 18. D. 24.
Lời giải.
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
dụ 20. Các thành phố A, B, C, D được nối với nhau bởi các con đường như hình vẽ. Hỏi bao
nhiêu cách đi từ A đến D rồi quay lại A?
A. 1296. B. 784. C. 576. D. 324.
Lời giải.
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Tổ HợpXác Suất
7
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
Ví dụ 21. Trong một tuần bạn A dự định mỗi ngày đi thăm một người bạn trong 12 người bạn của
mình. Hỏi bạn A thể lập được bao nhiêu kế hoạch đi thăm bạn của mình (thăm một bạn không
quá một lần)?
A.
3991680.
B.
12!.
C.
35831808.
D.
7!.
Lời giải.
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
dụ 22. Nhãn mỗi chiếc ghế trong hội trường gồm hai phần: phần đầu là một chữ cái (trong bảng
24
chữ cái tiếng Việt), phần thứ hai một số nguyên dương nhỏ hơn
26.
Hỏi nhiều nhất bao
nhiêu chiếc ghế được ghi nhãn khác nhau?
A.
624.
B.
48.
C.
600.
D.
26.
Lời giải.
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
Ví dụ 23. Biển số xe máy của tỉnh
A
(nếu không kể số tỉnh)
6
tự, trong đó tự vị trí
đầu tiên là một chữ cái (trong bảng
26
cái tiếng Anh), tự ở vị trí thứ hai là một chữ số thuộc tập
1;2;3;...;9
mỗi kí tự ở bốn vị trí tiếp theo một chữ số thuộc tập
0;1;2;3;...;9
. Hỏi nếu chỉ dùng
một mã số tỉnh thì tỉnh
A
có thể làm được nhiều nhất bao nhiêu biển số xe máy khác nhau?
A.
2340000.
B.
234000.
C.
75.
D.
2600000.
Lời giải.
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Tổ Hợp và Xác Suất
8
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
dụ 24. Một hình lập phương có cạnh
4cm
. Người ta sơn đỏ mặt ngoài của hình lập phương rồi
cắt hình lập phương bằng các mặt phẳng song song với các mặt của hình lập phương thành
64
hình lập phương nhỏ có cạnh
1cm
. Có bao nhiêu hình lập phương có đúng một mặt được sơn đỏ?
A.
16
. B.
72
. C.
24
. D.
.
Lời giải
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
III. ng dng quy tc cng quy tc nn vào gii toán.
1. Phương pháp đếm bài toán t hp da vào quy tc cng.
Để đếm s cách thc hin mt công vic
H
nào đó theo quy tắc cng ta cn phân tích xem
công việc H đó có bao nhiêu phương án thực hin?
Mỗi phương án có bao nhiêu cách chọn?
2. Phương pháp đếm bài toán t hp da vào quy tc nhân.
Để đếm s cách thc hin công vic H theo quy tc nhân, ta cn phân tích công việc H được
chia làm các giai đoạn
12
, ,...,
n
H H H
và đếm s cách thc hin mỗi giai đoạn
i
H
(
1,2,...,in
).
IV. Ta thường gp ba bài toán đếm cơ bản
Bài toán 1: Đếm s phương án liên quan đến s t nhiên
Khi lp mt s t nhiên
1
...
n
x a a
ta cần lưu ý:
0,1,2,...,9
i
a
1
0a
.
x
là s chn
n
a
là s chn
x
là s l
n
a
là s l
x
chia hết cho
12
3 ...
n
a a a
chia hết cho
3
x
chia hết cho
4
1nn
aa
chia hết cho
4
x
chia hết cho
5 0,5
n
a
x
chia hết cho
x
là s chn và chia hết cho
3
x
chia hết cho
21
8
n n n
a a a

chia hết cho
8
x
chia hết cho
12
9 ...
n
a a a
chia hết cho
9
.
x
chia hết cho
11
tng các ch s hàng l tr đi tổng các ch s hàng chn mt s
chia hết cho
11
.
x
chia hết cho
25
hai ch s tn cùng là
00,25,50,75
.
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Tổ HợpXác Suất
9
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
Bài toán 2: Đếm s phương án liên quan đến kiến thc thc tế
Bài toán 3: Đếm s phương án liên quan đến hình hc
B-PHÂN DNG VÀ VÍ D MINH HA.
1. Phương pháp chung.
Ta thường gặp bài toán đếm s phương án thực hiện hành động
H
tha mãn tính cht
T
. Để gii
bài toán này ta thường gii theo hai cách sau
ch 1: Đếm trc tiếp
Nhận xét đề bài để phân chia các trường hp xảy ra đối vi bài toán cần đếm.
Đếm s phương án thực hin trong mỗi trường hợp đó
Kết qu ca bài toán là tng s phương án đếm trong cách trường hp trên
Chú ý:
Để đếm s phương án thực hin trong mỗi trường hp ta phải chia hành động trong mi
trường hợp đó thành phương án hành động nh liên tiếp nhau
s dng quy tc nhân, các khái nim hoán ví, chnh hp t hợp để đếm s phương án
thc hiện các hành các hành động nh đó.
ch 2: Đếm gián tiếp (đếm phn bù)
Trong trường hợp hành động
H
chia nhiều trường hợp thì ta đi đếm phn của bài toán như
sau:
Đếm s phương án thực hiện hành động
H
(không cần quan tâm đến có tha tính cht
T
hay
không) ta được
a
phương án.
Đếm s phương án thực hiện hành động
H
không tha tính cht
T
ta được
b
phương án.
Khi đó số phương án thỏa yêu cu bài toán là:
ab
.
2. Một số bài toán thường gặp.
2.1. Bài toán chọn đồ vật.
Bài tp 1. Bn cn mua một áo sơ mi cỡ 30 hoc 32. Áo c 30 có 3 màu khác nhau, áo c 32
4 màu khác nhau. Hi bn có bao nhiêu cách la chn ?
Li gii.
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
Bài tp 2. 10 cun sách Toán khác nhau, 11 cuốn sách Văn khác nhau và 7 cun sách anh văn
khác nhau. Mt học sinh được chn mt quyn sách trong các quyn sách trên. Hi có bao nhiêu
cách la chn.
Li gii.
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
i tp 3. T thành ph
A
đến thành ph B có 6 con đường, t thành ph B đến thành ph C có
7 con đường. Có bao nhiêu cách đi từ thành ph A đến thành ph C, biết phi đi qua thành phố B.
Li gii.
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Tổ Hợp và Xác Suất
10
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
Bài tp 4. T thành ph A có 10 con đường đi đến thành ph B, t thành ph A có 9 con đường
đi đến thành ph C, t B đến D có 6 con đường, t C đến D có 11 con đường không con đường
nào ni B vi C. Hỏi có bao nhiêu cách đi từ A đến D.
Li gii.
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
2.2. Bài toán xếp ghế, xếp bàn tròn.
1. Phương pháp.
Xếp
n
người vào
n
ghế dài
!n
cách xếp.
Xếp
n
người vào
n
bàn tròn
cách xếp.
2. i tập minh họa
Bài tp 5. Có 3 hc sinh n và 2 hc sinh nam .Ta mun sp xếp vào mt bàn dài có 5 ghế ngi.
Hi có bao nhiêu cách sp xếp để :
1). 3 hc sinh n ngi k nhau
2). 2 hc sinh nam ngi k nhau.
Li gii.
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
Bài tp 6 . Xếp 6 người A, B, C, D, E, F vào mt ghế dài .Hi có bao nhiêu cách sp xếp sao cho:
1). A và F ngi hai đầu ghế
2). A và F ngi cnh nhau
3). A và F không ngi cnh nhau
Li gii
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Tổ HợpXác Suất
11
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
Bài tp 7. Có 3 nam và 3 n cn xếp ngi vào mt hàng ghế. Hi có my cách xếp sao cho :
a) Nam, n ngi xen k ?
b) Nam, n ngi xen k và có một người nam A, một người n B phi ngi k nhau ?
c) Nam, n ngi xen k và có một người nam C, một người n D không đưc ngi k nhau ?
Li gii.
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
Bài tp 8. Mt bàn dài 2 dãy ghế đối din nhau, mi dãy gm 6 ghế. Người ta mun xếp
ch ngi cho 6 học sinh trường A 6 học sinh trường B vào bàn nói trên. Hi bao nhiêu cách
xếp ch ngi trong mỗi trường hp sau :
a) Bt kì 2 hc sinh nào ngi cnh nhau hoặc đối diện nhau thì khác trường nhau.
b) Bt kì 2 hc sinh nào ngồi đối diện nhau thì khác trường nhau.
Li gii.
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Tổ Hợp và Xác Suất
12
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
Bài tp 9.
1). Có bao nhiêu cách xếp
n
người ngi vào mt bàn tròn.
2). Mt hi ngh bàn tròn các phái đoàn 3 người Anh , 5 người Pháp và 7 người M. Hi
bao nhiêu cách xếp ch ngi cho các thành viên sao cho những người cùng quc tch thì ngi
gn nhau.
Li gii.
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
Bài tp 10. bao nhiêu cách xếp
5
cun sách Toán,
6
cun sách
8
cun sách Hóa lên
mt k sách sao cho các cun sách cùng mt môn hc thì xếp cnh nhau, biết các cuốn sách đôi một
khác nhau .
Li gii.
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Tổ HợpXác Suất
13
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
Bài tp 11. bao nhiêu cách xếp 4 người A,B,C,D lên 3 toa tàu, biết mi toa th chứa 4 người.
Li gii.
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
i tp 12. Trong mt giải thi đấu bóng đá 20 đội tham gia vi th thức thi đấu vòng tròn. C
hai đội thì gặp nhau đúng một ln. Hi có tt c bao nhiêu trận đấu xy ra .
Li gii.
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
Bài tp 13. Hội đồng qun tr ca công ty X gm 10 người. Hi bao nhiêu cách bầu ra ba người
vào ba v trí ch tch, phó ch tịch và thư kí, biết kh năng mỗi người là như nhau.
Li gii.
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
2.3. Chn s và sp xếp s
1. Phương pháp.
Gi s cn lp
( )
..... 0x abcd a
Nếu trong tp
A
không có s
0
thì ta không cn xét h s
a
.
Nếu trong tp
A
có s
0
thì ta phi cn xét h s
a
tc là
0a
.
2. i tập minh họa.
Bài toán 1: Không có số 0 trong tập được chọn.
i tp 14. các s
1,2,3,4,5,6,7
lp được bao nhiêu s t nhiên gm 4 ch s khác nhau và là:
1). S chn
2). S l
3). S chia hết cho 5
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Tổ Hợp và Xác Suất
14
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
Li gii.
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
Bài tp 15. Cho tp
1,2,3,4,5,6,7,8A
1). T tp A có th lập được bao nhiêu s gm 8 ch s đôi một khác nhau sao các s này l
không chia hết cho 5.
2). T tp A có th lập được bao nhiêu s gm 8 ch s đôi một khác nhau sao ch s đầu
chn ch s đứng cui l.
Li gii.
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
Bài tp 16. Cho các ch s 1, 2, 3,..., 9. T các s đó có thể lập được bao nhiêu s
a) Có 4 ch s đôi một khác nhau.
b) S chn gm 4 ch s khác nhau và không vượt quá 2011.
Li gii.
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Tổ HợpXác Suất
15
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
Bài tp 17. Cho tp
1,2,3,4,5,6,7,8A
1). Có bao nhiêu tp con ca A cha s 2 mà không cha s 3
2). Tc các ch s thuc tp A, lập được bao nhiêu s t nhiên l gm 5 ch s không bắt đầu
bi 123.
Li gii.
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
Bài tp 18. Có 100000 vé được đánh số t 00000 đến 99999. Hi sgm 5 ch s khác nhau.
Li gii.
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
Bài tp 19. Tính tng các ch s gm 5 ch s đưc lp t các s 1, 2, 3, 4, 5?
Li gii.
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
3. u hỏi trắc nghiệm.
u 1. Số 253125000 có bao nhiêu ước số tự nhiên?
A.
160.
B.
240.
C.
180.
D.
120.
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Tổ Hợp và Xác Suất
16
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
Lời giải.
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
u 2. Từ các chữ số
1;5;6;7
thể lập được bao nhiêu chữ số tự nhiên
4
chữ số (không nhất
thiết phải khác nhau) ?
A.
324.
B.
256.
C.
248.
D.
124.
Lời giải.
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
u 3. Từ các chữ số
1;5;6;7
có thể lập được bao nhiêu chữ số tự nhiên có
4
chữ số khác nhau ?
A.
36.
B.
24.
C.
20.
D.
14.
Lời giải.
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
u 4.Có bao nhiêu số tự nhiên có hai chữ số mà hai chữ số đều chẵn ?
A.
99.
B.
50.
C.
20.
D.
10.
Lời giải.
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
u 5. Từ các chữ số
1;2;3;4;5;6;
có thể lập được bao nhiêu chữ số tự nhiên bé hơn
100
?
A.
36.
B.
62.
C.
54.
D.
42.
Lời giải.
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Tổ HợpXác Suất
17
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
u 6. Từ các chữ số
0;1;2;3;4;5;
có thể lập được bao nhiêu số lẻ gồm
4
chữ số khác nhau ?
A.
154.
B.
145.
C.
144.
D.
155.
Lời giải.
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
u 7. Có bao nhiêu số có
3
chữ số đôi một khác nhau có thể lập được từ các chữ số
0
,
2
,
4
,
6
,
8
?
A.
48
. B.
60
. C.
10
. D.
24
.
Lời giải
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
u 8. Có bao nhiêu số tự nhiên nhỏ hơn
1000
được lập từ các chữ số
0
,
1
,
2
,
3
,
4
?
A.
125
. B.
120
. C.
100
. D.
69
.
Lời giải
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
u 9. Có bao nhiêu s t nhiên có bn ch s?
A.
5040
. B.
4536
. C.
10000
. D.
9000
.
Lời giải
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
u 10. Có bao nhiêu số tự nhiên lẻ có 4 chữ số khác nhau?
A.
2240.
B.
2520.
C.
2016.
D.
256.
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Tổ Hợp và Xác Suất
18
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
Lời giải
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
Bài toán 2: số
0
trong tập được chọn và số được chọn số chẵn hoặc số chia hết cho
2,5.
1. Phương pháp
Do s tận cùng cũng chọn s
0
và ch s đầu tiên có liên quan đến s
( )
00
nên ta chia thành hai
trường hp.
Trường hp 1. Xét s tn cùng bng 0.
Trường hp 2. Xét s tn cùng khác
0
.
S cách chn là tng ca hai trường hợp đó.
2. i tp minh ha.
i tp 20. bao nhiêu ch s chn gm bn ch s đôi một khác nhau được lp t các s
0,1,2,4,5,6,8
.
Li gii.
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Tổ HợpXác Suất
19
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
Bài tp 21. Cho tp
1. T tp A ta có th lập được bao nhiêu s t nhiên l gm 4 ch s đôi một khác nhau
2. T tp A có th lập được bao nhiêu s t nhiên gm 5 ch s và chia hết cho 5.
Li gii.
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
i tp 22. T các s 0,1,2,3,4,5 th lập được bao nhiêu s t mi s 6 ch s khác
nhau và ch s 2 đứng cnh ch s 3?
Li gii.
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
i tp 23. Cho tp hp s :
0,1,2,3,4,5,6A
.Hi có th thành lp bao nhiêu s 4 ch s
khác nhau và chia hết cho 3.
Li gii.
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
0,1,2,3,4,5,6A
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Tổ Hợp và Xác Suất
20
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
Bài tp 24. T các s ca tp
0,1,2,3,4,5,6A
có th lập được bao nhiêu s chn gm 5 ch
s đôi một khác nhau trong đó có hai chữ s l và hai ch s l đứng cnh nhau.
Li gii.
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
i tp 25. T các s
1,2,3,4,5,6
th lập được bao nhiêu s t nhiên ,mi s 6 ch s
đồng thi thỏa điều kin :sáu s ca mi s là khác nhau và trong mi s đó tổng ca 3 ch s đầu
nh hơn tổng ca 3 s sau một đơn vị.
Li gii.
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
i tp 26. T các s
1,2,3
lp được bao nhiu s t nhiên gôm
6
ch s thỏa mãn đồng thi
hai điều kin sau
1). Trong mi s, mi ch s có mặt đúng một ln.
2). Trong mi s, hai ch s giống nhau không đứng cnh nhau.
Li gii.
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Tổ HợpXác Suất
21
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
Bài tp 27. Hi có tt c bao nhiêu s t nhiên chia hết cho
9
mà mi s
2011
ch s trong
đó có ít nhất hai ch s
9
.
Li gii.
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
3. u hi trc nghim.
u 11. Từ các chữ số
0;1;2;3;4;5;
có thể lập được bao nhiêu số chẵn gồm
4
chữ số khác nhau ?
A.
156.
B.
144.
C.
96.
D.
134.
Lời giải.
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Tổ Hợp và Xác Suất
22
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
u 12. Cho tập
0;1;2;3;4;5;6A
từ tập
A
thể lập được bao nhiêu số tự nhiên có
5
chsố và
chia hết cho
2
?
A.
1230
. B.
2880
. C.
1260
. D.
8232
.
Lời giải
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
u 13. Với năm chữ số
1
,
2
,
3
,
5
,
6
thể lập được bao nhiêu số có
5
chữ số đôi một khác nhau
và chia hết cho
5
?
A.
120
. B.
24
. C.
16
. D.
25
.
Lời giải
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
u 14. Với năm chữ số
1
,
2
,
3
,
4
,
7
thể lập được bao nhiêu số
5
chữ số đôi một khác nhau
và chia hết cho
2
?
A.
24
. B.
48
. C.
1250
. D.
120
.
Lời giải
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
u 15. Với năm chữ số
1
,
2
,
3
,
4
,
7
thể lập được bao nhiêu số
5
chữ số đôi một khác nhau
và chia hết cho
2
?
A.
24
. B.
48
. C.
1250
. D.
120
.
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Tổ HợpXác Suất
23
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
Lời giải
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
u 16. Từ các chữ số
0
,
1
,
2
,
3
,
4
,
5
,
6
thể lập được bao nhiêu số tự nhiên chẵn có ba ch
số?
A.
210
. B.
105
. C.
168
. D.
145
.
Lời giải
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
u 17. Cho tập
0;1;2;3;4;5;6A
từ tập
A
thể lập được bao nhiêu số tự nhiên có
5
chsố và
chia hết cho
2
?
A.
8232
. B.
1230
. C.
1260
. D.
2880
.
Lời giải
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
u 18. Cho các chữ số
0
,
1
,
2
,
3
,
4
,
5
. Từ các chữ số đã cho lập được bao nhiêu số tự nhiên chẵn
4
chữ số và các chữ số đôi một bất kỳ khác nhau.
A.
160
. B.
156
. C.
752
. D.
240
.
Lời giải
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Tổ Hợp và Xác Suất
24
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
Câu 19. Tcác chữ số
0
;
1
;
2
;
3
;
5
;
8
thể lập được bao nhiêu số tự nhn l bốn chữ số đôi một
khác nhau phải mặt chữ số
3
.
A.
108
số. B.
228
số. C.
số. D.
144
số.
Lời giải
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
u 20. Từ các chữ số
0
,
1
,
2
,
3
,
4
,
5
,
8
lập được bao nhiêu số ba chữ số đôi một khác nhau,
chia hết cho
2
3
.
A.
số. B.
số. C.
số. D.
48
số.
Lời giải
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
u 21. Có bao nhiêu số tự nhiên chẵn gồm
3
chữ số khác nhau?
A.
500
. B.
328
. C.
360
. D.
405
.
Lời giải
................................................................................................
.................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Tổ HợpXác Suất
25
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
u 22. Có bao nhiêu số tự nhiên có
5
chữ số mà tổng các chữ số trong mỗi số là
3
.
A.
15
. B.
. C.
. D.
19
.
Lời giải
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
u 23. Cho
5
chữ số
1
,
2
,
3
,
4
,
6
. Lập các số tự nhiên
3
chữ số đôi một khác nhau từ
5
chữ
số đã cho. Tính tổng của các số lập được.
A.
12321
. B.
21312
. C.
12312
. D.
21321
.
Lời giải
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
u 24. Có bao nhiêu số tự nhiên chẵn gồm
3
chữ số khác nhau?
A.
500
. B.
328
. C.
360
. D.
405
.
Lời giải
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Tổ Hợp và Xác Suất
26
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
u 25. Có bao nhiêu số 4 chữ số được viết từ các chữ số
1
,
2
,
3
,
4
,
5
,
6
,
7
,
8
,
9
sao cho s
đó chia hết cho
15
?
A.
234
. B.
243
. C.
132
. D.
432
Lời giải
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
u 26. Từ các chữ số
1, 2, 3, 4, 5, 6
thể lập được bao nhiêu số tự nhiên chẵn có sáu chữ số
thỏa mãn điều kiện: sáu chữ số của mỗi số là khác nhau và chữ số hàng nghìn lớn hơn
2
?
A.
720
số. B.
360
số. C.
288
số. D.
240
số.
Lời giải
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
u 27. Từ các chữ số
0
,
2
,
3
,
5
,
6
,
8
thể lập được bao nhiêu số tự nhiên gồm
6
chữ số đôi
một khác nhau trong đó hai chữ số
0
5
không đứng cạnh nhau.
A.
384
. B.
120
. C.
216
. D.
600
.
Lời giải
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
.................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán V-Chỉnh Hợp-Tổ Hợp
27
Lớp Toán Thầy -Diệp Tuân Tel: 0935.660.880
A. THUYT
I. GIAI THA
1. Định nghĩa: Vi mi s t nhiên dương
n
, tích
1.2.3....n
đưc gi là
n
- giai tha và kí hiu
!n
.
Vy
! . 1 . 2 . 3 ...3.2.1n n n n n
.
Ta quy ước
0! 1
.
Ví d 1.
7! 7.6.5.4.3.2.1
.
2. Tính cht:
! ( -1)!n n n
.
! ( 1)( 2)...( 1). !n n n n n k k
II. HOÁN V
1. Định nghĩa: Cho tp
A
gm
n
phn t (
1n
). Khi sp xếp
n
phn t này theo mt th t ta được
mt hoán v các phn t ca tp
A
.
2. Kí hiu s hoán v ca n phn t
! ( 1)( 2)...3.2.1
n
P n n n n
.
3. Các du hiu đặc trưng để giúp ta nhn dng mt hoán v ca n phn t là:
Tt c
n
phn t đều phi có mt.
Mi phn t xut hin mt ln.
Có th t gia các phn t.
4. Ví d minh ha.
d 2. T các ch s ca tp hp
1,2,3,4,5,6A
lập được bao nhiêu s t nhiên gm 6
ch s đôi một khác nhau..
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
III. CHNH HP
1. Định nghĩa: Cho tp
A
gm
n
phn t và s nguyên
k
vi
1 kn
.
Khi ly
k
phn t ca
A
và sp xếp chúng theo mt th t ta được mt chnh hp chp
k
ca
n
phn t ca
A
.
2. Kí hiu.
Kí hiu
k
n
A
là s chnh hp chp
k
ca
n
phn t
!
( )!
k
n
n
A
nk
.
3. Du hiu.
Ta s s dng khái nim chnh hp khi
Cn chn
k
phn t t
n
phn t, mi phn t xut hin mt ln.
k
phn t đã cho được sp xếp th t.
4. Ví d minh ha.
Ví d 3. T các s ca tp
{1,2,3,4,5,6,7}A
lập được bao nhiêu s t nhiên gm
1). Năm chữ s đôi một khác nhau
2). Sáu ch s khác nhau và chia hết cho 5.
3). Năm chữ s đôi một khác nhau, đồng thi hai ch s 2 và 3 luôn đứng cnh nhau
4). By ch s, trong đó chữ s 2 xut hiện đúng ba lần.
§BI 2. HOÁN V - CHNH HP T HP
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán Vị-Chỉnh Hợp-Tổ Hợp
28
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Ví d 4. Có bao nhiêu cách xếp khác nhau cho 6 người ngồi vào 4 chỗ trên một bàn dài?
A.
15.
B.
720.
C.
30.
D.
360.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Ví d 5. Giả sử bảy bông hoa khác nhau ba lọ hoa khác nhau. Hỏi bao nhiêu cách cắm
ba bông hoa vào ba lọ đã cho (mội lọ cắm một bông)?
A.
35.
B.
30240.
C.
210.
D.
21.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Ví d 6. Có bao nhiêu cách cắm 3 bông hoa vào 5 lọ khác nhau (mội lọ cắm không quá một một
bông)?
A.
60.
B.
10.
C.
15.
D.
720.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Ví d 7. Có bao nhiêu cách mắc nối tiếp 4 bóng đèn được chọn từ 6 bóng đèn khác nhau?
A.
15.
B.
360.
C.
24.
D.
17280.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
d 8. Trong mặt phẳng cho một tập hợp gồm 6 điểm phân biệt. bao nhiêu vectơ khác
vectơ
0
có điểm đầu và điểm cuối thuộc tập hợp điểm này?
A.
15.
B.
12.
C.
1440.
D.
30.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán V-Chỉnh Hợp-Tổ Hợp
29
Lớp Toán Thầy -Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
d 9. Trong trận chung kết bóng đá phải phân định thắng thua bằng đá luân lưu 11 mét.
Huấn luyện viên mỗi đội cần trình với trọng tài một danh sách sắp thứ tự 5 cầu thủ trong số 11
cầu thủ để đá luân lưu 5 quả 11 mét. Hãy tính xem huấn luyện viên của mỗi đội có bao nhiêu cách
lập danh sách gồm 5 cầu thủ.
A.
462.
B.
55.
C.
55440.
D.
11!.5!
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
d 10. Giả sử 8 vận động viên tham gia chạy thi. Nếu không kể trường hợp hai vận
động viên về đích cùng lúc thì có bao nhiêu kết quả có thể xảy ra đối với các vị trí nhất, nhì, ba?
A.
336.
B.
56.
C.
24.
D.
120.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
d 11. Trong một ban chấp hành đoàn gồm 7 người, cần chọn ra 3 người vào ban thường
vụ. Nếu cần chọn ban thường vụ gồm ba chức vụ thư, Phó bí thư, Ủy viên thường vụ thì có bao
nhiêu cách chọn?
A.
210.
B.
200.
C.
180.
D.
150.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
d 12. Một cuộc thi 15 người tham dự, giả thiết rằng không hai người nào điểm
bằng nhau. Nếu kết quả của cuộc thi việc chọn ra các giải nhất, nhì, ba thì có bao nhiêu kết quả
có thể?
A.
2730.
B.
2703.
C.
2073.
D.
2370.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Ví d 13. Trong một dạ hội cuối năm một cơ quan, ban tổ chức phát ra 100 vé xổ số đánh số
từ 1 đến 100 cho 100 người. Xổ số 4 giải: 1 giải nhất, 1 giải nhì, 1 giải ba, 1 giải tư. Kết quả
việc công bố ai trúng giải nhất, giải nhì, giải ba, giải tư. Hỏi có bao nhiêu kết quả có thể?
A.
94109040.
B.
94109400.
C.
94104900.
D.
94410900.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Ví d 14. Trong một dạ hội cuối năm một cơ quan, ban tổ chức phát ra 100 vé xổ số đánh số
từ 1 đến 100 cho 100 người. Xổ số 4 giải: 1 giải nhất, 1 giải nhì, 1 giải ba, 1 giải tư. Kết quả
việc công bố ai trúng giải nhất, giải nhì, giải ba, giải tư. Hỏi bao nhiêu kết quả thể nếu biết
rằng người giữ vé số 47 được giải nhất?
A.
944109.
B.
941409.
C.
941094.
D.
941049.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Ví d 15. Trong một dạ hội cuối năm một cơ quan, ban tổ chức phát ra 100 vé xổ số đánh số
từ 1 đến 100 cho 100 người. Xổ số 4 giải: 1 giải nhất, 1 giải nhì, 1 giải ba, 1 giải tư. Kết quả
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán Vị-Chỉnh Hợp-Tổ Hợp
30
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
việc công bố ai trúng giải nhất, giải nhì, giải ba, giải tư. Hỏi bao nhiêu kết quả thể nếu biết
rằng người giữ vé số 47 trúng một trong bốn giải?
A.
3766437.
B.
3764637.
C.
3764367.
D.
3764376.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Ví d 16. Có bao nhiêu số tự nhiên gồm
5
chữ số khác nhau được lập từ các số
1, 2, , 9?
A.
15120.
B.
C.
D.
126.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
d 17. Cho tập
0,1, 2, , 9 .A 
Số các số tự nhiên có 5 chữ số đôi một khác nhau lấy ra
từ tp
A
là?
A.
30420.
B.
27162.
C.
27216.
D.
30240.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Ví d 18. bao nhiêu số tự nhiên gồm 7 chữ số khác nhau đôi một, trong đó chsố 2 đứng
liền giữa hai chữ số 1 và 3?
A.
249.
B.
7440.
C.
3204.
D.
2942.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
IV. T HP
1. Định nghĩa: Cho tp
A
n
phn t và s nguyên
k
vi
1 kn
. Mi tp con ca
A
k
phn
t đưc gi là mt t hp chp
k
ca
n
phn t ca A.
2. Kí hiu.
Kí hiu
k
n
C
là s t hp chp
k
ca n phn t
!
( )! !
k
n
n
C
n k k
.
3. Du hiu:
Ta s dng khái nim t hp khi
Cn chn
k
phn t t
n
phn t, mi phn t xut hin mt ln
Không quan tâm đến th t
k
phn t đã chọn.
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán V-Chỉnh Hợp-Tổ Hợp
31
Lớp Toán Thầy -Diệp Tuân Tel: 0935.660.880
4. Ví d.
Ví d 19. Trong mt lp hc có 20 hc sinh n và 15 hc sinh nam. Hi giáo viên ch nhim có
bao nhiêu cách chn:
1). Ba hc sinh làm ban các s lp
2). Ba hc sinh làm ba nhim v lớp trưởng, lớp phó và bí thư
3). Ba hc sinh làm ban cán s trong đó có ít nhất mt hc sinh n
4). Bn hc sinh làm t trưởng ca 4 t sao cho trong 4 học sinh được chn có c nam và n.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
d 20. Một lớp học
40
học sinh gồm
25
nam
15
nữ. Chọn
3
học sinh để tham gia vệ
sinh công cộng toàn trường, hỏi có bao nhiêu cách chọn như trên?
A.
9880.
B.
59280.
C.
2300.
D.
455.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
d 21. Một tổ
10
người gồm
6
nam
4
nữ. Cần lập một đoàn đại biểu gồm
5
người,
hỏi có bao nhiêu cách lập?
A.
25.
B.
252.
C.
50.
D.
455.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
d 22. Trong một ban chấp hành đoàn gồm
7
người, cần chọn
3
người trong ban thường
vụ. Nếu không sự phân biệt về chức vụ của
3
người trong ban thường vụ thì có bao nhiêu các
chọn?
A.
25.
B.
42.
C.
50.
D.
35.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
d 23. Một cuộc thi
15
người tham dự, giả thiết rằng không hai người nào điểm
bằng nhau. Nếu kết quả cuộc thi việc chọn ra
4
người điểm cao nhất thì bao nhiêu kết
quả có thể xảy ra?
A.
1635.
B.
1536.
C.
1356.
D.
1365.
Li gii.
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán Vị-Chỉnh Hợp-Tổ Hợp
32
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
d 24. Một hộp đựng 5 viên bi màu xanh, 7 viên bi màu vàng. bao nhiêu cách lấy ra 6
viên bi bất kỳ?
A.
665280.
B.
924.
C.
7.
D.
942.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Ví d 25. Có bao nhiêu cách lấy hai con bài từ cỗ bài tú lơ khơ gồm
con?
A.
104.
B.
450.
C.
1326.
D.
2652.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
d 26.
15
đội bóng đá thi đấu theo thể thức vòng tròn tính điểm. Hỏi cần phải tổ chức
bao nhiêu trận đấu?
A.
100.
B.
105.
C.
210.
D.
200.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Ví d 27. Có bao nhiêu cách cắm 3 bông hoa giống nhau vào 5 lọ khác nhau (mỗi lọ cắm không
quá một bông)?
A.
10.
B.
30.
C.
6.
D.
60.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
d 28. Một lớp
15
học sinh nam
20
học sinh nữ. bao nhiêu cách chọn
5
bạn học
sinh sao cho trong đó có đúng
3
học sinh nữ?
A.
110790.
B.
119700.
C.
117900.
D.
110970.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
d 29. bao nhiêu số tự nhiên
4
chữ số khác nhau khác
0
trong mỗi số luôn
luôn có mặt hai chữ số chẵn và hai chữ số lẻ?
A.
11
45
4! .CC
B.
22
35
3! .CC
C.
22
45
4! .CC
D.
22
45
3! .CC
Li gii.
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán V-Chỉnh Hợp-Tổ Hợp
33
Lớp Toán Thầy -Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Ví d 30. Một túi đựng
6
bi trắng,
5
bi xanh. Lấy ra
4
viên bi từ túi đó. Hỏi có bao nhiêu cách
lấy mà
4
viên bi lấy ra có đủ hai màu.
A.
300.
B.
310.
C.
320.
D.
330.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
d 31. Một nhóm học sinh
6
bạn nam
5
bạn nữ. Hỏi có bao nhiêu cách chn ra
5
học
sinh trong đó có cả nam và nữ?
A.
455.
B.
7.
C.
456.
D.
462.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
d 32. Để chào mừng kỉ niệm ngày thành lập Đoàn TNCS Hồ Chí Minh, nhà trường tổ chức
cho học sinh cắm trại. Lớp 10A
19
học sinh nam
16
học sinh nữ. Giáo viên cần chn
5
học
sinh để trang trí trại. Hỏi có bao nhiêu cách chọn
5
học sinh sao cho có ít nhất
1
học sinh nữ? Biết
rằng học sinh nào trong lớp cũng có khă năng trang trí trại.
A.
5
19
.C
B.
55
35 19
.CC
C.
55
35 16
.CC
D.
5
16
.C
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán Vị-Chỉnh Hợp-Tổ Hợp
34
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
B PHÂN DNG VÀ VÍ D MINH HA.
Dạng 1. Giải phương trình–Bất phương trình–Hệ Phương trình.
1. Phương pháp:
Da vào công thc t hp, chnh hp hoán v để chuyển phương trình, bất phương trình, hệ
phương trình tổ hp v phương trình, bất phương trình, hệ phương trình đại s.
Nh kiểm tra điều kin.
2. Bài tp minh ha.
Bài tp 1. Tìm s nguyên dương
n
sao cho:
1).
21
8.
nn
AA
2).
65
10 .
nn
AA
3).
4
1 4 2
. 15 .
n n n
P A P
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 2. Giải các phương trình sau
1).
22
12
34
xx
C xP A

2).
22
72 6( 2 )
x x x x
P A A P
3).
5 6 7
5 2 14
x x x
C C C

4).
4 3 2
1 1 2
5
0
4
x x x
C C A
5).
1 2 3 2
6. 6. 9 14
x x x
C C C x x
6).
3 4 4
1
24 23
x
x x x
A C A

7).
2 2 2 2
1 2 3
2 3 4 130
x x x x
C C C C
8).
2
3 1 2 3
2 4 2 4
x x x
xx
CC

9).
2 2 2 3 3 3
2 100
xx
x x x x x x
C C C C C C

Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán V-Chỉnh Hợp-Tổ Hợp
35
Lớp Toán Thầy -Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 3.
1). Cho
3
1140
n
n
C
. Tính
65
4
nn
n
AA
A
A
2). Tính
2 2 2
23
1 1 1
...
n
B
A A A
, biết
2
1
11
2 ... 45
n
nn
n
n
nn
CC
Cn
CC
3). Tính
43
1
3
1!
nn
AA
M
n
, biết
2 2 2 2
1 2 3 4
2 2 149
n n n n
C C C C
.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán Vị-Chỉnh Hợp-Tổ Hợp
36
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 4. Giải các phương trình sau
1).
12
22
5
2
nn
n n n
C C A


2).
2
1
2
3
10
n
n
C
n
C
3).
31
11
14 1
n
nn
A C n

4).
4
4
143
2 ! 4
n
n
A
nP
5).
4
34
1
24
23
n
n
nn
A
AC
6).
3
23
! . . 720
n n n
n n n
n C C C
7).
2 2 3
2
16
10
2
x x x
A A C
x
8).
2
5
3
60
( )!
k
x
x
P
A
xk
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán V-Chỉnh Hợp-Tổ Hợp
37
Lớp Toán Thầy -Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 5. Giải các phương trình sau
a).
1
1
1
6
xx
x
PP
P
. b).
2
23
. . 8P x P x
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 6. Giải các phương trình sau
a).
22
2
3 42 0
xx
AA
. b).
10 9 8
9
x x x
A A A
.
c).
4
34
1
24
23
x
x
xx
A
AC
. d).
32
5 2 15
xx
A A x
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán Vị-Chỉnh Hợp-Tổ Hợp
38
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 7. Giải các phương trình sau
a).
21
14 14 14
2
x x x
C C C


. b).
23
11
2 7 1
x
xx
C C x

.
c).
1 2 3 2
6 6 9 14
x x x
C C C x x
. d).
1 2 1
14
1 1 7
6
x x x
C C C


.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 8. Giải các phương trình sau
a)
22
72 6 2
x x x x
P A A P
. b)
1
11
7 2 30
x
x x x
A P P


.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán V-Chỉnh Hợp-Tổ Hợp
39
Lớp Toán Thầy -Diệp Tuân Tel: 0935.660.880
Bài tp 9. Giải các phương trình sau
a).
22
2
101
x
xx
AC

. b).
21
. 48
x
xx
AC
.
c).
3 4 2
23
x x x
A C A
. d).
32
14
x
xx
A C x

.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 10. Giải các bất phương trình sau
a).
4
4
15
2 ! 1 !
n
A
nn

. b).
4
2
21
143
0
4
n
nn
A
PP


.
c).
23
2
16
10
2
n
n n n
A A C
n
. d).
22
1
2 3 20 0
nn
CA
.
e).
22
1
2 3 30
nn
CA

. f).
3
1
4
13
1
14.
n
n
n
C
AP
.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán Vị-Chỉnh Hợp-Tổ Hợp
40
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
3. Câu hi trc nghim.
u 1. Tìm tất cả các giá trị
x
thỏa mãn
11
6.
x x x
P P P


A.
2.x
B.
3.x
C.
2;x
3.x
D.
5.x
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán V-Chỉnh Hợp-Tổ Hợp
41
Lớp Toán Thầy -Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 2. Tính tổng
S
của tất cả các giá trị của
x
thỏa mãn
2
23
. . 8.P x P x
A.
4.S 
B.
1.S 
C.
4.S
D.
3.S
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 3. Có bao nhiêu số tự nhiên
x
thỏa mãn
22
2
3 42 0
xx
AA
?
A.
0.
B.
1.
C.
2.
D.
6.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 4. Cho số tự nhiên
x
thỏa mãn
10 9 8
9
x x x
A A A
. Mệnh đề nào sau đây đúng?
A.
x
là số chính phương. B.
x
là số nguyên tố.
C.
x
là số chẵn. D.
x
là số chia hết cho
3.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 5. Có bao nhiêu số tự nhiên
n
thỏa mãn
32
5 2 15
nn
A A n
?
A.
0.
B.
1.
C.
2.
D.
3.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 6. Tìm giá trị
n
thỏa mãn
1 2 3
1 2 1
3.
n n n
C C C

A.
12.n
B.
9.n
C.
16.n
D.
2.n
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán Vị-Chỉnh Hợp-Tổ Hợp
42
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 7. Tính tích
P
của tất cả các giá trị của
x
thỏa mãn
21
14 14 14
2.
x x x
C C C


A.
4.P
B.
32.P
C.
32.P 
D.
12.P
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 8. Tính tổng
S
của tất cả các giá trị của
n
thỏa mãn
1 2 1
14
1 1 7
.
6
n n n
C C C


A.
8.S
B.
11.S
C.
12.S
D.
15.S
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 9. Tìm giá trị
x
thỏa mãn
0 1 2
79.
xx
x x x
C C C

A.
13.x
B.
17.x
C.
16.x
D.
12.x
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán V-Chỉnh Hợp-Tổ Hợp
43
Lớp Toán Thầy -Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 10. Tìm giá trị
n
thỏa mãn
1
43
7 3 .
nn
nn
C C n

A.
15.n
B.
18.n
C.
16.n
D.
12.n
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 11. Tìm giá trị
n
thỏa mãn
1 2 3
7
.
2
n n n
n
C C C
A.
3.n
B.
4.n
C.
6.n
D.
8.n
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 12. Tính tổng
S
của tất cả các giá trị của
x
thỏa
1 2 3 2
6 6 9 14 .
x x x
C C C x x
A.
2.S
B.
7.S
C.
9.S
D.
14.S
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 13. Tìm giá trị
n
thỏa mãn
6 7 8 9 8
2
3 3 2 .
n n n n n
C C C C C
A.
18.n
B.
16.n
C.
15.n
D.
14.n
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán Vị-Chỉnh Hợp-Tổ Hợp
44
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 14. Đẳng thức nào sau đây là sai?
A.
6 7 7
2006 2006 2007
C C C
. . B.
7 2000 6
2007 2006 2006
.C C C
C.
7 2000 1999
2007 2006 2006
.C C C
D.
7 7 2000
2007 2006 2006
.C C C
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 15. Đẳng thức nào sau đây là đúng?
A.
2
1
1 2 3 4 ... .
n
nC
B.
2
1
1 2 3 4 ... .
n
nA
C.
12
1 2 3 4 ... .... .
n
n n n
n C C C
D.
12
1 2 3 4 ... .... .
n
n n n
n A A A
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 16. Tính tích
P
của tất cả các giá trị của
n
thỏa mãn
22
72 6 2 .
n n n n
P A A P
A.
12.P
B.
5.P
C.
10.P
D.
6.P
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 17. Tính tích
P
của tất cả các giá trị của
x
thỏa mãn
1
11
7 2 30 .
x
x x x
A P P


A.
7.P
B.
4.P
C.
28.P
D.
14.P
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán V-Chỉnh Hợp-Tổ Hợp
45
Lớp Toán Thầy -Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 18. Tìm giá trị
n
thỏa mãn
33
86
5.
n
nn
CA

A.
15.n
B.
17.n
C.
6.n
D.
14.n
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 19. Tìm giá trị
x
thỏa mãn
21
. 48.
x
xx
AC
A.
4.x
B.
3.x
C.
7.x
D.
12.x
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 20. Tìm giá trị
n
thỏa mãn
21
1
5.
n
nn
AC

A.
3.n
B.
5.n
C.
4.n
D.
6.n
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 21. Tính tích
P
của tất cả các giá trị của
n
thỏa mãn
22
3 15 5 .
nn
A C n
A.
5.P
B.
6.P
C.
30.P
D.
360.P
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán Vị-Chỉnh Hợp-Tổ Hợp
46
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 22. Tìm giá trị
x
thỏa mãn
4 3 4
1
3 24 .
x
x x x
A A C

A.
3.x
B.
1.x
C.
5.x
D.
1; 5.xx
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 23. Có bao nhiêu số tự nhiên
n
thỏa mãn
4
4
15
2 ! 1 !
n
A
nn

?
A.
1.
B.
2.
C.
3.
D. Vô số.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 24. Có bao nhiêu số tự nhiên
n
thỏa mãn
22
1
2 3 20 0
nn
CA
?
A.
1.
B.
2.
C.
3.
D. Vô số.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 24. Có bao nhiêu số tự nhiên
n
thỏa mãn
22
1
2 3 30
nn
CA

?
A.
1.
B.
2.
C.
3.
D. Vô số.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 25. Có bao nhiêu số tự nhiên
n
thỏa mãn
34
3 1 1
14.
n
nn
PC A

?
A.
1.
B.
2.
C.
3.
D. Vô số.
Li gii.
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán V-Chỉnh Hợp-Tổ Hợp
47
Lớp Toán Thầy -Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
H phuơng trình.
1. Phương pháp.
Điu kiện để phương trình xác định.
Biến đổi từng phương trình một rồi dùng phương pháp thế, cộng đại số…
Phương pháp đặt n ph.
2. Bài tập minh họa.
Bài tp11. Giải các phương trình sau
1).
2 5 90
5 2 80
xx
yy
xx
yy
AC
AC


2).
1
11
11
11
35
yy
xx
yy
xx
CC
CC



Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 12. Giải các hệ phương trình sau
a).
1
1
01
4 5 0 2
yy
xx
yy
xx
CC
CC


. b).
11
1
6 5 2
y y y
x x x
C C C


.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán Vị-Chỉnh Hợp-Tổ Hợp
48
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 13. Giải các hệ phương trình sau
a).
32
55
23
55
71
4 7 2


yy
xx
yy
xx
AA
CC
. b).
2 5 90
5 2 80
yy
xx
yy
xx
AC
AC


.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 14. Giải các hệ phương trình sau
a).
2
1
:1
3
1
:2
24
xx
yy
xx
yy
CC
CA
. b).
1 1 1
11
10 1 2
y y y y
x x x x
A yA C A


.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán V-Chỉnh Hợp-Tổ Hợp
49
Lớp Toán Thầy -Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 15. Tìm số nguyên dương
n
thỏa mãn hệ
4 3 2
1 1 2
43
11
5
4
7
15
n n n
n
nn
C C A
CA


.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
3. Câu hi trc nghim.
u 26. Giải hệ phương trình
1
1
0
.
4 5 0
yy
xx
yy
xx
CC
CC


A.
17
.
8
x
y
B.
17
.
8
x
y

C.
9
.
8
x
y
D.
7
.
9
x
y
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 27. Tìm cặp số
;xy
thỏa mãn
11
1
.
6 5 2
y y y
x x x
C C C


A.
; 8;3 .xy
B.
; 3;8 .xy
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán Vị-Chỉnh Hợp-Tổ Hợp
50
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
C.
; 1;0 .xy 
D.
; 1;0 , ; 8;3 .x y x y
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 28. Giải hệ phương trình
2
1
:
3
1
:
.
24
xx
yy
xx
yy
CC
CA
A.
4
.
1
x
y
B.
4
.
8
x
y
C.
44
, .
18
xx
yy





D.
1
.
8
x
y
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 29. Giải hệ phương trình
2 5 90
5 2 80
yy
xx
yy
xx
AC
AC


.
A.
5
.
2
x
y
B.
20
.
10
x
y
C.
2
.
5
x
y
D.
6
.
3
x
y
Li gii.
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán V-Chỉnh Hợp-Tổ Hợp
51
Lớp Toán Thầy -Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
DẠNG 2. Bài toán sắp xếp vị trí.
1. Phương pháp.
Da vào hai quy tc cng, quy tc nhân và các khái nim hoán v.
Các du hiệu đặc trưng để giúp ta nhn dng mt hoán v ca
n
phn t là:
Tt c
n
phn t đều phi có mt.
Mi phn t xut hin mt ln.
Có th t gia các phn t.
2. Bài tp minh ha.
Bài tp 16. Có bao nhiêu cách xếp
n
người ngi vào mt bàn tròn.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 17.
n
bạn nam và
n
bạn nữ ngồi quanh bàn tròn có 2
n
ghế. Có bao nhiêu cách xếp:
1). Nam, nữ ngồi tùy ý.
2). Không có hai học sinh cùng giới ngồi liền nhau.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 18. Mt hi ngh bàn tròn các phái đoàn 3 người Anh , 5 người Pháp 7 người M.
Hi có bao nhiêu cách xếp ch ngi cho các thành viên sao cho những người có cùng quc tch thì
ngi gn nhau.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán Vị-Chỉnh Hợp-Tổ Hợp
52
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 19. Có bao nhiêu cách xếp
5
học sinh
, , , ,A B C D E
vào một ghế dài sao cho:
1).
C
ngồi chính giữa.
2).
A
E
ngồi ở hai đầu ghế.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 20. Có 6 học sinh nam và 3 học sinh nữ xếp hàng dọc vào lớp. Có bao nhiêu cách xếp để
học sinh nữ đứng đầu hàng.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 21. bao nhiêu cách xếp 12 học sinh thành hàng một hàng ngang để chụp ảnh u
niệm, biết rằng trong đó phải có 5 em định trước đứng kề nhau.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 22. Một học sinh có 12 cuốn sách khác nhau gồm 2 Toán, 4 Văn 6 Anh Văn. bao
nhiêu cách xếp 12 cuốn sách trên lên kệ dài mà sách cùng loại liền kề nhau.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 23. Một người có 8 pho tượng khác nhau muốn bày 6 pho tượng trong số đó vào 6
chỗ trống trên một kệ trang trí. Hỏi có bao nhiêu cách sắp xếp
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán V-Chỉnh Hợp-Tổ Hợp
53
Lớp Toán Thầy -Diệp Tuân Tel: 0935.660.880
Bài tp 24. Trong một toa u hai ghế xalông đối mặt nhau, mỗi ghế 4 chỗ ngồi. Trong số
8 hành khách thì 3 người muốn ngồi nhìn theo hướng tàu chạy, còn hai người muốn ngồi theo
hướng ngược lại, 3 người còn lại không có yêu cầu gì. Hỏi có bao nhiêu cách xếp chỗ ngồi để thỏa
mãn các yêu cầu của khách.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 25. Một nhóm lớp học có 10 nam và 6 nữ chụp hình lưu niệm cuối năm cùng thầy giáo
theo một dãy hàng ngang. Hỏi bao nhiêu cách xếp vị trí sao cho mỗi bạn nữ luôn 2 nam
đứng cạnh 2 bên.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
3. Câu hi trc nghim.
u 30. bao nhiêu khả năng thể xảy ra đối với thứ tự giữa các đội trong một giải bóng 5
đội bóng? (giả sử rằng không có hai đội nào có điểm trùng nhau)
A.
120.
B.
100.
C.
80.
D.
60.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 31. Có bao nhiêu cách xếp khác nhau cho 5 người ngồi vào một bàn dài?
A.
120
B.
5
C.
20
D.
25
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 32. Số cách sắp xếp 6 nam sinh và 4 nữ sinh vào một dãy ghế hàng ngang có 10 chỗ ngồi là:
A.
6!4!.
B.
10!.
C.
6! 4!.
D.
6! 4!.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 33. Sắp xếp năm bạn học sinh An, Bình, Chi, Dũng, Lệ vào một chiếc ghế dài 5 chỗ ngồi. Số
cách sắp xếp sao cho bạn Chi luôn ngồi chính giữa là
A.
24.
B.
120.
C.
60.
D.
16.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 34. Sắp xếp năm bạn học sinh An, Bình, Chi, Dũng, Lệ vào một chiếc ghế dài có 5 chỗ ngồi. Hỏi
có bao nhiêu cách sắp xếp sao cho bạn An và bạn Dũng luôn ngồi ở hai đầu ghế?
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán Vị-Chỉnh Hợp-Tổ Hợp
54
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
A.
120.
B.
16
C.
12.
D.
24.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 35. Sắp xếp năm bạn học sinh An, Bình, Chi, Dũng, Lệ vào một chiếc ghế dài có 5 chỗ ngồi. Hỏi
có bao nhiêu cách sắp xếp sao cho bạn An và bạn Dũng không ngồi cạnh nhau?
A.
24
. B.
48
. C.
72
. D.
12
.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 36. 3 viên bi đen khác nhau, 4 viên bi đkhác nhau, 5 viên bi xanh khác nhau. Hỏi bao
nhiêu cách sắp xếp các viên bi trên thành một dãy sao cho các viên bi cùng màu ở cạnh nhau?
A.
345600.
B.
725760.
C.
103680.
D.
518400.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 37. dâu chú rể mời
6
người ra chụp ảnh kỉ niệm, người thợ chụp hình bao nhiêu
cách sắp xếp sao cho cô dâu, chú rể đứng cạnh nhau.
A.
8! 7!.
B.
2.7!.
C.
6.7!.
D.
2! 6!.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 38. Trên giá sách muốn xếp
20
cuốn sách khác nhau. bao nhiêu cách sắp xếp sao cho tập
1
và tập
2
đặt cạnh nhau.
A.
20! 18!.
B.
20! 19!.
C.
20! 18!.2!.
D.
19!.18.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 39. Có bao nhiêu cách sắp xếp 4 người vào 4 ghế ngồi được bố trí quanh một bàn tròn?
A.
12.
B.
24.
C.
4.
D.
6.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 40. 4 nữ sinh tên Huệ, Hồng, Lan, Hương 4 nam sinh tên An, Bình, Hùng, Dũng
cùng ngồi quanh một bàn tròn 8 chỗ ngồi. Hỏi bao nhiêu cách sắp xếp biết nam nữ ngồi
xen kẽ nhau?
A.
576.
B.
144.
C.
2880.
D.
1152.
Li gii.
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán V-Chỉnh Hợp-Tổ Hợp
55
Lớp Toán Thầy -Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 41. Từ các số tự nhiên 1, 2, 3, 4 có thể lập được bao nhiêu số tự nhiên có 4 chữ số khác nhau:
A.
4
4.
B.
24
. C.
1
. D.
42
.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
DẠNG 3. i toán đếm chn số.
2. Phương pháp.
Da vào hai quy tc cng, quy tc nhân và các khái nim hoán v, chnh hp, t hp.
Mt s du hiu giúp chúng ta nhn biết được hoán v, chnh hp hay t hp.
Chnh hp: Ta s s dng khái nim chnh hp khi
Cn chn k phn t t n phn t, mi phn t xut hin mt ln.
k
phn t đã cho được sp xếp th t.
T hp: Ta s dng khái nim t hp khi
Cn chn
k
phn t t n phn t, mi phn t xut hin mt ln
Không quan tâm đến th t
k
phn t đã chọn.
3. Bài tp minh ha.
Loại 1: Đếm s
Bài tp 26. T các s 1, 2, 3, 4, 5, 6 lập được bao nhiêu s t nhiên
1). Gm 4 ch s.
2). Gm 3 ch s đôi một khác nhau.
3). Gm 4 ch s đôi một khác nhau và là ch s t nhiên chn.
4). Gm 4 ch s đôi một khác nhau và không bắt đầu bng ch s 1.
5). Gm 6 ch s đôi một khác nhau và hai ch s 1 và 2 không đứng cnh nhau.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán Vị-Chỉnh Hợp-Tổ Hợp
56
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 27. T các ch s 0,1,2,3,4,5,6 th lập được bao nhiêu s chn, mi s 5 ch s
khác nhau trong đó có đúng hai chữ s l và 2 ch s l đứng cnh nhau?
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 28. Có bao nhiêu s t nhiên gm 7 ch s, biết rng ch s 2 có mt hai ln, ch s ba
có mt ba ln và các ch s còn li có mt nhiu nht mt ln?
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 29. Hi có th lập được bao nhiêu s t nhiên 4 ch s sao cho trong mi s đó, chữ
s hàng ngàn lớn hơn hàng trăm, chữ s hàng trăm lớn hơn hàng chục ch s hàng chc ln
hơn hàng đơn vị.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán V-Chỉnh Hợp-Tổ Hợp
57
Lớp Toán Thầy -Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 30. T các s
1,2,3,4,5,6,7,8,9
th lập được bao nhiêu s t nhiên , mi s
6
ch s khác nhau và tng các ch s hàng chục, hàng trăm, hàng ngàn bằng 8.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 31. T các ch s ca tp hp
0,1,2,3,4,5,6A
lập được bao nhiêu s t nhiên gm
1). 5 ch s.
2). 4 ch s đôi một khác nhau.
3). 4 ch s đôi một khác nhau và là s l
4). 5 ch s đôi một khác nhau và là s chn.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
4. Câu hi trc nghim.
u 42. Từ các chữ số
1
;
2
;
3
;
4
có thể lập được bao nhiêu số tự nhiên có
4
chữ số đôi một khác
nhau?
A.
12
. B.
24
. C.
. D.
4
4
.
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán Vị-Chỉnh Hợp-Tổ Hợp
58
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 43. Cho
1,2,3,4A
. Từ
A
lập được bao nhiêu số tự nhiên có
4
chữ số đôi một khác nhau?
A.
. B.
24
. C.
256
. D.
18
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 44. Từ các chữ số
1
;
2
;
3
thể lập được bao nhiêu số tự nhiên
3
chữ số khác nhau đôi
một?
A.
8
. B.
6
. C.
9
. D.
3
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 45. Từ tập
2,3,4,5,6X
có thể lập được bao nhiêu số tự nhiên có ba chữ số mà các chữ số
đôi một khác nhau ?
A.
60
. B.
125
. C.
10
. D.
6
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 46. Có bao nhiêu số tự nhiên có
5
chữ số, các chữ số khác
0
và đôi một khác nhau?
A.
5!
. B.
5
9
. C.
5
9
C
. D.
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 47. Có bao nhiêu số chẵn mà mỗi số có
4
chữ số đôi một khác nhau?
A.
2520
. B.
50000
. C.
4500
. D.
2296
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 48. bao nhiêu số tự nhiên có sáu chữ số khác nhau từng đôi một, trong đó chữ số
5
đứng
liền giữa hai chữ số
1
4
?
A.
249
. B.
1500
. C.
3204
. D.
2942
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán V-Chỉnh Hợp-Tổ Hợp
59
Lớp Toán Thầy -Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 49. Từ các chữ số
0
,
1
,
2
,
3
,
5
thể lập được bao nhiêu số gồm
4
chữ số khác nhau
không chia hết cho
5
?
A.
72
. B.
120
. C.
. D.
69
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 50. bao nhiêu số tự nhiên ba chữ số dạng
abc
với
a
,
b
,
c
0;1;2;3;4;5;6
sao cho
abc
.
A.
120
. B.
. C.
40
. D.
20
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 51. bao nhiêu số tự nhiên có bảy chữ số khác nhau từng đôi một, trong đó chữ số
2
đứng
liền giữa hai chữ số
1
3
.
A.
3204
số. B.
249
số. C.
2942
số. D.
7440
số.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 52. T các ch s
1
,
2
,
3
,
4
,
5
,
6
th lập được bao nhiêu s t nhiên l
6
ch s khác
nhau và trong mi s đó tổng ca ba ch s đầu lớn hơn tổng ca ba ch s cui một đơn vị
A.
. B.
72
. C.
. D.
24
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán Vị-Chỉnh Hợp-Tổ Hợp
60
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 53. Có bao nhiêu số tự nhiên lẻ có 4 chữ số khác nhau?
A.
2240.
B.
2520.
C.
2016.
D.
256.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 54. Gọi
S
tập hợp tất cả các số tự nhiên gồm 5 chsố đôi một khác nhau được lập từ các
chữ số
5,6,7,8,9.
Tính tổng tất cả các số thuộc tâp
.S
A.
9333420.
B.
46666200.
C.
9333240.
D.
46666240.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 55. bao nhiêu số tự nhiên
7
chữ số khác nhau từng đôi một, trong đó chữ số
2
đứng
liền giữa chữ số
1
và chữ số
3
?
A.
2942
. B.
5880
. C.
7440
. D.
3204
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 56. Lập được bao nhiêu số tự nhiên
3
chữ số khác nhau chọn từ tập
1;2;3;4;5A
sao
cho mỗi số lập được luôn có mặt chữ số
3
A.
72
. B.
. C.
. D.
48
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán V-Chỉnh Hợp-Tổ Hợp
61
Lớp Toán Thầy -Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 57. Từ các chữ số
0
,
1
,
2
,
3
,
4
,
5
,
6
có thể lập được bao nhiêu số có
5
chữ số khác nhau mà
số đó nhất thiết phải có mặt các chữ số
1
,
2
,
5
?
A.
684
. B.
648
. C.
846
. D.
864
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 58. bao nhiêu số tự nhiên
6
chữ số đôi một khác nhau trong đó chứa các chữ số
3
,
4
,
5
và chữ số
4
đứng cạnh chữ số
3
và chữ số
5
?
A.
1470
. B.
750
. C.
2940
. D.
1500
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 59. bao nhiêu số tự nhiên tám chữ số trong đó ba chữ số
0
, không hai chữ số
0
nào đứng cạnh nhau và các chữ số khác chỉ xuất hiện nhiều nhất một lần.
A.
786240
. B.
846000
. C.
907200
. D.
151200
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán Vị-Chỉnh Hợp-Tổ Hợp
62
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 60. Từ
2
chữ số
1
8
lập được bao nhiêu số tự nhiên
8
chữ số sao cho không
2
chữ
số
1
đứng cạnh nhau?
A.
. B.
110
. C.
. D.
108
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 61. Từ các chữ số
0
,
1
,
2
,
3
,
4
,
5
,
8
lập được bao nhiêu số ba chữ số đôi một khác nhau,
chia hết cho
2
3
.
A.
số. B.
số. C.
số. D.
48
số.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 62. bao nhiêu số tự nhiên tám chữ số trong đó ba chữ số
0
, không hai chữ số
0
nào đứng cạnh nhau và các chữ số khác chỉ xuất hiện nhiều nhất một lần.
A.
786240
. B.
846000
. C.
907200
. D.
151200
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 63. Cho
5
chữ số
1
,
2
,
3
,
4
,
6
. Lập các số tự nhiên
3
chữ số đôi một khác nhau từ
5
chữ
số đã cho. Tính tổng của các số lập được.
A.
12321
. B.
21312
. C.
12312
. D.
21321
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán V-Chỉnh Hợp-Tổ Hợp
63
Lớp Toán Thầy -Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 64. Cho tập
1;2;3;...;2018A
các số
,,a b c A
. Hỏi bao nhiêu số tự nhiên dạng
abc
sao cho
abc
2016abc
.
A.
2027070
. B.
2026086
. C.
337681
. D.
20270100
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Loại 2: Xếp đồ vật Phân công công việc
Bài tp 32. Có 3 bông hng vàng, 3 bông hng trng và 4 bông hồng đỏ ( các bông hoa xem như
đôi 1 khác nhau) người ta mun chn ra mt bó hoa gm 7 bông.
1). Có bao nhiêu cách chn các bông hoa được chn tu ý.
2). Có bao nhiêu cách chn sao cho có đúng 1 bông màu đỏ.
3). Có bao nhiêu cách chn sao cho có ít nht 3 bông hng vàng và ít nht 3 bông hồng đỏ.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 33. Có 10 qu cầu đỏ được đánh số t 1 đến 10, 7 qu cu xanh được đánh số t 1 đến
7 và 8 qu cầu vàng được đánh số t 1 đến 8. Hi có bao nhiêu cách ly ra 3 qu cu khác màu và
khác s.
Li gii.
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán Vị-Chỉnh Hợp-Tổ Hợp
64
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 34. Có 7 bông hồng đỏ, 8 bông hng vàng 10 bông hng trng, mi bông hng khác
nhau từng đôi một. Hi có bao nhiêu cách ly 3 bông hồng có đủ ba màu.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 35. Mt lp hc 20 nam 26 n. Giáo viên ch nhim cn chn mt ban cán s
gồm 3 người. Hi có bao nhiêu cách chn nếu
1). Trong ban cán s có ít nht mt nam
2). Trong ban cán s có c nam và n.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 36. Một đội thanh niên tình nguyện có 15 người ,gm 12 nam và 3 n .Hi có bao nhiêu
cách phân công đội thanh niên tình nguyện đó về giúp đỡ 3 tnh min núi, sao cho mi tnh 4
nam và mt n ?
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 37. Một đội thanh niên tình nguyn có 15 người gm 12 nam và 3 n. Hi có bao nhiêu
cách phân công đội thanh niên tình nguyện đó về 3 tnh min núi sao cho mi tnh 4 nam và 1
n.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán V-Chỉnh Hợp-Tổ Hợp
65
Lớp Toán Thầy -Diệp Tuân Tel: 0935.660.880
Bài tp 38. Đội thanh niên xung kích ca một trường ph thông 12 hc sinh, gm 5 hc
sinh lp A, 4 hc sinh lp B 3 hc sinh lp C. Cn chn 4 học sinh đi làm nhiệm v sao cho 4
hc sinh này thuc không quá 2 trong ba lp trên. Hi có bao nhiêu cách chọn như vy?
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 39. Đội tuyn HSG ca một trường gồm 18 em, trong đó 7 HS khi 12, 6 HS khi 11
và 5 HS khi 10. Hi có bao nhiêu cách c 8 cách c 8 HS đi dự đại hi sao cho mi khi có ít nht
1 HS được chn
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 40. Mt cuc họp 13 người, lúc ra v mỗi người đều bắt tay người khác mt ln,
riêng ch ta ch bắt tay ba người. Hi có bao nhiêu cái bt tay?
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 41. Đội tuyn hc sinh gii ca một trường gồm 18 em, trong đó có 7 em khối 12, 6 em
khi 11 5 em khi 10. Tính s cách chọn 6 em trong đội đi dự tri sao cho mi khi ít
nhất 1 em được chn
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 42. Trong mt môn hc, Thy giáo 30 câu hi khác nhau gm 5 câu k,10 câu
trung bình và 15 câu d .T 30 câu hỏi đó thể lập được bao nhiêu đề kim tra, mỗi đề gm 5
câu hi khác nhau, sao cho trong mỗi đề nht thiết phải đủ c 3 câu ( khó, d, Trung bình)
s câu d không ít hơn 2?
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán Vị-Chỉnh Hợp-Tổ Hợp
66
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 43. Hai nhóm người cn mua nn nhà, nhóm th nhất 2 người h mun mua 2
nền k nhau, nhóm th hai 3 người h mun mua 3 nn k nhau. H tìm được một đất
chia thành 7 nền đang rao bán (các nền như nhau và chưa có người mua). Tính s cách chn nn
ca mỗi người tha yêu cu trên
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 44. Mt nhóm công nhân gm 15 nam 5 nữ. Người ta mun chn t nhóm ra 5
người để lp thành mt t công tác sao cho phi có 1 t trưởng nam, 1 t phó nam và có ít nht 1
n. Hi có bao nhiêu cách lp t công tác
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 45. Mt nhóm 5 nam 3 n. Chọn ra 3 người sao cho trong đó ít nhất 1 n. Hi
có bao nhiêu cách.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 46. Một đội văn nghệ 15 người gm 10 nam 5 n. Hi bao nhiêu cách lp mt
nhóm đồng ca gồm 8 người biết rằng nhóm đó có ít nhất 3 n.
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán V-Chỉnh Hợp-Tổ Hợp
67
Lớp Toán Thầy -Diệp Tuân Tel: 0935.660.880
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 47. Mt lp 33 học sinh, trong đó 7 n. Cn chia lp thành 3 t, t 1 10 hc
sinh, t 2 có 11 hc sinh, t 3 có 12 hc sinh sao cho trong mi t có ít nht 2 hc sinh n. Hi
bao nhiêu cách chia như vậy?
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 48. 7 nhà toán hc nam, 4 nhà toán hc n 5 nhà vt nam.Có bao nhiêu cách
lập đoàn công tác gồm 3 người có c nam và n đồng thi có c toán hc và vt lý.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 49. Có 15 hc sinh lớp A, trong đó có Khánh và 10 học sinh lp B, trong đó có Oanh. Hi
bao nhiêu cách lp một đội tình nguyn gm 7 học sinh trong đó 4 học sinh lp A, 3 hc
sinh lớp B và trong đó chỉ có mt trong hai em Hùng và Oanh.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán Vị-Chỉnh Hợp-Tổ Hợp
68
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 50. T 20 câu hi trc nghim gm 9 câu dễ, 7 câu trung bình 4 câu khó ngưi ta
chọn ra 10 câu để làm đề kim tra sao cho phải đủ c 3 loi d, trung bình khó. Hi th
lập được bao nhiêu đề kim tra
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 51. Mt Thy giáo 5 cun sách Toán, 6 cuốn sách Văn 7 cuốn sách anh văn các
cuốn sách đôi một khác nhau. Thy giáo mun tng 6 cun sách cho 6 hc sinh. Hi Thy giáo có
bao nhiêu cách tng nếu:
1). Thy giáo ch mun tng hai th loi
2). Thy giáo mun sau khi tng xong mi th loi còn li ít nht mt cun.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 51. Mt Thy giáo 10 cuốn sách Toán đôi một khác nhau, trong đó 3 cuốn Đại s,
4 cun Gii tích và 3 cun Hình hc. Ông mun ly ra 5 cun tng cho 5 hc sinh sao cho sau
khi tng mi loi sách còn li ít nht mt cun. Hi có bao nhiêu cách tng.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán V-Chỉnh Hợp-Tổ Hợp
69
Lớp Toán Thầy -Diệp Tuân Tel: 0935.660.880
Bài tp 52. Mt nhóm hc sinh gm 15 nam và 5 nữ. Người ta mun chn t nhóm ra 5 người
để lp thành một đội c đỏ sao cho phải 1 đội trưởng nam, 1 đi phó nam ít nht 1 n.
Hi có bao nhiêu cách lập đội c đỏ.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
3. Câu hi trc nghim.
u 65. Một lớp học
40
học sinh, trong đó
25
nam và
15
nữ. Giáo viên cần chọn
3
học sinh
tham gia vệ sinh công cộng toàn trường. Hỏi có bao nhiêu cách chọn
3
học sinh trong đó có nhiều
nhất
1
học sinh nam?
A.
2625.
B.
455.
C.
2300.
D.
3080.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 66. Từ
20
người cần chọn ra một đoàn đại biểu gồm
1
trưởng đoàn,
1
phó đoàn,
1
thư kí và
3
ủy viên. Hỏi có bao nhiêu cách chọn đoàn đại biểu ?
A.
4651200.
B.
4651300.
C.
4651400.
D.
4651500.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán Vị-Chỉnh Hợp-Tổ Hợp
70
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 67. Một tổ gồm
10
học sinh. Cần chia tổ đó thành ba nhóm có
5
học sinh,
3
học sinh và
2
học
sinh. Số các chia nhóm là:
A.
2880.
B.
2520.
C.
2515.
D.
2510.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 68. Một nhóm đoàn viên thanh niên tình nguyện về sinh hoạt tại một xã nông thôn gồm có
đoàn viên nam
15
đoàn viên nữ. Hỏi bao nhiêu cách phân chia
3
nhóm về
3
ấp để hoạt
động sao cho mỗi ấp có 7 đoàn viên nam và 5 đoàn viên nữ?
A.
12
36
3.C
B.
12
36
.C
C.
75
21 15
3.CC
D.
7 5 7 5
21 15 14 10
.C C C C
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 69. Trong một giỏ hoa có
5
bông hồng vàng,
3
bông hồng trắng và
4
bông hồng đỏ (các bông
hoa coi như đôi một khác nhau). Người ta muốn làm một bó hoa gồm
7
bông được lấy từ giỏ hoa
đó. Hỏi có bao nhiêu cách chọn hoa biết bó hoa có đúng
1
bông hồng đỏ?
A.
56.
B.
112.
C.
224.
D.
448.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 70. Một hộp có
6
viên bi xanh,
5
viên bi đỏ và
4
viên bi vàng. Chọn ngẫu nhiên
5
viên bi sao
cho có đủ cả ba màu. Số cách chọn là:
A.
2163.
B.
3843.
C.
3003.
D.
840.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 71. Đội văn nghệ của nhà trường gồm
4
học sinh lớp 12A,
3
học sinh lớp 12B
2
học sinh
lớp 12C. Chọn ngẫu nhiên 5 học sinh từ đội văn nghệ để biểu diễn trong lễ bế giảng. Hỏi bao
nhiêu cách chọn sao cho lớp nào cũng có học sinh được chọn?
A.
126.
B.
102.
C.
98.
D.
100.
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán V-Chỉnh Hợp-Tổ Hợp
71
Lớp Toán Thầy -Diệp Tuân Tel: 0935.660.880
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 72.
12
học sinh giỏi gồm
3
học sinh khối 12,
4
học sinh khối 11
5
học sinh khối 10.
Hỏi bao nhiêu cách chọn ra
6
học sinh trong số học sinh giỏi đó sao cho mỗi khối ít nhất
1
học sinh?
A.
85.
B.
58.
C.
508.
D.
805.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 73. Đội học sinh giỏi cấp trường môn Tiếng Anh của trường THPT X theo từng khối như sau:
khối 10
5
học sinh, khối 11
5
học sinh khối 12
5
học sinh. Nhà trường cần chọn một
đội tuyển gồm
10
học sinh tham gia IOE cấp tỉnh. Tính số cách lập đội tuyển sao cho có học sinh
cả ba khối và có nhiều nhất
2
học sinh khối 10.
A.
50.
B.
500.
C.
502.
D.
501.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 74. Đội văn nghcủa một nhà trường gồm
4
học sinh lớp 12A,
3
học sinh lớp 12B
2
học
sinh lớp 12C. Cần chọn ngẫu nhiên
5
học sinh từ đội văn nghệ đó để biểu diễn trong lễ bế giảng.
Hỏi bao nhiêu cách chọn sao cho lớp nào cũng học sinh được chọn ít nhất
2
học sinh
lớp 12A?
A.
80.
B.
78.
C.
76.
D.
98.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán Vị-Chỉnh Hợp-Tổ Hợp
72
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 75. Một hộp đựng
8
viên bi màu xanh,
5
viên bi đỏ,
3
viên bi màu vàng. bao nhiêu cách
chọn từ hộp đó ra
4
viên bi sao cho số bi xanh bằng số bi đỏ?
A.
280.
B.
400.
C.
40.
D.
1160.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 76. Một hộp bi có
5
viên bi đỏ,
3
viên bi vàng và
4
viên bi xanh. Hỏi có bao nhiêu cách lấy ra
4
viên bi trong đó số viên bi đỏ lớn hơn số viên bi vàng.
A.
654.
B.
275.
C.
462.
D.
357.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 77.
5
tem thư khác nhau và 6 bì thư khác nhau. Từ đó người ta muốn chọn ra 3 tem thư, 3
bì thư và dán 3 tem thư ấy lên 3 bì đã chọn. Hỏi có bao nhiêu cách làm như thế?
A.
1000.
B.
1200.
C.
2000.
D.
2200.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 78. Cho
10
câu hỏi, trong đó
4
câu thuyết
6
câu bài tập, người ta cấu tạo thành các
đề thi. Biết rằng trong đề thi phải gồm
3
câu hỏi trong đó ít nhất
1
u thuyết
1
câu hỏi
bài tập. Hỏi có thể tạo được bao nhiêu đề như trên ?
A.
69.
B.
88.
C.
96.
D.
100.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán V-Chỉnh Hợp-Tổ Hợp
73
Lớp Toán Thầy -Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Loi 3: Đếm t hp liên quan đến hình hc
4. 1. Phương pháp.
Cho một đa giác có
n
đỉnh.
C hai điểm bt k
2
n
C
s cnh hoặc đường chéo.
S đưng chéo bng
2
n
Cn
C ba điểm bt k
3
n
C
tam giác được to thành.
5. 2. Các ví dụ.
Bài tp 53. Mt Cho hai đường thng song song
12
,dd
. Trên đường thng
1
d
ly
10
đim phân
bit, trên
2
d
ly
15
đim phân bit. Hỏi bao nhiêu tam giác ba đỉnh của được chn t
25
va nói trên.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 54. Trong mt phẳng cho 2010 điểm phân biệt sao cho ba điểm bt không thng
hàng. Hi:
1). Có bao nhiêu véc tơ khác véc tơ – không có điểm đầu và điểm cui thuộc 2010 điểm đã cho.
2). Có bao nhiêu tam giác mà ba đỉnh ca nó thuộc vào 2010 điểm đã cho.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 55. Cho đa giác lồi có
n
4n
cạnh. Tìm
n
để đa giác có số đường chéo bằng số cạnh
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán Vị-Chỉnh Hợp-Tổ Hợp
74
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
Bài tp 56. Cho hai đường thẳng song song
1
d
2
d
. Trên
1
d
có 6 điểm phân biệt, trên
2
d
n
điểm phân biệt
2, nn
. Tìm
n
, biết rằng có 96 tam giác có đỉnh là các điểm đã cho.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 57. Trong mặt phẳng cho đa giác đều
H
20
cạnh. Xét tam giác đúng
3
đỉnh
được lấy từ các đỉnh của
H
.
a). Có tất cả bao nhiêu tam giác như vậy.
b). Có bao nhiêu tam giác có đúng hai cạnh là cạnh của
H
.
c). Có bao nhiêu tam giác có đúng một cạnh là cạnh của
H
.
d). Có bao nhiêu tam giác không có cạnh nào là cạnh của
H
.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 58.
1). Cho hai đường thng d
1
d
2
song song vi nhau. Trên d
1
10 điểm phân bit, trên d
2
n điểm phân bit (
2n
). Biết có 2800 tam giác có đỉnh là các điểm nói trên. Tìm n?
2). Cho đa giác đều
1 2 2
...
n
A A A
ni tiếp trong đường tròn tâm O. Biết rng s tam giác có đỉnh
3 trong 2n điểm
1 2 2
, ,...,
n
A A A
gp 20 ln so vi s hình ch nhật đỉnh 4 trong 2n điểm
1 2 2
, ,...,
n
A A A
. Tìm n?
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán V-Chỉnh Hợp-Tổ Hợp
75
Lớp Toán Thầy -Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 59. Trong mt phng cho
n
điểm, trong đó không 3 đim nào thng hàng trong
tt c các đường thng nối hai điểm bất kì, không hai đường thng nào song song, trùng nhau
hoặc vuông góc. Qua mi dim v các đường thng vuông góc với các đường thẳng được xác định
bi 2 trong
1n
đim còn li. S giao điểm của các đường thng vuông góc giao nhau bao
nhiêu?
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 60. Cho mt tp hp A gm
n
phn t (
4n
). Biết s tp con gm 4 phn t ca A gp
20 ln s tp con gm hai phn t ca A
1). Tìm
n
2). Tìm
1,2,3,...,kn
sao cho s tp con gm
k
phn t ca tp A là ln nht.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán Vị-Chỉnh Hợp-Tổ Hợp
76
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
4. Câu hi trc nghim.
u 79. Trong mặt phẳng cho tập hợp
P
gồm
2018
điểm phân biệt. Hỏi bao nhiêu đoạn thẳng
mà hai đầu mút thuộc
?P
A.
2018!
.
2016!
B.
2016!
.
2!
C.
2018!
.
2!
D.
2018!
.
2016!.2!
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 80. Cho
10
điểm, không
3
điểm nào thẳng hàng. Hỏi có bao nhiêu đường thẳng khác nhau
tạo bởi
2
trong
10
điểm nói trên?
A.
90.
B.
20.
C.
45.
D. Một số khác.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 81. Trong mặt phẳng, cho
6
điểm phân biệt sao cho không có ba điểm nào thẳng hàng. Hỏi có
thể lập được bao nhiêu tam giác mà các đỉnh của nó thuộc tập điểm đã cho?
A.
15.
B.
20.
C.
60.
D. Một số khác.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 82. Cho
10
điểm phân biệt
1 2 10
, ,...,A A A
trong đó có
4
điểm
1 2 3 4
, , ,A A A A
thẳng hàng, ngoài ra
không
3
điểm nào thẳng hàng. Hỏi bao nhiêu tam giác
3
đỉnh được lấy trong
10
điểm
trên?
A.
tam giác. B.
60
tam giác. C.
116
tam giác. D.
tam giác.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán V-Chỉnh Hợp-Tổ Hợp
77
Lớp Toán Thầy -Diệp Tuân Tel: 0935.660.880
u 83. Cho mặt phẳng chứa đa giác đều
H
20
cạnh. Xét tam giác
3
đỉnh được lấy từ các
đỉnh của
H
. Hỏi có bao nhiêu tam giác có đúng
1
cạnh là cạnh của
H
.
A.
1440.
B.
360.
C.
1120.
D.
816.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 84. Cho hai đường thẳng song song
1
d
2
.d
Trên
1
d
lấy 17 điểm phân biệt, trên
2
d
ly 20
điểm phân biệt. Tính số tam giác mà có các đỉnh được chọn từ
37
điểm này.
A.
5690.
B.
5960.
C.
5950.
D.
5590.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 85. Số giao điểm tối đa của
5
đường tròn phân biệt là:
A.
10.
B.
20.
C.
18.
D.
22.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 86. Số giao điểm tối đa của
10
đường thẳng phân biệt là:
A.
50.
B.
100.
C.
120.
D.
45.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 87. Với đa giác lồi
10
cạnh thì số đường chéo là
A.
90.
B.
45.
C.
35.
D. Một số khác.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 88. Cho đa giác đều
n
đỉnh,
n
3.n
Tìm
n
biết rằng đa giác đã cho
135
đưng
chéo.
A.
15.n
B.
27.n
C.
8.n
D.
18.n
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 2. Hoán Vị-Chỉnh Hợp-Tổ Hợp
78
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 89. Trong mặt phẳng bao nhiêu hình chữ nhật được tạo thành từ bốn đường thẳng phân
biệt song song với nhau năm đường thẳng phân biệt vuông góc với bốn đường thẳng song
song đó.
A.
60.
B.
48.
C.
20.
D.
36.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 3. Nhị Thức NewTơn
79
Lớp Toán Thầy-Diệp Tn Tel: 0935.660.880
A LÝ THUYT.
1. Nh thc Newton
0 1 1 2 2 2 1 1
0
( ) ...
n
n k n k k n n n n n n n
n n n n n n
k
a b C a b C a C a b C a b C ab C b
Ví d 1. Khai triển các nhị thức sau:
a).
5
2xy
b).
6
23xy
c).
5
1
2x
y



d).
6
1
2y
x



Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
2. Nhn xét
Trong khai trin Newton
()
n
ab
có các tính cht sau:
Gm có
1n
s hng.
S mũ của
a
gim t
n
đến
0
và s mũ của
b
tăng từ
0
đến
n
.
Tng các s mũ của
a
b
trong mi s hng bng
n
.
Các h s có tính đối xng:
k n k
nn
CC
S hng tng quát :
1
k n k k
kn
T C a b
.
Ví d 2. Tìm số hạng thứ
6
trong khai triển
13
2xy
.
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
3. Mt s h qu
§BI 3. THC NEW TƠN
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 3. Nhị Thức NewTơn
80
Lớp Toán Thầy-Diệp Tn Tel: 0935.660.880
Ta có :
0 1 2 2
(1 ) ...
n n n
n n n n
x C xC x C x C
. T khai trin này ta có các kết qu sau
01
... 2
nn
n n n
C C C
0 1 2
... ( 1) 0
nn
n n n n
C C C C
4. Tam giác Pa-xcan
Trên đây ta thấy mun khai trin
n
ab
thành đa thức, ta biết
1n
s
0 1 2 1
, , ,..., ,
nn
n n n n n
C C C C C
mt trong công thc nh thc Niu-tơn. Các số này có th tính được bng cách s dng bng s sau
Bng s này do nhà toán hc Pháp Pa-xcan thiết lập vào năm 1653 được người ta gi tam
giác Pa-xcan.
Tam giác Pa-xcan được thiết lp theo quy lut sau :
Đỉnh được ghi s 1. Tiếp theo là hàng th nht ghi hai s 1.
Nếu biết hàng th
1nn
thì hàng th
1n
tiếp theo được thiết lp bng cách cng hai
s liên tiếp ca hàng th
n
ri viết kết qu xuống hàng dưới v trí gia hai s này. Sau đó
viết s 1 đầu và cui hàng.
5. Các công thc b tr.
Cùng cơ số, khác mũ
.
m n m n
x x x
:
m n m n
x x x
.
nm
m n m n
x x x
Khác cơ số, cùng mũ
.
m
mm
x y xy
:
m
mm
x
xy
y



1
n
n
x
x
Mi quan h n thức và lũy tha
1
2
0x x x
m
n
m
n
xx
BPHÂN DNG VÍ D MINH HA.
DNG 1. c định s hng th
k
trong khai trin, s hng đng gia trong khai trin.
1. Phương pháp.
S hạng đứng gia: gi s trong khai trin
()
n
ab
1Ln
s hng.
Nếu
L
là s l thì có 1 s hạng đứng gia và s hng th
1
2
L
.
Nếu
L
là s chn thì có 2 s hạng đứng gia và s hng th
2
L
1
2
L
.
S hng th
1k
là :
1
, 0 ,
k n k k
kn
T C a b k n n
2. Bài tp minh ha.
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 3. Nhị Thức NewTơn
81
Lớp Toán Thầy-Diệp Tn Tel: 0935.660.880
Bài tp 1. Tìm số hạng thứ
k
trong các khai triển nhị thức sau:
1). Tìm số hạng thứ 6 trong khai triển
11
3xy
2). Tìm số hạng thứ 8 trong khai triển
15
2
2x
y



Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 2. Tìm hng t đứng gia trong các khai trin sau:
1).
10
3
5
1
x
x



2).
30
3
x xy
3).
15
3
x xy
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
3. Câu hi trc nghim.
u 1. Đa thức
5 4 3 2
80 80 40 10 132P x x xx xx
là khai triển của nhị thức nào?
A.
5
1 2 .x
B.
5
1 2 .x
C.
5
2 1 .x
D.
5
1.x
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 3. Nhị Thức NewTơn
82
Lớp Toán Thầy-Diệp Tn Tel: 0935.660.880
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 2. Trong khai triển
5
2ab
, hệ số của số hạng thứ
3
bằng:
A.
80
. B.
. C.
10
. D.
10
.
Li gii
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 3. Trong khai triển
7
2
1
a
b



, số hạng thứ
5
là:
A.
64
35. .ab
. B.
64
35. .ab
. C.
45
35. .ab
. D.
4
35. .ab
.
Li gii
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 4. Trong khai triển
5
0,2 + 0,8
, số hạng thứ tư là:
A.
0,0064
. B.
0,4096
. C.
0,0512
. D.
0,2048
.
Li gii
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 5. Trong khai triển nhị thức:
7
2
1
a
b



Số hạng thứ 5 là:
A.
64
35ab
B.
64
35ab
C.
45
21ab
D.
45
21ab
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 6. Trong khai triển
6
21a
, tổng ba số hạng đầu là:
A.
6 5 4
2 6 15a a a
. B.
6 5 4
2 15 30a a a
.
C.
6 5 4
64 192 480a a a
. D.
6 5 4
64 192 240a a a
.
Li gii
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 3. Nhị Thức NewTơn
83
Lớp Toán Thầy-Diệp Tn Tel: 0935.660.880
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 7. Trong khai triển
16
xy
, tổng hai số hạng cuối là:
A.
15 8
16x y y
. B.
15 4
16x y y
. C.
15 4
16xy y
. D.
15 8
16xy y
.
Li gii
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 8. Trong khai triển nhị thức
6
2,
n
an

. Có tất cả
số hạng. Vậy
n
bằng:
A.
. B.
11.
C.
10
. D.
12
.
Li gii
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 9. Tìm số hạng đứng giữa trong khai triển
21
3
.x xy
A.
10 40 10
21
.C x y
B.
10 43 10
21
.C x y
C.
11 41 11
21
.C x y
D.
10 43 10
21
C x y
;
11 41 11
21
.C x y
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 10. Trong khai triển
10
2
3xy
, hệ số của số hạng chính giữa là:
A.
44
10
3.C
. B.
44
10
3.C
. C.
55
10
3.C
. D.
55
10
3.C
.
Li gii
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 11. Số hạng chính giữa trong khai triển
4
3 2xy
là:
A.
2 2 2
4
C x y
.
B.
22
6 3 2xy
.
C.
2 2 2
4
6C x y
.
D.
2 2 2
4
36C x y
.
Li gii
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 12. Trong khai triển
20
13x
với số mũ tăng dần,hệ số của số hạng đứng chính giữa là
A.
99
20
3 C
. B.
12 12
20
3 C
. C.
11 11
20
3 C
. D.
10 10
20
3 C
.
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 3. Nhị Thức NewTơn
84
Lớp Toán Thầy-Diệp Tn Tel: 0935.660.880
Li gii
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 13. Tìm số hạng chính giữa của khai triển
8
3
4
1
()x
x
,với
0x
A.
1
4
56x
. B.
1
3
70x
. C.
1
3
70x
1
4
56x
. D.
3
4
70. .xx
.
Li gii
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 14. Trong khai triển nhị thức:
6
21a
. Ba số hạng đầu là:
A.
6 5 4
2 6 15a a a
. B.
6 5 4
2 12 30a a a
.
C.
6 5 4
64 192 480a a a
. D.
6 5 4
64 192 240 .a a a
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 15. Trong khai triển nhị thức:
16
xy
. Hai số hạng cuối là:
A.
15 8
16 xy y
B.
4
16 xy
. C.
15 4
16xy y
. D.
8
15
2
16xy y
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 16. Trong khai triển nhị thức:
6
3
8
2
b
a



. Số hạng thứ
4
là:
A.
93
80 .ab
B.
93
64ab
C.
93
1280 .ab
D.
64
60 .ab
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 3. Nhị Thức NewTơn
85
Lớp Toán Thầy-Diệp Tn Tel: 0935.660.880
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 17. Khai triển nhị thức:
5
2xy
. Ta được kết quả là:
A.
5 4 3 2 2 3 4 5
32 16 8 4 2 .x x y x y x y xy y
B.
5 4 3 2 2 3 4 5
32 80 80 40 10 .x x y x y x y xy y
C.
5 4 3 2 2 3 4 5
2 10 20 20 10 .x x y x y x y xy y
D.
5 4 3 2 2 3 4 5
32 10000 80000 400 10 .x x y x y x y xy y
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 18. Trong khai triển nhị thức:
7
3 0,02
. Tìm tổng số ba số hạng đầu tiên
A.
2289,3283.
B.
2291,1012.
C.
2275,93801.
D.
2291,1141.
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
DNG 2. c định h s ca s hng cha
m
x
trong khai trin
n
pq
ax bx
vi
0x
(
,pq
là các hng s khác nhau).
1. Phương pháp.
Ta có:
00
nn
n n k k
p q k p q k n k k np pk qk
nn
kk
ax bx C ax bx C a b x


S hng cha
m
x
ng vi giá tr
k
tha:
np pk qk m
.
T đó tìm
m np
k
pq
Vy h s ca s hng cha
m
x
là:
.
k n k k
n
C a b
vi giá tr
k
đã tìm được trên.
Nếu
k
hoc
kn
thì trong khai trin không cha
m
x
, h s phi tìm bng 0.
2. Bài tp minh ha.
Bài tp 3. Tìm h s ca
7
x
trong khai trin biu thc sau
1).
10
( ) (1 2 )f x x
2).
9
( ) (2 3 )h x x x
3).
7 8 9
( ) (1 ) (1 ) (2 )g x x x x
4).
10
( ) (3 2 )f x x
5).
9
( ) (1 2 )h x x x
6).
8 9 10
( ) 8(1 ) 9(1 2 ) 10(1 3 )g x x x x
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 3. Nhị Thức NewTơn
86
Lớp Toán Thầy-Diệp Tn Tel: 0935.660.880
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Chú ý:
Với
0a
ta có:
1
n
n
a
a
với
n
.
Với
0a
ta có:
m
n
m
n
aa
với
, ; 1m n n
.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 4. Tìm s hng không cha
x
trong các khai trin sau
1).
12
2
( ) ( ) ( 0)f x x x
x
2).
3 17
4
3
2
1
( ) ( ) ( 0)g x x x
x
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 3. Nhị Thức NewTơn
87
Lớp Toán Thầy-Diệp Tn Tel: 0935.660.880
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 5. Tìm số hạng không chứa
x
trong các triển khai sau:
a).
15
2
1
x
x



b).
12
2
4
1
x
x



c).
12
2
2x
x



Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 6. Tìm hệ số của
101 99
xy
trong khai triển
200
23xy
.
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 3. Nhị Thức NewTơn
88
Lớp Toán Thầy-Diệp Tn Tel: 0935.660.880
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 7. Trong khai triển của nhị thức
2
2
n
x
x



cho biết tổng hệ số của 3 số hạng đầu tiên
trong khai triển trên bằng 97. Tìm hệ số của số hạng có chứa
4
.x
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 8.
1). Tìm h s ca s hng cha trong khai trin nh thức Niutơn của
biết
1
43
73
nn
nn
C C n

.
2). Xét khai trin
20
1
( ) (2 )f x x
x

a). Viết s hng th
1k
trong khai trin
b). S hng nào trong khai trin không cha
x
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
8
x
5
3
1
n
x
x



Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 3. Nhị Thức NewTơn
89
Lớp Toán Thầy-Diệp Tn Tel: 0935.660.880
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 9. Tìm h s không cha
x
trong các khai trin sau
3
2
()
n
x
x
,
biết rng
12
78
nn
nn
CC


vi
0x
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 10. Vi
n
s nguyên dương, gọi
33n
a
h s ca
33n
x
trong khai triển thành đa
thức ca
2
( 1) ( 2)
nn
xx
. Tìm
n
để
33
26
n
an
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 3. Nhị Thức NewTơn
90
Lớp Toán Thầy-Diệp Tn Tel: 0935.660.880
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Chú ý: Xác định h s ca s hng cha
m
x
trong khai trin
n
pq
P x a bx cx
đưc viết
i dng
2
0 1 2
...
n
n
a a x a x
. Ta làm như sau:
Viết
0
n
nk
p q k n k p q
n
k
P x a bx cx C a bx cx
;
Viết s hng tng quát khi khai trin các s hng dng
k
pq
bx cx
thành một đa thức theo
lu tha ca x.
T s hng tng quát ca hai khai triển trên ta tính được h s ca
m
x
.
Bài tp 11.
1). Tìm hệ số của
4
x
trong khai triển
10
2
1 2 3xx
2). Tìm hệ số của
8
x
trong khai triển
8
23
12xx
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 12. Tìm h s cu
8
x
trong khai triển đa thức
8
2
( ) 1 1f x x x


Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 3. Nhị Thức NewTơn
91
Lớp Toán Thầy-Diệp Tn Tel: 0935.660.880
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 13. Xác định h s ca
6
x
trong khai trin sau:
2 10
( ) (3 2 1)f x x x
.
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 14. Đa thức
10
2 20
0 1 20
1 3 2 ...P x x x a a x a x
. Tìm
15
a
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 3. Nhị Thức NewTơn
92
Lớp Toán Thầy-Diệp Tn Tel: 0935.660.880
3. Câu hi trc nghim.
u 19. Tìm hệ số của
12
x
trong khai triển
10
2
2.xx
A.
8
10
.C
B.
28
10
2.C
C.
2
10
.C
D.
28
10
2.C
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 20. Khai triển đa thức
2007
51P x x
ta được
2007 2006
2007 2006 10
... .P x a a ax x x a
Mệnh đề nào sau đây là đúng?
A.
77
2000 2007
..5Ca 
B.
77
2000 2007
..5Ca
C.
2
2000 2 7
2000 00
00
0
..5Ca 
D.
77
2000 2007
..5Ca
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 21. Tìm số hạng chứa
7
x
trong khai triển
13
1
.x
x



A.
47
13
.Cx
B.
3
13
.C
C.
37
13
.Cx
D.
37
13
.Cx
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 22. Tìm số hạng chứa
3
x
trong khai triển
9
1
.
2
x
x



A.
33
9
1
.
8
Cx
B.
33
9
1
.
8
Cx
C.
33
9
.Cx
D.
33
9
.Cx
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 23. Tìm số hạng chứa
31
x
trong khai triển
40
2
1
.x
x



A.
37 31
40
.Cx
B.
37 31
40
.Cx
C.
2 31
40
.Cx
D.
4 31
40
.Cx
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 3. Nhị Thức NewTơn
93
Lớp Toán Thầy-Diệp Tn Tel: 0935.660.880
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 24. Tìm số hạng không chứa
x
trong khai triển
6
2
2
.x
x



A.
42
6
2.C
B.
22
6
2.C
C.
44
6
2.C
D.
24
6
2.C
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 25. Tìm số hạng không chứa
x
trong khai triển
8
2
1
.xy
xy



A.
4
70 .y
B.
4
60 .y
C.
4
50 .y
D.
4
40 .y
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 26. Tìm số hạng chứa
3
xy
trong khai triển
5
1
.xy
y



A.
3
3.xy
B.
3
5.xy
C.
3
10 .xy
D.
3
4.xy
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 27. Tìm hệ số của
6
x
trong khai triển
31
3
1
n
x
x



với
0x
, biết
n
là số nguyên dương
thỏa mãn
22
12
34
nn
C nP A

.
A.
6
210 .x
B.
6
120 .x
C.
120.
D.
210.
Li gii.
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 3. Nhị Thức NewTơn
94
Lớp Toán Thầy-Diệp Tn Tel: 0935.660.880
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 28. Tìm hệ số của
9
x
trong khai triển
2
13
n
x
, biết
n
là số nguyên dương thỏa mãn
23
2 14 1
3
nn
C C n

.
A.
9
9
18
3.C
B.
9
99
18
3.Cx
C.
9
99
18
3.Cx
D.
9
9
18
3.C
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 29. Tìm số hạng không chứa
x
trong khai triển
2
3
3
2
n
x
x



với
0x
, biết
n
số nguyên
dương thỏa mãn
32
1
2
nn
C n A

.
A.
12 4 12
16
.2 .3 .C
B.
0 16
16
.2 .C
C.
12 4 12
16
.2 .3 .C
D.
16 0
16
.2 .C
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 30. Tìm hệ số của
7
x
trong khai triển
2
2
3
n
x
x



với
0x
, biết hệ số của số hạng thứ ba
trong khai triển bằng
1080.
A.
1080.
B.
810.
C.
810.
D.
1080.
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 3. Nhị Thức NewTơn
95
Lớp Toán Thầy-Diệp Tn Tel: 0935.660.880
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 31. Tìm số tự nhiên
n
, biết hệ số của số hạng thứ
3
theo số mũ giảm dần của
x
trong khai
triển
1
3
n
x



bằng
4.
A.
8.
B.
17.
C.
9.
D.
4.
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 32. Tính tổng
S
tất cả các hệ số trong khai triển
17
3 4 .x
A.
1.S
B.
1.S 
C.
0.S
D.
8192.S
Li gii.
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 33. Tìm hệ số của
5
x
trong khai triển
5 10
2
1 2 1 3 .P x x x x x
A.
80.
B.
3240.
C.
3320.
D.
259200.
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 34. Tìm hệ số chứa
10
x
trong khai triển
2
3
2
1
12
4
n
f x x x x



với
n
số tự nhiên
thỏa mãn hệ thức
32
14
n
nn
A C n

.
A.
5 10
19
2.C
B.
5 10 10
19
2.Cx
C.
9 10
19
2.C
D.
9 10 10
19
2.Cx
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 3. Nhị Thức NewTơn
96
Lớp Toán Thầy-Diệp Tn Tel: 0935.660.880
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 35. Tìm hệ số của
4
x
trong khai triển
3
13
n
P x x x
với
n
là số tự nhiên thỏa mãn hệ
thức
22
1
65
n
nn
C n A
.
A.
210.
B.
840.
C.
480.
D.
270.
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 36. Tìm hệ số của
10
x
trong khai triển
5
23
1 x x x
.
A.
5.
B.
50.
C.
101.
D.
105.
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 3. Nhị Thức NewTơn
97
Lớp Toán Thầy-Diệp Tn Tel: 0935.660.880
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 37. Tìm hệ số của
5
x
trong khai triển
28
1 2 1 ... 8 1 .P x x x x
A.
630.
B.
635.
C.
636.
D.
637.
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
DNG 3. Tìm h s ln nht ca khai trin.
1. Phương pháp.
Để xác định h s ln nht trong khai trin nh thức Niutơn
Ta làm như sau:
Tính h s
k
a
theo
k
n
;
Gii h bất phương trình
1
1
kk
kk
aa
aa
vi n s
k
;
H s ln nht phi tìm ng vi s t nhiên k ln nht tho mãn bất phương trình trên.
2. Bài tp minh ha.
i tp 15. Khai triển đa thức:
12
12P x x
thành dng:
2 3 12
0 1 2 3 12
...a a x a x a x a x
.
Tìm
1 2 12
max , ,...,a a a
.
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 3. Nhị Thức NewTơn
98
Lớp Toán Thầy-Diệp Tn Tel: 0935.660.880
Bài tp 16.Trong khai trin ca
10
12
33
x



thành đa thức:
2 3 10
0 1 2 3 10
...
k
a a x a x a x a x a
Hãy tìm h s
k
a
ln nht (
0 10k
).
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 17. Cho khai triển đa thức
12
12
0 1 12
1 2 ...P x x a a x a x
.
Tìm hệ số
k
a
0 12k
lớn nhất trong khai triển trên.
Li gii
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tập 18. Cho khai triển đa thức
10
9 10
0 1 9 10
12
...
33
P x x a a x a x a x



.
Tìm hệ số
k
a
0 10k
lớn nhất trong khai triển trên.
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 3. Nhị Thức NewTơn
99
Lớp Toán Thầy-Diệp Tn Tel: 0935.660.880
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 19. Cho
,xy
là các số thực dương và thỏa mãn
100
xy
. Tìm
x
để số hạng thứ 50 có
giá trị lớn nhất trong khai triển
100
xy
.
Li gii
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tập 20. Tìm
0;1;2; ;2005k 
sao cho
2005
k
C
đạt giá trị lớn nhất.
Li gii
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
i tp 21. Xét khai triển
2
0 1 2
2 ...
n
n
n
x a a x a x a x
. Tìm
n
để hệ số lớn nhất trong
trai triển là
10
a
.
Li gii
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 3. Nhị Thức NewTơn
100
Lớp Toán Thầy-Diệp Tn Tel: 0935.660.880
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
i tập 22. Giả sử
2
0 1 2
1 2 ...
n
n
n
P x x a a x a x a x
thỏa
12
12
0
2
... 2
2 2 2
n
n
a
aa
a
.
Tìm hệ số lớn nhất trong các hệ số
0 1 2
, , , ...,
n
a a a a
.
Li gii
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 23. Tìm số hạng chứa tích của các số mũ là lớn nhất trong khai triển
20
23
2x xy
.
Li gii
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
i tp 24. Khai triển thành đa thức
30
2 30
0 1 2
1 3 ...
n
x a a x a x a x
. Tìm hệ số lớn nhất
của các hệ số .
Li gii
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 3. Nhị Thức NewTơn
101
Lớp Toán Thầy-Diệp Tn Tel: 0935.660.880
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
3. Bài tp rèn luyn.
Bài 1.Xác định h s ca
8
x
trong các khai trin sau:
a). b).
8
3
2
( ) 5f x x
x




c).
12
3
()
2
x
fx
x




d).
2 10
( ) (1 2 )f x x x
e.
8 9 10
( ) 8(1 8 ) 9(1 9 ) 10(1 10 )f x x x x
Li gii
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài 2. Tìm h s ca s hng cha
26
x
trong khai trin nh thc Newton ca
7
4
1
n
x
x



,
biết
1 2 20
2 1 2 1 2 1
... 2 1
n
n n n
C C C
.
2 10
( ) (3 1)f x x
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 3. Nhị Thức NewTơn
102
Lớp Toán Thầy-Diệp Tn Tel: 0935.660.880
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài 3. Tìm h s ca
7
x
trong khai triển thành đa thức ca
2
(2 3 )
n
x
, biết n s nguyên
dương thỏa mãn :
1 3 5 2 1
2 1 2 1 2 1 2 1
... 1024
n
n n n n
C C C C
.
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài 4. Tìm h s ca
9
x
trong khai trin
9 10 14
( ) (1 ) (1 ) ... (1 )f x x x x
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài 5. Tìm h s ca
5
x
trong khai triển đa thc ca:
5 10
2
1 2 1 3x x x x
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 3. Nhị Thức NewTơn
10
3
Lớp Toán Thầy-Diệp Tn Tel: 0935.660.880
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài 6. Xác định s hng không ph thuc vào
x
khi khai trin biu thc
2
1
n
xx
x




vi
n là s nguyên dương thoả mãn
32
1
2
nn
C n A

.(
,
kk
nn
CA
tương ng là s t hp, s chnh hp
chp
k
ca
n
phn t).
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài 7. Tìm
n
biết:
1).
1 1 2 2 3 3
3 2 3 3 3 .. 256
n n n n
n n n n
C C C nC
2).
0 1 2
2 4 ... 2 243
nn
n n n n
C C C C
3).
1 2 2 3 2 1
2 1 2 1 2 1 2 1
2.2 3.2 ... (2 1)2 2005
nn
n n n n
C C C n C
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 3. Nhị Thức NewTơn
104
Lớp Toán Thầy-Diệp Tn Tel: 0935.660.880
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài 8. Khai trin
10
2 2 20
0 1 2 20
1 2 3 ...x x a a x a x a x
a). Hãy tính h s
4
a
b). Tính tng
20
1 2 3 20
2 4 ... 2S a a a a
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài 9. Tìm s hng ca khai trin
9
3
32
là mt s nguyên
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài 10. Gi s
2
0 1 2
(1 2 ) ...
nn
n
x a a x a x a x
, biết rng
01
... 729
n
a a a
.
Tìm
n
và s ln nht trong các s
01
, ,...,
n
a a a
.
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
4. Câu hi trc nghim.
u 38. Khai triển đa thức
12
12
0 1 12
1 2 ...P x x a a x a x
. Tìm hệ số
k
a
0 12k
lớn
nhất trong khai triển trên.
A.
88
12
2.C
B.
99
12
2.C
C.
10 10
12
2.C
D.
88
12
1 2 .C
Li gii.
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 3. Nhị Thức NewTơn
10
5
Lớp Toán Thầy-Diệp Tn Tel: 0935.660.880
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 39. Khai triển đa thức
10
9 10
0 1 9 10
12
...
33
P x x a a x a x a x



.
Tìm hệ số
k
a
0 10k
lớn nhất trong khai triển trên.
A.
7
7
10
10
2
1.
3
C
B.
7
7
10
10
2
.
3
C
C.
6
6
10
10
2
.
3
C
D.
8
8
10
10
2
.
3
C
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 40. Cho khai triển
2
0 1 2
1 2 ...
n
n
n
x a a x a x a x
, trong đó
*
n
và các hệ số thỏa
mãn hệ thức
1
0
... 4096.
22
n
n
a
a
a
Tìm hệ số lớn nhất ?
A.
1293600
. B.
126720
. C.
924
. D.
792
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 3. Nhị Thức NewTơn
106
Lớp Toán Thầy-Diệp Tn Tel: 0935.660.880
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
DNG 4. Bài toán liên quan đến tng
0
n
kk
kn
k
a C b
.
1. Phương pháp:
Da vào khai trin nh thc Newton
0 1 1 2 2 2 1 1
n
n n n n n n n
n n n n n
a b C a C a b C a b C ab C b
S mũ của biến
x
tăng dần
0 1 2 2 1 1
1
n
n n n n
n n n n n
x C C x C x C x C x

S ca biến
x
gim dn
0 1 1 2 2 1
1
n
n n n n n
n n n n n
x C x C x C x C x C
.
Sau đó chọn
,,a b x
các giá tr thích hp
Ta chn nhng giá tr
,ab
thích hợp thay vào đẳng thc trên.
Mt s kết qu ta thường hay s dng:
k n k
nn
CC
01
... 2
nn
n n n
C C C
0
( 1) 0
n
kk
n
k
C

2
2 2 1
2 2 2
0 0 0
1
2
n n n
k k k
n n n
k k k
C C C

0
(1 )
n
k k n
n
k
C a a

.
2. Bài tp minh ha.
Bài tp 25. Tính tổng
a).
0 1 2
...
n
n n n n
S C C C C
. b).
0 1 2 2
2 2 2 2
...
n
n n n n
S C C C C
.
Li gii
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 26. Tính tổng
0 1 2 2
3 3 ... 3
nn
n n n n
S C C C C
.
Li gii
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 3. Nhị Thức NewTơn
10
7
Lớp Toán Thầy-Diệp Tn Tel: 0935.660.880
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 27. Chứng minh rằng
1 3 2 1 0 2 2 2 1
2 2 2 2 2 2
... ... 2
n n n
n n n n n n
C C C C C C

.
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 28. Chứng minh rằng
0 2 2 4 4 2 2 2 1 2
2 2 2 2
3 3 ... 3 2 2 1
n n n n
n n n n
C C C C
.
Li gii
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 29. Chứng minh rằng
a).
2 2 2
01
2
...
nn
n n n n
C C C C
. b).
2 2 2
12
2
2 ...
2
nn
n n n n
n
C C n C C
.
Li gii
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 3. Nhị Thức NewTơn
108
Lớp Toán Thầy-Diệp Tn Tel: 0935.660.880
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 30. Tính tổng
a).
2014 0 2013 1 2012 2 2014
2014 2014 2014 2014
3 . 3 . 3 .S C C C C
.
b).
2015 0 2014 1 1 2013 2 2 2015 2015
2015 2015 2015 2015
3 3 .4. 3 .4 . 4 .S C C C C
.
c).
2016 1 0 2015 2 1 2014 3 2 1 2016 2015
2015 2015 2015 2015
4 .5. 4 .5 . 4 .5 . ... 4.5 .S C C C C
.
Li gii
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 31. Tính tổng
0 2015 1 2014 2015 2015 0
2016 2016 2016 2015 2016 2016 2016 1
... ...
kk
k
S C C C C C C C C
.
Li gii
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 3. Nhị Thức NewTơn
10
9
Lớp Toán Thầy-Diệp Tn Tel: 0935.660.880
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 32. Tính tổng
0 0 1 1 2 2 3 3 2010 2010
2010 2010 2010 2010 2010
2 2 2 2 2
...
1 2 3 4 2011
C C C C C
S
.
Li gii
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 33. Tìm s nguyên dương n sao cho:
0 1 2
2 4 ... 2 243
nn
n n n n
C C C C
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 34. Tính tng sau:
0 1 3 4
1 1 1 1 ( 1)
...
2 4 6 8 2( 1)
n
n
n n n n n
S C C C C C
n
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 35. Tính tng sau:
1 1 2 2 3 3
3 2 3 3 3 ...
n n n n
n n n n
S C C C nC
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 3. Nhị Thức NewTơn
110
Lớp Toán Thầy-Diệp Tn Tel: 0935.660.880
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 36. Chứng minh đẳng thc sau
1).
0 1 1 0
...
k k k k
m n m n m n m n
C C C C C C C
vi
, ,0 min ,m n k m n
2).
0 2 2 1 3 2 1
2 2 2 2 2 2
... ...
nn
n n n n n n
C C C C C C
3).
0 1 1 0
1
... 2
k k k k k
n n n n n n k n
C C C C C C C

vi
0 kn
.
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
C. Bài toánn luyn.
Bài tp 1. Chứng minh các đẳng thc sau:
0 2 2 1 3 2 1
2 2 2 2 2 2
... ...
nn
n n n n n n
C C C C C C
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 2. Chứng minh các đẳng thc sau:
0 1 1 0
...
k k k k
m n m n m n m n
C C C C C C C
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 3. Nhị Thức NewTơn
111
Lớp Toán Thầy-Diệp Tn Tel: 0935.660.880
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 3. Chng minh các đẳng thc sau:
2011
0 2 2 2010 2010
2011 2011 2011
31
2 ... 2
2
C C C
.
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 4. Tính các tng sau:
0 1 2
1
1 1 1
...
2 3 1
n
n n n n
S C C C C
n
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 5. Tính các tng sau:
12
2
2 ...
n
n n n
S C C nC
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 6. Tính các tng sau:
234
3
2.1. 3.2 4.3 ... ( 1)
n
n n n n
S C C C n n C
.
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 3. Nhị Thức NewTơn
112
Lớp Toán Thầy-Diệp Tn Tel: 0935.660.880
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 7. Tính tng
21
01
3 1 3 1
...
21
n
n
n n n
S C C C
n

Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 8. Tính tng
21
01
2 1 2 1
...
21
n
n
n n n
S C C C
n

Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 9.
Tìm s nguyên dương n sao cho :
1 2 2 3 2 1
2 1 2 1 2 1 2 1
2.2 3.2 ... (2 1)2 2005
nn
n n n n
C C C n C
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 10. Chng minh:
0 1 1 1 2 2 1 0 0 1
1.3 .5 2.3.5 ... .3 5 .8
n n n n n n
n n n
C C n C n
Li gii.
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 3. Nhị Thức NewTơn
113
Lớp Toán Thầy-Diệp Tn Tel: 0935.660.880
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 11. Tính tng
234
2.1 3.2 4.3 ... ( 1)
n
n n n n
S C C C n n C
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 12. Chng minh
2 2 2 2
0 1 2
2
...
nn
n n n n n
C C C C C
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 12. Tính các tng sau
1).
0 1 1 2 2 2 0
1
5 5 .3. 3 .5 ... 3
n n n n n n
n n n n
S C C C C
2).
0 2 2 2010 2010
2 2011 2011 2011
2 ... 2S C C C
3).
12
3
2 ...
n
n n n
S C C nC
4).
234
4
2.1. 3.2 4.3 ... ( 1)
n
n n n n
S C C C n n C
5).
21
01
5
3 1 3 1
...
21
n
n
n n n
S C C C
n

.
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 3. Nhị Thức NewTơn
114
Lớp Toán Thầy-Diệp Tn Tel: 0935.660.880
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 12.
Cho
*n
01
(1 ) ...
nn
n
x a a x a x
. Biết rng tn ti s nguyên
k
(
11kn
)sao cho
11
2 9 24
k k k
a a a


. Tính
?n
.
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Bài tp 13. Cho khai trin
01
(1 2 ) ...
nn
n
x a a x a x
, trong đó
*n
. Tìm s ln nht
trong các s
01
, ,...,
n
a a a
, biết các h s
01
, ,...,
n
a a a
tha mãn h thc:
1
0
... 4096
22
n
n
a
a
a
.
Li gii.
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 3. Nhị Thức NewTơn
115
Lớp Toán Thầy-Diệp Tn Tel: 0935.660.880
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
5. Câu hi trc nghim.
u 41. Khai triển đa thức
1000
21P x x
ta được
1000 9
9 10
99
1000 99
... .P x a a ax x x a
Mệnh đề nào sau đây là đúng?
A.
1000 99 19
... 2
n
a a a
. B.
1000 99 19
... 2 1
n
a a a
.
C.
1000 999 1
... 1a a a
. D.
1000 999 1
... 0a a a
.
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 42. Mệnh đề nào sau đây là đúng?
A.
0 1 1 2 2
2 2 2 2 2 2
... ... .
n n n n
n n n n n n
C C C C C C

B.
0 1 1 1 2 2
2 2 2 2 2 2
... ... .
n n n n
n n n n n n
C C C C C C
C.
0 1 2 1 2 2
2 2 2 2 2 2
... ... .
n n n n
n n n n n n
C C C C C C
D.
0 1 1 1 2 2
2 2 2 2 2 2
... ... .
n n n n
n n n n n n
C C C C C C
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 3. Nhị Thức NewTơn
116
Lớp Toán Thầy-Diệp Tn Tel: 0935.660.880
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 43. Tính tổng
0 1 2
...
n
n n n n
S C C C C
.
A.
2 1.
n
S 
B.
2.
n
S
C.
1
2.
n
S
D.
2 1.
n
S 
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 44. Tính tổng
0 1 2 2
2 2 2 2
...
n
n n n n
S C C C C
.
A.
2
2.
n
S
B.
2
2 1.
n
S 
C.
2.
n
S
D.
2
2 1.
n
S 
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 45. Tìm số nguyên dương
n
thỏa mãn
1 2 20
2 1 2 1 2 1
... 2 1
n
n n n
C C C
.
A.
8.n
B.
9.n
C.
10.n
D.
11.n
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 45. Tìm số nguyên dương
n
thỏa mãn
1 3 2 1
2 1 2 1 2 1
... 1024
n
n n n
C C C
.
A.
5.n
B.
9.n
C.
10.n
D.
4.n
Li gii.
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 3. Nhị Thức NewTơn
117
Lớp Toán Thầy-Diệp Tn Tel: 0935.660.880
u 47. Tính tổng
0 1 2 3
3 3 ... 3
nn
n n n n
S C C C C
.
A.
3.
n
S
B.
2.
n
S
C.
3.2 .
n
S
D.
4.
n
S
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 48. Tổng
1 2 3 2016
2016 2016 2016 2016
...C C C C
bằng:
A.
2016
2
. B.
2016
21
. C.
2016
21
. D.
2016
4
.
Li gii
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 49. Khai triển
5
xy
rồi thay
,xy
bởi các giá trị thích hợp. Tính tổng
0 1 5
5 5 5
...S C C C
A.
32
. B.
64
. C.
1
. D.
12
.
Li gii
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 50. Tổng
0 1 2 3
. ..
n
n n n n n
T C C C C C
bằng:
A.
2
n
T
. B.
2 1
n
T
. C.
2 1
n
T 
. D.
4
n
T
.
Li gii
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 51. Tính giá trị của tổng
0 1 6
6 6 6
.. S C C C 
bằng:
A.
64
. B.
48
. C.
72
. D.
100
.
Li gii
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 52. Tổng số
0 1 2
... 1
n
n
n n n n
C C C C
có giá trị bằng:
A.
0
nếu
n
chẵn. B.
0
nếu
n
lẻ.
C.
0
nếu
n
hữu hạn. D.
0
trong mọi trường hợp.
Li gii
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 3. Nhị Thức NewTơn
118
Lớp Toán Thầy-Diệp Tn Tel: 0935.660.880
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 53. Giá trị của tổng
1 2 7
7 7 7
.....A C C C
bằng
A.
255
. B.
. C.
127
. D.
31
.
Li gii
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 54. Cho
0 1 2 2
5 5 ... 5 .
nn
n n n n
A C C C C
Vậy
A
bằng
A.
7
n
. B.
5
n
. C.
6
n
. D.
4
n
.
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 55. Trong khai triển
100
100
0 1 100
2 ... .x a a x a x
Hệ số
97
a
A.
1293600
. B.
1293600
. C.
3 97
100
2.C
. D.
98 98
100
2.C
.
Li gii.
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 56. Tìm hệ số chứa
9
x
trong khai triển
9 10 11 12 13 14 15
(1 ) (1 ) (1 ) (1 ) (1 ) (1 ) (1 )x x x x x x x
.
A.
3000.
B.
8008.
C.
3003.
D.
8000.
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 3. Nhị Thức NewTơn
11
9
Lớp Toán Thầy-Diệp Tn Tel: 0935.660.880
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 57. Nếu khai triển nhị thức Niutơn:
5 4 3 2
5 4 3 0
5
21
1 a x a x ax x a x a x a
.
thì tổng
5 4 3 2 1 0
a a a a a a
bằng
A.
32.
B.
0.
C.
1.
D.
.
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 58. Tổng
0 1 2 3
...
n
n n n n n
T C C C C C
bằng
A.
2.
n
T
B.
4.
n
T
C.
2 1.
n
T 
D.
2 1.
n
T 
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 59.
0 2 4 2
2 2 2 2
.....
n
n n n n
C C C C
bằng
A.
2
2.
n
B.
1
2.
n
C.
22
2.
n
D.
21
2.
n
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 60. Khai trin
5
xy
ri thay
,xy
bi các giá tr thích hp. Tính tng
0 1 5
5 5 5
...S C C C
A.
32
. B.
64
. C.
1
. D.
12
.
Li gii
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 61. Tng
0 1 2 3
. ..
n
n n n n n
T C C C C C
bng:
A.
2
n
T
. B.
2 1
n
T
. C.
2 1
n
T 
. D.
4
n
T
.
Li gii
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 3. Nhị Thức NewTơn
120
Lớp Toán Thầy-Diệp Tn Tel: 0935.660.880
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 62. Nếu khai trin nh thức Niutơn:
5 4 3 2
5 4 3 0
5
21
1 a x a x ax x a x a x a
.
thì tng
5 4 3 2 1 0
a a a a a a
bng
A.
32.
B.
0.
C.
1.
D.
.
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 63. Tng
1 2 3 2016
2016 2016 2016 2016
...C C C C
bng:
A.
2016
2
. B.
2016
21
. C.
2016
21
. D.
2016
4
.
Li gii
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 64. Tng s
0 1 2
... 1
n
n
n n n n
C C C C
có giá tr bng:
A.
0
nếu
n
chn. B.
0
nếu
n
l.
C.
0
nếu
n
hu hn. D.
0
trong mọi trường hp.
Li gii
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 65. Giá tr ca tng
1 2 7
7 7 7
.....A C C C
bng
A.
255
. B.
. C.
127
. D.
31
.
Li gii
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 66. Tng
0 1 2 3
...
n
n n n n n
T C C C C C
bng
A.
2.
n
T
B.
4.
n
T
C.
2 1.
n
T 
D.
2 1.
n
T 
Li gii.
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 3. Nhị Thức NewTơn
121
Lớp Toán Thầy-Diệp Tn Tel: 0935.660.880
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 67. Tng tt c các h s ca khai trin
20
xy
bng bao nhiêu.
A.
77520
. B.
1860480
. C.
1048576
D.
81920
.
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 68.
0 2 4 2
2 2 2 2
.....
n
n n n n
C C C C
bng
A.
2
2.
n
B.
1
2.
n
C.
22
2.
n
D.
21
2.
n
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 69. Cho
0 1 2 2
5 5 ... 5 .
nn
n n n n
A C C C C
Vy
A
bng
A.
7
n
. B.
5
n
. C.
6
n
. D.
4
n
.
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 70. Trong khai trin
100
100
0 1 100
2 ... .x a a x a x
H s
97
a
A.
1293600
. B.
1293600
. C.
3 97
100
2.C
. D.
98 98
100
2.C
.
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 71. Tìm h s cha
9
x
trong khai trin
9 10 11 12 13 14 15
(1 ) (1 ) (1 ) (1 ) (1 ) (1 ) (1 )x x x x x x x
.
A.
3000.
B.
8008.
C.
3003.
D.
8000.
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 3. Nhị Thức NewTơn
122
Lớp Toán Thầy-Diệp Tn Tel: 0935.660.880
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 72. Trong khai trin
(1 )
n
x
biết tng các h s
1 2 3 1
..... 126
n
n n n n
C C C C
. H s ca
3
x
bng
A.
15.
B.
21.
C.
35.
D.
20.
Li gii.
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
u 73. Tng các h s nh thc Niu-tơn trong khai triển
3
1
n
x
bng
64
. S hng không cha
x
trong khai trin
3
2
1
2
2
n
nx
nx



là:
A.
360
. B.
210
. C.
250
. D.
240
.
Li gii
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
123
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
A L THUY󰈸T
I. PHÉP TH VÀ BI󰈸N C.
1. Phép th ngu nhiên không gian mu
a). Phép th ngu nhiên (gi tt là phép th) là mt thí nghim hay một hành động mà :
Kết quả của nó không đoán trước được.
Có thể xác định được tập hợp tất cả các kết quả có thể xảy ra của phép thử đó.
Phép thử thường được kí hiệu bởi chữ
T
.
d 1. Tung một đồng xu bt k ta có th biết:
Kết qu có th là mt sp hoc nga.
Nhưng không biết được là mt nào.
b). Không gian mu:
tập hợp tất cả các kết quả có thể xảy ra của phép thử đó được gọi không gian mẫu của phép
thử đó.
Kí hiu bi ch
c là ô--ga).
d 2. Tung mt con súc sc bt k ta có th biết :
S kết qu ca phép th là mt
1
chm,
2
chm,
3
chm,
4
chm,
5
chm,
6
chm.
S kết qu đó là một không gian mu
1;2;3;4;5;6
.
2. Biến c
Biến c
A
liên quan đến phép th
T
là biến c mà vic xy ra hay không xy ra ca
A
tùy thuc
vào kết qu ca
T
.
Mi kết qu ca phép th
T
làm cho
A
xảy ra, được gi là kết qu thun li cho
A
.
Tập hơp các kết qu thun li cho
A
đưc kí hiu là
A
hoc
()nA
.
Vi mi phép th
T
có mt biến c luôn xy ra, gi là biến c chc chn.
Vi mi phép th
T
có mt biến c không bao gi xy ra, gi là biến c không th. Kí hiu
.
d 3. Gieo một đồng tiền cân đối đồng cht ba ln và quan sát s xut hin ca mt sp
S
,
mt nga
N
.
a). Xây dng không gian mu.
b). Xác định các biến c:
A
: "Lần gieo đầu tiên xut hin mt sp".
B
: "Ba ln xut hin các mặt như nhau".
C
: "Đúng hai lần xut hin mt sp".
D
: "Ít nht mt ln xut hin mt sp".
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
d 4. Gieo một đồng tin liên tiếp cho đến khi lần đầu tiên xut hin mt sp
S
, hoc c
bn ln nga
N
thì dng li.
a). Mô t không gian mu.
b). Xác định các biến c:
A
: "S lần gieo không vượt quá ba".
B
: "S ln gieo là bn".
§BI 4. XÁC SUT-CÁC QUY TC TÍNHC SUT
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
124
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
3. Tính cht
Gi s là không gian mu,
A
B
là các biến c.
\ AA
đưc gi là biến c đối ca biến c
A
.
AB
là biến c xy ra khi và ch khi
A
hoc
B
xy ra.
AB
là biến c xy ra khi và ch khi
A
B
cùng xy ra.
AB
còn được viết là
AB
.
Nếu
AB 
, ta nói
A
B
xung khc.
II. C SUT CA BI󰈸N C.
1. Đnh nghĩa c đin ca c sut:
Cho
T
là mt phép th ngu nhiên vi không gian mu
là mt tp hu hn.
Gi s
A
là mt biến c đưc mô ta bng
A
.
Xác sut ca biến c
A
, kí hiu bi
PA
, được cho bi công thc
nA
PA
n
.
nA
là s phn t ca
A
hay s kết qu thun li cho biến c
A
.
n
là số các kết quả có thể xảy ra của phép thử(
Không gian mẫu
).
Chú ý:
Xác sut ca biến c
A
ch ph thuc vào s kết qu thun li cho
A
, nên ta đồng nht
A
vi
A
nên ta có :
()
()
()
nA
PA
n
( ) 1, ( ) 0, 0 ( ) 1P P P A
d 5. Gieo hai đồng xu cân đối một cách độc lp. Tính xác suất để :
a). C hai đồng xu đu sp.
b). Có ít nht một đồng xu sp.
c). Có đúng một đồng xu nga.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
d 6. Gọi
A
tập hợp các số tự nhiên
5
chữ số khác nhau được thành lập từ các chữ số
0,1,2,3,4,5,6
. Chọn ngẫu nhiên một phần tử của tập
A
. Tìm xác suất để phần tử đó một số
không chia hết cho 5.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
125
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
d 7. Mt đoàn tàu gồm ba toa đỗ sân ga. 5 hành khách lên tàu. Mỗi hành khách độc lp
vi nhau. Chn ngu nhiên mt toa. Tìm xác suất để mi toa có ít nhất 1 hành khách bước lên tàu.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
2. Đnh nghĩa thng ca xác sut.
Xét phép th ngu nhiên T và mt biến c A liên quan ti phép th đó.
Nếu tiến hành lặp đi lặp li N ln phép th T và thng kê s ln xut hin ca A
Khi đó xác suất ca biến c A được định nghĩa như sau:
lÇn xuÊt hiÖn cña biÕn A
PA
phÇn cña kh«nggian mÉu
B-PHÂN DNG D MINH HA.
DẠNG 1. c định không gian mẫu biến cố.
1. Phương pháp:
Để xác định không gian mu và biến c ta thường s dng các cách sau
Cách 1: Lit kê các phn t ca không gian mu và biến c rồi chúng ta đếm.
Cách 2:S dng các quy tắc đếm để xác định s phn t ca không gian mu và biến c.
2. Bài tp minh ha.
Bài tp 1. Trong mt chiếc hộp đựng 6 viên bi đỏ, 8 viên bi xanh, 10 viên bi trng.
Ly ngu nhiên 4 viên bi. Tính s phn t ca:
1). Không gian mu
2). Các biến c:
A
: “ 4 viên bi lấy ra có đúng hai viên bi màu trắng”
B
: “ 4 viên bi lấy ra có ít nht một viên bi màu đỏ”
C
: “ 4 viên bi lấy ra có đủ 3 màu”
Li gii.
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
126
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 2. Xét phép th tung con súc sc 6 mt hai ln. Tính s phn t ca:
1). Không gian mu.
2). Các biến c:
A
:“ số chm xut hin c hai ln tung giống nhau”
B
:“ Tổng s chm xut hin hai ln tung chia hết cho
3
C
: “ Số chm xut hin ln mt lớn hơn số chm xut hin lần hai”.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 3. Gieo một đồng tin
5
lần. Xác định và tính s phn t ca
1). Không gian mu
2). Các biến c:
A
: “ Lần đầu tiên xut hin mt nga”
B
: “ Mặt sp xut hin ít nht mt ln”
C
: “ Số ln mt sp xut hin nhiều hơn mặt nga”
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
127
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
Bài tp 4. Có 100 tm th được đánh số t 1 đến 100. Ly ngu nhiên 5 th.
Tính s phn t ca:
1). Không gian mu
2). Các biến c:
A
: “ Số ghi trên các tm th đưc chn là s chn”
B
: “ Có ít nhất mt s ghi trên th đưc chn chia hết cho 3”.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 5. Tung một đồng tin hai ln. Tìm xác suất để hai lần tung đó
1). Đu là mt
S
. 2). Mt
S
mt
N
.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 6. Tung một đồng tin ba ln
1). Mô t không gian mu
2). Xác đnh các biến c sau và tính xác sut các biến c đó
A: “ Có ít nhất mt ln xut hin mt
S
B: “ Mặt
N
xut hin ít nht hai ln”
C: “ Lần th hai xut hin mt
S
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 7. Gieo mt con xúc sắc đồng chất cân đối ba ln liên tiếp. Tìm xác sut ca các biến
c sau:
A: “ Tổng s chm xut hin trong ba lần là 10”
B: “Có ít nhất mt mt chn xut hiện”.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
128
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 8. Trong mt lp hc gm 15 hc sinh nam và 10 hc sinh n. Giáo viên gi ngu nhiên
4 hc sinh lên gii bài tp. Tính xác suất để 4 học sinh được gọi đó có cả nam và n?
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
DNG 2. Tính c sut theo định nghĩa c đin.
1. Phương pháp:
Tính xác sut theo thng kê ta s dng công thc:
lÇn xuÊt hiÖn cña biÕn A
PA
phÇn cña kh«nggian mÉu
.
Tính xác sut ca biến c theo định nghĩa cổ điển ta s dng công thc :
()
()
()
nA
PA
n
.
2. Bài tp minh ha .
Nhóm bài 1: Chn i -K-Rút th-Gieo súc sc.
Bài tp 9. B bài tú-lơ khơ 52 quân bài. Rút ngu nhiên ra 4 quân bài. Tìm xác sut ca các
biến c:
A
: “Rút ra được t quý K ‘’
B
: “4 quân bài rút ra có ít nhất một con Át”
C
: “4 quân bài lấy ra có ít nhất hai quân bích’’
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 10. Chn ngu nhiên 5 quân bài trong c bài tú lơ khơ .Tính xác suất để trong sp bài
cha hai b đôi ( hai con cùng thuộc 1 b , hai con thuc b th 2,con th 5 thuc b khác)
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
129
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
i tp 11. Chn ngu nhiên 5 quân bài .Tính xác suất để trong sp bài 5 quân lp thành b
liên tiếp tc b (A,2-3-4-5) (2-3-4-5-6) ….(10 J-Q-K-A). Quân A va quân nht va
quân ln nht.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 12. Mt hộp đựng 9 th được đánh từ 1,2,3…9 .Rút ngẫu nhiên 5 th. Tính xác suất để
1). các th ghi s 1,2,3
2). Có đúng 1 trong ba thẻ ghi 1,2,3 được rút
3). Không có th nào trong ba th đưc rút
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 13. Chon ngu nhiên 3 s t tp
1). Tính xác suất để tng ba s đưc chn là 12.
2). Tính xác suất để tng ba s đựợc chn là s l.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 14. Chn ngu nhiên 3 s trong 80 s t nhiên 1,2,3, . . . ,80
1). Tính xác sut ca biến c A : “trong 3 số đó có và chỉ có 2 s là bi s của 5”
2). Tính xác sut ca biến c B : “trong 3 số đó có ít nhất mt s chính phương”
Li gii.
1,2,....,10,11
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
130
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
3. Câu hi trc nghim:
u 1.(THPT Chuyên Quốc Học-Huế 2018) Gieo một con súc sắc cân đối đồng chất một lần. Tính
xác suất để xuất hiện mặt có số chấm là một số nguyên tố.
A.
1
4
. B.
1
2
. C.
2
3
. D.
1
3
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 2.(Chuyên Đại Học Vinh)Gieo đồng thời hai con súc sắc cân đối và đồng chất.
Xác suất để tổng số chấm trên mặt xuất hiện của hai con súc sắc đó không vượt quá
5
bằng
A.
5
12
. B.
1
4
. C.
2
9
. D.
5
18
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 3.(THPT Đức THọ- Tĩnh 2018) Gieo một con xúc xắc cân đối đồng chất
2
lần,nh xác suất
để biến cố có tổng
2
lần số chấm khi gieo xúc xắc là một số chẵn.
A.
0,25.
B.
0,75.
C.
0,85.
D.
0,5.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
131
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
u 4.(Chuyên Bc Ninh-2018) Gieo ngu nhiên
2
con xúc sắc cân đối đồng cht. Tìm xác sut
ca biến cố: “ Hiệu s chm xut hin trên
2
con xúc sc bng
1
”.
A.
2
9
. B.
1
9
. C.
5
18
. D.
5
6
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 5.(THPT Hoàn Thanh Hóa 2018)
tm th đánh số t
1
đến
. Chn ngu nhiên ra
10
tm th. Tìm xác suất để
5
tm th mang s l
5
tm th mang s chẵn trong đó chỉ
đúng một tm th chia hết cho
10
.
A.
99
667
. B.
98
667
. C.
97
667
. D.
96
667
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 6.(THPT Chuyên Hà Tĩnh)Một hộp đựng
9
th được đánh số
1
,
2
,
3
,
4
, ,
9
.
Rút ngẫu nhiên đồng thi
2
th nhân hai s ghi trên hai th li vi nhau. Tính xác suất đểch
nhận được là s chn.
A.
1
6
. B.
5
18
. C.
8
9
. D.
13
18
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 7.(Chuyên H Long )
10
th được đánh số
1
,
2
,…,
10
. Bc ngu nhiên
2
th.
Tính xác suất để tích
2
s ghi trên
2
th bốc được là mt s l.
A.
1
2
. B.
7
9
. C.
5
18
. D.
2
9
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
132
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
u 8.(THPT Chuyên Quý Đôn) Thầy Bình đặt lên bàn
tm th đánh số t
1
đến
.
Bn An chn ngu nhiên
10
tm th. Tính xác suất để trong
10
tm th ly ra
5
tm th mang
s l,
5
tm mang s chẵn trong đó ch có mt tm th mang s chia hết cho
10
.
A.
99
667
. B.
. C.
. D.
99
167
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 9.(SGD Rịa Vũng Tàu)
11
chiếc th đưc đánh số t
1
đến
11
, ngưi ta rút ngu nhiên
hai th khác nhau. Xác suất để rút được hai th mà tích hai s được đánh trên thẻ là s chn bng
A.
. B.
. C.
. D.
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 10.(Chuyên Hùng Vương 2018) Một hộp đựng
11
tấm thẻ được đánh số từ
1
đến
11
. Chọn
ngẫu nhiên
4
tấm thẻ từ hộp. Gọi
P
xác suất để tổng số ghi trên
4
tấm thẻ ấy là một số lẻ. Khi
đó
P
bằng
A.
16
33
. B.
1
2
. C.
. D.
10
33
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 11.(Chuyên KHTN-2018) Mt hp cha
th được đánh số t
1
đến
. Người ta ly ngu
nhiên mt th t hộp đó. Tính xác suất để th lấy được mang s l và không chia hết cho
3
.
A.
2
5
. B.
3
10
. C.
1
3
. D.
4
15
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
133
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
u 12.(THPT Kim Liên- Ni 2018) Mt hp cha
20
th được đánh số t
1
đến
20
.Ly ngu
nhiên
1
th t hộp đó. Tính xác suất th lấy được ghi s l và chia hết cho
3
.
A.
0,3
. B.
0,5
. C.
0,2
. D.
0,15
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Nhómi toán 2: Chn Bi
Bài tp 15. Trong mt chiếc hộp có 20 viên bi, trong đó có 8 viên bi màu đỏ, 7 viên bi màu
xanh và 5 viên bi màu vàng. Ly ngu nhiên ra 3 viên bi. Tìm xác suất để:
1). 3 viên bi lấy ra đều màu đỏ 2). 3 viên bi ly ra có không quá hai màu.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 16. Một bình đựng 16 viên bi ,7 viên bi trắng ,6 viên bi đen,3 viên bi đỏ.
1). Ly ngu nhiên ba viên bi .Tính xác sut ca các biến c :
A: “Lấy được 3 viên đỏ
B: “ Lấy c ba viên bi không có bi đỏ
C: “ Lấy được 1 bi trắng ,1 bi đen ,1 bi đỏ”
2). Ly ngu nhiên 4 viên bi .Tình xác sut ca các biến c
X: “Lấy đúng 1 viên bi trng
Y: “ Lấy đúng 2 viên bi trắng”
3). Ly ngu nhiên 10 viên bi .
Tính xác sut ca biến c D: “lấy được 5 viên bi trắng , 3 bi đen, 2 bi đỏ”.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
134
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 17. Trong mt chiếc hp có 7 viên bi trắng, 8 viên bi đỏ và 10 viên bi vàng. Ly ngu
nhiên ra 6 viên bi
1). Tính s phn t ca không gian mu
2). Tính xác sut ca các biến c sau
` A: “ 6 viên bi lấy ra cùng một màu”
B: “ có ít nhất mt viên bi màu vàng”
C: “ 6 viên bi lấy ra có đủ ba màu”
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
4. Câu hi trc nghim:
u 13.(THPT Hồng Lĩnh- Tĩnh 2018)Một hộp đựng
10
viên bi kích thước khá nhau, trong
đó
7
viên bi màu đỏ
3
viên b màu xanh. Chọn ngẫu nhiên
2
viên. Xác suất để
2
viên bi
được chọn có ít nhất một viên bi màu xanh bằng
A.
1
15
. B.
2
15
. C.
7
15
. D.
8
15
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 14.(THPT Đặng Thúc Ha 2018) Mt hộp đựng
5
viên bi đỏ,
4
viên bi xanh. Ly ngu nhiên
3
viên bi t hộp đó. Tính xác suất lấy được ít nht
1
viên đỏ.
A.
37
42
. B.
1
21
. C.
5
42
. D.
20
21
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
135
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 15.(THPT Hoàn-Thanh Hóa-2018)Một túi đựng
6
bi xanh và
4
bi đỏ. Lấy ngẫu nhiên
2
bi.
Xác suất để cả hai bi đều đỏ là.
A.
7
15
. B.
7
45
. C.
8
15
. D.
2
15
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 16.(THPT Chuyên ĐH Vinh 2018)Lấy ngẫu nhiên hai viên bi từ một thùng gồm
4
bi xanh,
5
bi đỏ và
6
bi vàng. Tính xác suất để lấy được hai viên bi khác màu?
A.
67,6%.
B.
29,5%.
C.
32,4%.
D.
70,5%.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 17.(THPT Chuyên Trần Phú-2018) Trong một chiếc hộp
20
viên bi, trong đó
9
viên bi
màu đỏ,
6
viên bi màu xanh
5
viên bi màu vàng. Lấy ngẫu nhiên đồng thời
3
viên bi. Tìm xác
suất để
3
viên bi lấy ra có không quá
2
màu.
A.
9
38
. B.
29
38
. C.
82
95
. D.
183
190
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 18.(THPT Chuyên ĐHSP- Ni 2018) Mt hộp đựng
7
qu cu màu trng và
3
qu cu màu
đỏ. Ly ngu nhiên t hp ra
4
qu cu. Tính xác suất để trong
4
qu cầu lấy được đúng
2
qu cầu đỏ.
A.
21
71
. B.
20
71
. C.
62
211
. D.
21
70
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
136
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Câu
19.
(THPT Chuyên Vĩnh Pc-2018) Một hộp
5
bi đen,
4
bi trắng. Chọn ngẫu nhiên
2
bi.
Xác suất
2
bi được chọn cùng màu là:
A.
1
4
. B.
4
9
. C.
1
9
. D.
5
9
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 20. (THPT Phan Đăng u-Huế-2018) Một hộp chứa viên bi xanh và viên bi đỏ.
Lấy ngẫu nhiên bi. Tính xác suất để bi lấy được có đủ hai màu.
A. . B. . C. . D. .
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 21.(THPT Phan Châu Trinh-2018) Mt hp
5
viên bi xanh,
6
viên bi đỏ
7
viên bi vàng.
Chn ngu nhiên
5
viên bi trong hp, tính xác sut để
5
viên bi được chọn có đủ ba màu s bi
đỏ bng s bi vàng.
A.
313
408
. B.
95
408
. C.
5
102
. D.
25
136
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 22.(S GD ĐT Hà Nam-2018) Mt chiếc hp cha
9
qu cu gm
4
qu màu xanh,
3
qu
màu đỏ
2
qu màu vàng.Ly ngu nhiên
3
qu cu t hộp đó. Xác suất để trong
3
qu cu ly
đưc có ít nht
1
qu màu đỏ bng:
A.
1
3
B.
19
28
C.
16
21
D.
17
42
Li gii
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
20
15
4
4
4610
5236
4615
5236
4651
5236
4615
5236
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
137
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 23.(S GD-ĐT Phú Th-2018) Mt hp cha
12
qu cu gm
5
qu cu màu xanh
7
qu
cầu màu đỏ. Chn ngu nhiên lần lượt hai qu cu t hộp đó. Xác suất để hai qu cu cùng màu
bng
A.
31
66
. B.
31
33
. C.
25
66
. D.
25
33
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 24. (S GD-ĐT Gia Lai 2018) Mt hp cha
15
qu cu gm
7
qu cu màu đỏ
8
qu cu
màu xanh. Chn ngẫu nhiên đồng thi hai qu cu t hộp đó. Tính xác suất để chọn được hai qu
cu cùng màu.
A.
6
13
. B.
1
7
. C.
7
15
. D.
7
30
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 25.(S GD -ĐT Hu Giang 2018)Mt hp cha
11
qu cầu trong đó có
5
qu màu xanh
6
qu đỏ. Ly ngu nhiên lần lượt
2
qu cu t hộp đó. Tính xác suất để
2
lần đều lấy được qu
màu xanh.
A.
9
55
. B.
. C.
. D.
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 26. tham khảo BGD 2018) Một hộp chứa
11
quả cầu gồm
5
quả cầu màu xanh
6
quả
cầu màu đỏ. Chọn ngẫu nhiên đồng thời
2
quả cầu từ hộp đó. Xác suất để chọn ra
2
quả cầu cùng
màu bằng
A.
5
22
. B.
. C.
. D.
.
Li gii
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
138
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 27.(THPT Hồng Quang-2018) Trong một hộp đựng
7
bi màu đỏ,
5
bi màu xanh và
3
bi vàng,
lấy ngẫu nhiên
3
viên bi. Tính xác suất để
3
viên bi lấy được đều có màu đỏ.
A.
1
13
. B.
3
7
. C.
1
5
. D.
7
15
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 28.(THPT Chuyên ĐHSP- Ni 2018) Mt hộp đựng
7
qu cu màu trng và
3
qu cu màu
đỏ. Ly ngu nhiên t hp ra
4
qu cu. Tính xác suất để trong
4
quả cu lấy được đúng
2
qu cầu đỏ.
A.
21
71
. B.
20
71
. C.
62
211
. D.
21
70
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 29.(THPT Lê Xoay-Vĩnh phúc) Mt hp cha
7
qu cu xanh,
5
qu cu vàng.
Chn ngu nhiên
3
qu. Xác suất để
3
qu được chn có ít nht
2
qu xanh là
A.
7
44
. B.
. C.
. D.
21
220
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
139
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
u 30.(Chuyên Thái Bình Ln3)Một hộp đựng 7 viên bi đỏ đánh số từ 1 đến 7 6 viên bi xanh
đánh số từ 1 đến 6. Hỏi bao nhiêu cách chọn hai viên bi từ hộp đó sao cho chúng khác màu
khác số?
A.
36
. B.
42
. C.
49
. D.
30
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 31.(THPT Chuyên Nguyễn Du 2019) Trong một hộp 3 bi đỏ, 5 bi xanh 7 bi vàng. Bốc
ngẫu nhiên 4 viên. Xác suất để bốc được đủ 3 màu là
A.
8
13
. B.
6
13
. C.
7
13
. D.
5
13
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 32.(Sở GD và ĐT Hưng Yên 2019) Một hộp đựng
15
quả cầu trong đó có
6
quả màu đỏ,
5
quả
màu xanh,
4
quả màu vàng. Lấy ngẫu nhiên
6
quả cầu trong
15
quả cầu đó. Tính xác suất để
6
quả lấy được có đủ ba màu.
A.
757
5005
. B.
4248
5005
. C.
607
715
. D.
850
1001
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Nhómi toán 3. Chn u trc nghim
Bài tp 18. Ngân hàng đề thi gm 100 câu hi, mỗi đề thi có 5 câu. Mt hc sinh hc thuc 80
câu. Tính xác suất để học sinh đó rút ngẫu nhiên được một đề thi có 4 câu hc thuc.
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
140
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 31.(S GD-ĐT Bắc Ninh-2018) Đề kim tra
15
phút
10
câu trc nghim mi câu bn
phương án trả lời, trong đó có một phương án đúng, trả lời đúng được
1,0
đim. Mt thí sinh làm
c
10
câu, mi câu chn một phương án. Tính xác suất để thí sinh đó đạt t
8,0
tr lên.
A.
10
436
4
. B.
10
463
4
. C.
4
436
10
. D.
4
463
10
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 32.(THTT S 2-485-2018) Thy giáo 10 câu hi trc nghiệm, trong đó
6
câu đại s
4
câu hình hc. Thy gi bn Nam lên tr bài bng cách chn ly ngu nhiên
3
câu hi trong
10
câu
hỏi trên để tr li. Hi xác sut bn Nam chn ít nht có mt câu hình hc là bng bao nhiêu?
A.
5
6
. B.
1
30
. C.
1
6
. D.
29
30
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 33.(THPT Tam Phưc 2018) Một ngân hàng đề thi 50 câu hỏi khác nhau, trong đó 40%
câu hi mức đ nhn biết, 20% câu hi mức độ thông hiu, 30% câu hi mức độ vn dng
và 10% câu hi mức độ vn dng cao. Xây dựng 1 đề thi trc nghim gm 50 câu hi khác nhau
t ngân hàng đề thi đó bằng cách sp xếp ngu nhiên các câu hi. Tính xác suất để xây dựng được
1 đề thi các câu hỏi được sp xếp theo mức độ khó tăng dần:
nhn biết thông hiu vn
dng vn dng cao. (chn giá tr gần đúng nhất)
A.
26
4,56.10
. B.
29
5,46.10
. C.
26
5,46.10
. D.
29
4,56.10
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
141
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 34.(SGD Phú Th 2018) Mt đề thi môn Toán
câu hi trc nghim khách quan, mi câu
hi
4
phương án trả lời, trong đó đúng một phương án đáp án. Học sinh chọn đúng đáp
án được
0,2
đim, chọn sai đáp án không được điểm. Mt học sinh làm đề thi đó, chọn ngu
nhiên các phương án trả li ca tt c
câu hi, xác suất để học sinh đó được
5,0
đim bng
A.
1
2
. B.
25
25 1
50 3
50
1
4
.AA
A
. C.
1
16
. D.
25
25 1
50 3
50
1
4
.CC
C
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 35.(S GD-ĐT Bc Ninh 2018) Đề kim tra
15
phút
10
câu trc nghim mi câu bn
phương án trả lời, trong đó có một phương án đúng, tr lời đúng được
1,0
đim. Mt thí sinh làm
c
10
câu, mi câu chn một phương án. Tính xác suất để thí sinh đó đạt t
8,0
tr lên.
A.
10
436
4
. B.
10
463
4
. C.
4
436
10
. D.
4
463
10
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 36.(S GD-ĐT Quãng Nam 2018) Hai bn Bình và Lan cùng d thi trong K thi THPT Quc Gia
năm
2018
hai phòng thi khác nhau. Mi phòng thi
24
thí sinh, mi môn thi
24
đề
khác nhau. Đề thi được sp xếp phát cho thi sinh mt cách ngu nhiên. Xác suất để trong hai
môn thi Toán và Tiếng Anh, Bình và Lan có chung đúng một mã đề thi.
A.
32
235
. B.
46
2209
. C.
23
288
. D.
23
576
.
Li gii
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
142
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 37.(Chuyên Lam Sơn-Thanh Hóa 2018) An Bình cùng tham gia thi THPTQG năm
2018
,
ngoài thi ba môn Toán, Văn, Tiếng Anh bt buộc thì An Bình đều đăng thi them đúng hai
môn t chn khác trong ba môn Vt lí, Hóa hc và Sinh học dưới hình thc thi trc nghiệm để xét
tuyển Đại hc. Mi môn t chn trc nghim
8
đề thi khác nhau, đề thi ca các môn
khác nhau khác nhau. Tính xác suất để An Bình chung đúng một n thi t chn
chung một mã đề.
A.
1
9
. B.
1
10
. C.
1
12
. D.
1
24
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 19. Một đoàn tàu có 7 toa ở mt sân ga. Có 7 hành khách t sân ga lên tàu, mỗi người
độc lp vi nhau và chn mt toa mt cách ngu nhiên. Tìm xác sut ca các biến c sau
A
:“Mt toa 1 người, một toa 2 người, mt toa 4 người lên và bốn toa không có người nào c
B
: “ Mỗi toa có đúng một người lên”.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
143
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 20. Một người b ngu nhiên bốn lá thư vào 4 bì thư đã được ghi địa ch. Tính xác sut
ca các biến c sau: A: “ Có ít nhất một lá thư bỏ đúng phong bì của nó”.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Nhómi toán 4. Nhóm chn s.
Bài tp 21. Gọi
S
tập hợp các số tự nhiên gồm ba chữ số đôi một khác nhau được lập từ các
chữ số
0; 1; 2; 3; 4
. Lấy ngẫu nhiên ba số bất trong tập
S
. Tính xác suất để trong ba số được
lấy ra có đúng một số có chữ số 3.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 22. Cho tập hợp
2
2 31 15 0X x x x
.
Chọn ngẫu nhiên từ tập
X
ba số t nhiên. Tính xác suất để ba số được chọn có tổng là một số lẻ.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
144
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 23. Gọi
X
tập hợp các số tự nhiên có năm chữ số đôi một khác nhau luôn mặt
chữ số 5 được lập từ các chữ số
0, 1, 2, 3, 5, 4, 6
. Chọn ngẫu nhiên một số từ
X
, tính xác suất để
số được chọn chia hết cho 5.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 24. Cho tập hợp
0,1,2,3,4,5A
. Tìm số phần tử của tập
S
gồm các số ba chữ số
khác nhau được lập thành từ các chữ số của tập
A
. Chọn ngẫu nhiên một số từ tập
S
, tính xác
sut để số được chọn có chữ số cuối gấp đôi chữ số đầu.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 25. Từ các chữ số
0, 1, 2, 3, 4, 5
lập các số lẻ có bốn chữ số đôi một khác nhau.
Lấy ngẫu nhiên một số vừa lập, tính xác suất để lấy được một số nhỏ hơn 2015.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
145
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 26. 27 tấm thẻ được đánh số từ 1 đến 27. Chọn ngẫu nhiên ra 8 tấm thẻ. Tìm xác
suất để có 3 tấm thẻ mang số lẻ, 5 tấm thẻ mang số chẵn trong đó có đúng 2 tấm thẻ mang số chia
hết cho 4.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 27. Một số điện thoại bảy chữ số, trong đó chữ số đầu chữ số
8
. Số điện thoại
được gọi may mắn nếu bốn chữ số đầu bốn chữ số chẵn phân biệt ba chữ số còn lại ba
chữ s lẻ, đồng thời hai chữ số
0
9
không đứng liền nhau. Tính xác suất để một người khi lắp
đặt điện thoại ngẫu nhiên được một số điện thoại may mắn.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
146
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
5. Câu hi trc nghim:
u 38.(THPT Bình Xuyên-2018) Gọi
X
tập các số tự nhiên
10
chữ số được lập từ các chữ
số
1
,
2
,
3
. Chọn một số thuộc
X
. Tính xác suất để số được chọn có đúng
5
chữ số
1
;
2
chữ số
2
3
chữ số
3
?
A.
280
6561
. B.
13
2130
. C.
157
159
. D.
20
31
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 39.(THPT Hoàn Thanh Hóa 2018) Từ các chữ số
1
,
2
,
3
,
4
,
5
,
6
,
7
,
8
ta lập các số tự
nhiên
6
chữ số, c chữ số đôi một khác nhau. Chọn ngẫu nhiên một số vừa lập, tính c
suất để chọn được một số có đúng
3
chữ số lẻ mà các chữ số lẻ xếp kề nhau.
A.
4
35
. B.
1
35
. C.
1
840
. D.
1
210
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 40.(Chuyên H Long 2019)Chn ngu nhiên mt s t nhiên trong các s t nhiên có bn ch
s. Tính xác suất để s đưc chn có ít nht hai ch s 8 đứng lin nhau.
A.
0,029
. B.
0,019
. C.
0,021
. D.
0,017
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
147
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 41.(SGD Phú Th 2018) Chn ngu nhiên mt s nguyên dương nhỏ hơn
. Xác suất để s
đưc chn là s chia hết cho
5
bng
A.
1
5
. B.
6
29
. C.
2
29
. D.
5
29
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 42.(THPT Chuyên ĐH Vinh 2018) Gieo mt con súc sắc cân đối đồng cht. Gi s súc sc
xut hin mt
b
chm. Xác suất để phương trình
2
20x bx
có hai nghiệm phân bit là
A.
2
3
. B.
5
6
. C.
1
3
. D.
1
2
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 43.(THPT Nguyễn Du) Gieo một con súc sắc cân đối đồng chất. Giả sử súc sắc xuất hiện
mặt
b
chấm. Xác suất để phương trình
2
2 4 0x bx
có nghiệm là
A.
1
. B.
2
3
. C.
1
6
. D.
5
6
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 44.(THPT Hồng Bàng 2018) Một người gọi điện thoại, quên hai chữ số cuối chỉ nhớ rằng
hai chữ số đó phân biệt. Tính xác suất để người đó gọi một lần đúng số cần gọi.
A.
83
90
. B.
1
90
. C.
13
90
. D.
89
90
.
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
148
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 45.(S GD-ĐT Bình Thun-2018) Gi
A
tp hp tt c các s t nhiên có
7
ch s đôi một
khác nhau được to ra t các ch s
0
,
1
,
2
,
3
,
4
,
5
,
6
. T
A
chn ngẫu nhiên mt s. Tính c
suất để s đưc chn có ch s
1
và ch s
2
đứng cnh nhau.
A.
5
21
. B.
5
18
. C.
2
7
. D.
1
3
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 46.(THPT Năng Khiếu TP HCM 2018)Gi
S
là tp hp các s t nhiên có
6
ch s. Chn ngu
nhiên mt s t
S
, tính xác suất để các ch s ca s đó đôi một khác nhau và phi có mt ch s
0
1
.
A.
7
125
. B.
7
150
. C.
189
1250
. D.
7
375
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
149
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
u 47.(THPT Quý Đôn- Nội 2018) Lập các số tự nhiên có 7 chữ số từ các chữ số
1
;
2
;
3
;
4
.
Tính xác suất để số lập được thỏa mãn: các chữ số
1
;
2
;
3
mặt hai lần, chữ số
4
mặt
1
lần
đồng thời các chữ số lẻ đều nằm ở các vị trí lẻ (tính từ trái qua phải).
A.
9
8192
. B.
3
4096
. C.
3
2048
. D.
9
4096
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 48.(THPT Chuyên Tiền Giang-2018) Gọi
S
tập hợp tất cả các số tự nhiên
4
chữ số được
lập từ tập hợp
1; 2; 3; 4; 5; 6; 7;8;9X
. Chọn ngẫu nhiên một số từ
S
. Tính xác suất để schọn
được là số chia hết cho
6
.
A.
4
27
. B.
9
28
. C.
1
9
. D.
4
9
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 49.(THTT số 6-489 năm 2018) Kết quả
;bc
của việc gieo một con súc sắc cân đối hai lần
liên tiếp, trong đó
b
số chấm xuất hiện của lần gieo thứ nhất,
c
số chấm xuất hiện lần gieo
thứ hai được thay vào phương trình bậc hai
2
0x bx c
. Tính xác suất để phương trình bậc hai
đó vô nghiệm?
A.
7
12
. B.
23
36
. C.
17
36
. D.
5
36
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 50.(PTNK-ĐHQG TP HCM-2018) Gọi
S
tập hợp tất cả các số tự nhiên
7
chữ số chia
hết cho
9
. Chọn ngẫu nhiên một số từ tập
S
, tính xác suất để các chữ số của số đó đôi một khác
nhau.
A.
396
625
. B.
512
3125
. C.
369
6250
. D.
198
3125
.
Li gii
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
150
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 51.(THPT Yên Lc Vĩnh Phúc 2018) Gi
A
tp hp các s t nhiên
5
ch s đôi một
khác nhau. Chn ngu nhiên mt s t nhiên thuc tp
A
. Tính xác suất để chọn được mt s
thuc
A
và s đó chia hết cho
5
.
A.
11
27
P
. B.
53
243
P
. C.
2
9
P
. D.
17
81
P
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 52.(Sở GD&ĐT Bình Phước) Cho
A
tập các số tự nhiên có
9
chữ số. Lấy ngẫu nhiên một số
thuộc tập
A
. Tính xác suất lấy được một số lẻ và chia hết cho
9
.
A.
1
18
. B.
1
9
. C.
625
1701
. D.
1250
1701
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
151
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
u 53.(S GD -ĐT Hu Giang 2018)Gi
A
tp hp tt c các s t nhiên
8
chữ s đôi một
khác nhau. Chn ngu nhiên mt s thuc
A
. Tính xác suất để s t nhiên được chn chia hết cho
25
.
A.
17
81
. B.
43
324
. C.
1
27
. D.
11
324
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 54.(THPT Hi Hu A-2018)Cho các s
0
,
1
,
2
,
3
,
4
,
5
,
6
lp mt s t nhiên
6
ch s đôi
mt khác nhau dng
abcdef
. Tính xác suất để s lập được tha mãn
a b c d e f
?
A.
4
135
. B.
5
158
. C.
4
85
. D.
3
20
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 55.(THPT Chuyên Quý Đôn 2018) Xét tp hp
A
gm tt c các s t nhiên 5 ch s
khác nhau. Chn ngu nhiên mt s t
A
. Tính xác suất để s đưc chn ch s đng sau ln
hơn chữ s đứng trước (tính t trái sang phi) ?
A.
74
411
. B.
62
431
. C.
1
216
. D.
3
350
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
152
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 56.(Chuyên Tin Giang-2018) Gi
S
là tp hp tt c các s t nhiên có
4
ch s đưc lp t
tp hp
1,2,3,4,5,6,7,8,9X
. Chn ngu nhiên mt s t
S
. Tính xác suất để s chọn được
s chia hết cho
6
.
A.
4
27
. B.
9
28
. C.
1
9
. D.
4
9
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 57.(THPT Thường Kiết Ni) Chn ngu nhiên mt s t nhiên nh hơn
300
. Gi
A
biến c “s đưc chn không chia hết cho 4”. Tính xác suất
PA
ca biến c
.A
A.
1
3
PA
. B.
3
4
PA
. C.
2
3
PA
. D.
1
4
PA
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 58. Gi
S
là tp hp tt c các s t nhiên gm 3 ch s. Chn ngu nhiên mt s thuc
S
. Xác
suất để s chọn được là mt s t nhiên chia hết cho 9 và có các ch s đôi một khác nhau bng
A.
19
225
B.
29
450
C.
16
225
D.
7
75
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
153
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 59.(Chuyên KHTN -2018) Cho tp hp
1,2,3,...,10A
. Chn ngu nhiên ba s t
A
. Tìm
xác suất để trong ba s chn ra không có hai s nào là hai s nguyên liên tiếp.
A.
7
90
P
. B.
7
24
P
. C.
7
10
P
. D.
7
15
P
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 60.(Đề Chính Thức 2018 ) Ba bạn
A
,
B
,
C
mỗi bạn viết ngẫu nhiên lên bảng một số tự nhiên
thuộc đoạn
1;19
. Xác suất để ba số được viết ra có tổng chia hết cho 3 bằng
A.
1027
6859
. B.
2539
6859
. C.
2287
6859
. D.
109
323
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 61. Chính Thc 2018) Ba bn A, B, C mi bn viết ngu nhiên lên bng mt s t nhiên
thuộc đoạn
1;16
. Xác suất để ba s đưc viết ra có tng chia hết cho
3
bng .
A.
683
2048
. B.
1457
4096
. C.
19
56
. D.
77
512
.
Li gii
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
154
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 62.(THPT Chuyên Trn Phú 2018) Chn ngu nhiên mt s t nhiên 4 ch s. Tính xác
suất để s đưc chn có dng
abcd
, trong đó
19a b c d
.
A.
0,014
. B.
0,0495
. C.
0,079
. D.
0,055
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 63.(THPT Trn Phú 2018) Gi
S
tp hp các t nhiên
9
ch s đôi một khác nhau.
Chn ngu nhiên mt s trong tp
S
. Tính xác suất để s đưc chọn đúng bốn ch s l sao
cho s
0
luôn đứng gia hai ch s l.
A.
5
54
. B.
5
648
. C.
5
42
. D.
20
189
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
155
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 64.(Đề Chính Thức 2018) Ba bạn
A
,
B
,
C
mỗi bạn viết ngẫu nhiên lên bảng một số tự nhiên
thuộc đoạn
1;17
. Xác suất để ba số được viết ra có tổng chia hết cho
3
bằng
A.
1728
4913
. B.
1079
4913
. C.
23
68
. D.
1637
4913
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 65. Ba bạn
A
,
B
,
C
mỗi bạn viết ngẫu nhiên lên bảng một số tự nhiên thuộc đoạn
1;14
. Xác
suất để ba số được viết có tổng chia hết cho
3
.
A.
307
1372
. B.
457
1372
. C.
207
1372
. D.
31
91
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 66.(THPT Chuyên Quý Đôn) Xét tp hp
A
gm tt c các s t nhiên 5 ch s khác
nhau. Chn ngu nhiên mt s t
A
. Tính xác suất để s đưc chn ch s đứng sau lớn hơn
ch s đứng trước (tính t trái sang phi) ?
A.
74
411
. B.
62
431
. C.
1
216
. D.
3
350
.
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
156
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 67.(Chuyên Khoa hc T Nhiên) Mt người viết ngu nhiên mt s bn ch s. Tính xác
suất để các ch s ca s đưc viết ra th t tăng dần hoc gim dần ( nghĩa nếu s đưc
viết dưới dng
abcd
thì
a b c d
hoc
a b c d
).
A.
7
125
. B.
7
375
. C.
7
250
. D.
14
375
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 68.(TTHT Ln 4) Gi
S
tp hp tt c các s t nhiên
4
ch s đưc lp t tp hp
1,2,3,4,5,6,7,8,9X
. Chn ngu nhiên mt s t
S
. Tính xác sut chọn được s chia hết cho
6
A.
4
27
. B.
9
28
. C.
9
25
. D.
4
9
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
157
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 69.(CLoa Hà Ni) Gi
S
tp tt c các s t nhiên bn ch s khác nhau. Chn ngu
nhiên mt s t tp
S
, tính xác suất để s đưc chn lớn hơn số 6700.
A.
10
27
. B.
12
33
. C.
15
29
. D.
21
46
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 70.(Cầu Giấy Hà Nội 2019) Gieo ngẫu nhiên một con súc sắc 3 lần liên tiếp. Gọi
,,abc
lần lượt
là số chấm xuất hiện ở 3 lần gieo. Xác suất của biến cố “ số
abc
chia hết cho
45
” là
A.
1
216
. B.
1
54
. C.
1
72
. D.
1
108
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 71.(Sở Thanh Hóa 2019) Gọi
S
tập tất cả các số tự nhiên 4 chữ số đôi một khác nhau
được chọn từ các chữ s
1, 2, 3, 4, 5, 6, 7, 8, 9
. Lấy ngẫu nhiên một số thuộc
S
. Tính xác suất đ
lấy được một số chia hết cho
11
và tổng 4 chữ số của nó cũng chia hết cho
11
.
A.
1
63
P
. B.
1
126
P
. C.
2
63
. D.
8
21
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
158
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 72. T các s lập được bao nhiêu s t nhiên gm tám ch s sao cho trong mi
s đó đúng ba ch s 1, các ch s còn lại đôi một khác nhau hai ch s chẵn không đứng
cnh nhau?
A. . B. . C. . D. .
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 73.(Hu Lc Thanh Hóa) Gi là tp hp các s t nhiên có ch s. Ly ngu nhiên hai s
t tp . Xác suất để nhận được ít nht mt s chia hết cho gn nht vi s nào dưới đây?
A. . B. . C. . D. .
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Nhómi toán 5. Liên quan đến hình hc.
u 74.(Cụm 8 trường Chuyên) Cho hình tứ diện đều
ABCD
. Trên mỗi cạnh của tứ diện, ta đánh
dấu
3
điểm chia đều cạnh tương ứng thành các phần bằng nhau. Gọi
S
là tập hợp các tam giác
ba đỉnh lấy từ
18
điểm đã đánh dấu. Lấy ra từ
S
một tam giác, xác suất để mặt phẳng chứa tam
giác đó song song với đúng một cạnh của tứ diện đã cho bằng
A.
2
45
. B.
9
34
. C.
2
5
. D.
4
15
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
1;2;3;4;5;6
2612
2400
1376
2530
X
5
X
4
0,23
0,44
0,56
0,12
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
159
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 75.(THPT Chuyên Lương Văn Ty2018) Cho hai đường thng song song
1
d
;
2
d
. Trên
1
d
6
đim phân biệt được màu đỏ. Trên
2
d
4
đim phân biết được màu xanh. Xét tt c các
tam giác được to thành khi nối các điểm đó với nhau. Chn ngu nhiên một tam giác, khi đó xác
suất để thu được tam giác có hai đỉnh màu đỏ là:
A.
5
32
. B.
5
8
. C.
5
9
. D.
5
7
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 76.
(THTT S 4 2018) Cho một đa giác đều
20
đỉnh ni tiếp trong đường tròn
O
. Chn ngu
nhiên bốn đỉnh của đa giác đó. Tính xác suất sao cho bốn đỉnh được chn bốn đỉnh ca hình
ch nht.
A.
3
323
. B.
4
9
. C.
2
969
. D.
7
216
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 77.(THPT Kinh Môn 2018) Cho một đa giác đều gm
2n
đỉnh
2,nn
. Chn ngu nhiên
ba đỉnh trong s
2n
đỉnh của đa giác, xác suất ba đỉnh được chn to thành mt tam giác vuông
1
5
. Tìm
n
A.
5n
. B.
4n
. C.
10n
. D.
8n
.
Li gii
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
160
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 78. Cho đa giác đu
20
đỉnh. Trong các t giác bốn đỉnh đỉnh của đa giác, chọn ngu
nhiên mt t giác. Tính xác suất để t giác được chn là hình ch nht.
A.
6
323
. B.
3
323
. C.
15
323
. D.
14
323
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 79.(Chuyên Phan Bi Châu 2018) Một đa giác lồi
10
đỉnh. Chn ngẫu nhiên ba đỉnh của đa
giác li ni chúng li với nhau ta được mt tam giác. Tính xác suất đ tam giác thu được ba
cạnh là ba đường chéo của đa giác đã cho.
A.
11
12
. B.
1
4
. C.
3
8
. D.
5
12
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 80.(THPT Thch Thành 2018) Cho một đa giác đều
18
đỉnh ni tiếp trong một đường tròn
tâm
O
. Gi
X
tập các tam giác các đỉnh các đỉnh của đa giá trên. Tính xác suất để chn
đưc mt tam giác t tp
X
là tam giác cân nhưng không phải là tam giác đều.
A.
23
136
. B.
3
17
. C.
144
136
. D.
7
816
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
161
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
u 81.(THPT Chuyên Vĩnh Phúc 2018)Cho một đa giác li
H
có
đỉnh. Chn ngu nhiên
4
đỉnh của đa giác đó. Gọi
P
xác sut sao cho
4
đỉnh được chn to thành mt t giác có bn
cạnh đều là đưng chéo ca
H
. Hi
P
gn vi s nào nht trong các s sau?
A.
0,6792
. B.
0,5287
. C.
0,6294
. D.
0,4176
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
âu 82. (Chuyên Phan Bội Châu 2018) Cho đa giác đều
100
đỉnh. Chọn ngẫu nhiên 3 đỉnh của đa
giác.Xác suất ba đỉnh được trọn là ba đỉnh của tam giác tù là
A.
. B.
16
33
. C.
. D.
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 83.(Chuyên Vĩnh Phúc 2018) Cho một đa giác lồi
H
có
đỉnh. Chọn ngẫu nhiên
4
đỉnh
của đa giác đó. Gọi
P
xác suất sao cho
4
đỉnh được chọn tạo thành một tứ giác bn cnh
đều là đưng chéo ca
H
. Hỏi
P
gn vi s nào nht trong các s sau?
A.
0,6792
. B.
0,5287
. C.
0,6294
. D.
0,4176
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
162
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 84.ng Thành Nam) Cho đa giác đều 20 cnh. Ly ngẫu nhiên 3 đỉnh của đa giác đều. Xác
suất để 3 đỉnh ly được 3 đỉnh ca mt tam giác vuông không cnh nào cnh của đa giác
đều bng
A.
3
38
. B.
7
114
. C.
7
57
. D.
5
114
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 85.ng Thành Nam) Năm đoạn thẳng độ dài
1cm
;
3cm
;
5cm
;
7cm
;
9cm
. Ly ngu
nhiên ba đoạn thng trong năm đoạn thng trên. Xác suất để ba đoạn thng ly ra to thành ba
cnh ca mt tam giác bng
A.
2
5
. B.
7
10
. C.
3
5
. D.
3
10
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
163
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 86.(THPT Mê Linh-Nội) Cho một đa giác đều
18
đỉnh nội tiếp đường tròn tâm
O
. Gọi
X
tập hợp tất cả các tam giác
3
đỉnh trùng với
3
trong số
18
đỉnh của đa giác đã cho. Chọn
1
tam giác trong tập hợp
X
. Xác suất để tam giác được chọn là tam giác cân bằng
A.
23
136
. B.
144
136
. C.
3
17
. D.
11
68
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 87.(THPT Hùng Vương) Cho đa giác đều
20
đnh. Ly ngu nhiên
4
đỉnh trong các đỉnh ca
đa giác. Tính xác suất đ
4
đỉnh lấy được to thành t giác
2
góc
2
đỉnh k chung mt cnh
ca t giác là
2
góc tù.
A.
112
323
. B.
14
323
. C.
14
19
. D.
16
19
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
164
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
Nhómi 6. Xếp v trí
Bài tp 28.
6
học sinh lớp
11
3
học sinh lớp
12
được xếp ngẫu nhiên vào
9
ghế thành
một dãy. Tính xác suất để xếp được
3
học sinh lớp
12
xen kẽ giữa
6
học sinh lớp
11
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 29. Đội tuyển học sinh giỏi của một trường THPT có
8
học sinh nam và
4
học sinh nữ.
Trong buổi lễ trao phần thưởng, các học sinh trên được xếp thành một hàng ngang. Tính xác suất
để khi xếp sao cho
2
học sinh nữ không đứng cạnh nhau.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
i tp 30. Đại hội đại biểu toàn quốc lần thứ
XII
Đảng Cộng Sản Việt Nam năm
2016
10
đại biểu trong đó
, , A B C
tham dự đại hội được xếp vào ngồi một dãy ghế dài
10
chổ trống.
Tính xác suất để
A
B
luôn ngồi cạnh nhau nhưng
A
C
không được ngồi cạnh nhau.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
165
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
i tp 31. Một tổ
9
học sinh gồm
4
học sinh nữ trong đó .
2
. học sinh n Thu
Nguyệt với
5
học sinh nam. Xếp
9
học sinh trong tthành một hàng dọc. Tính xác suất để chỉ
hai học sinh nữ Thu và Nguyệt đứng cạnh nhau còn các học sinh nữ khác không đứng cạnh nhau
đồng thời cũng không đứng cạnh Thu và Nguyệt.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 32.
4
hc sinh nam
4
hc sinh n đưc xếp ngi ngu nhiên vào
8
ghế xếp
thành
2
dãy đối din nhau. Tính xác sut sao cho hc sinh nam và hc sinh n ngồi đối din nhau
hoc các hc sinh n ngồi đối din nhau.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 33.
3
thư giống nhau lần lượt được đánh số thứ tự từ
1
đến
3
3
con tem
giống nhau lần lượt đánh số thứ tự từ
1
đến
3
. Dán
3
con tem đó vào
3
thư sao cho không
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
166
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
bì thư nào không có tem. Tính xác suất để lấy ra được
2
thư trong
3
bì thư trên sao cho mỗi
thư đều có số thứ tự giống với số thứ tự con tem đã dán vào nó.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 34. Trong thư viện có
12
quyn sách gm
3
quyn Toán ging nhau,
3
quyn Lý ging
nhau,
3
quyn Hóa ging nhau
3
quyn Sinh ging nhau. bao nhiêu cách xếp thành mt
dãy sao cho
3
quyn sách thuc cng
1
môn không được xếp lin nhau.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 35. Xếp
6
học sinh nam
4
học sinh nữ vào một bàn tròn
10
ghế. Tính xác suất để
không có hai học sinh nữ ngồi cạnh nhau.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 36.
5
hc sinh nam,
8
hc sinh n
1
thầy giáo được xếp ngu nhiên thành mt
vòng tròn. Tính xác suất để thy giáo xếp gia hai hc sinh n.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
167
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 9.
4
hành khách bước lên một đoàn tàu gồm
4
toa. Mỗi hành khách độc lập với
nhau chọn ngẫu nhiên một toa. Tính xác suất để
1
toa
3
người,
1
toa
1
người,
2
toa còn
lại không có ai.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 37.
8
người khách bước ngẫu nhiên vào một cửa hàng có
3
quầy.
Tính xác suất để
3
người cng đến quầy thứ nhất.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 38. Trong kỳ thi THPT Quốc Gia năm
2016
, một trường THPT miền núi
9
học sinh
gồm
5
nam
4
nữ cng trúng tuyển vào khoa Toán của một trường Đại học. Sinh viên khoa
Toán của trường Đại học này được chia ngẫu nhiên thành
4
lớp (mỗi lớp nhiều hơn
9
sinh
viên). Tính xác suất để trong
4
lớp đó một lớp đúng
3
sinh viên nam đúng
2
sinh viên nữ
đến từ trường THPT ở miền núi.
Li gii
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
168
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 39. Một đoàn tàu gồm
3
toa đỗ sân ga. Có
5
hành khách bước lên tàu, mỗi hành
khách độc lập với nhau chọn ngẫu nhiên
1
toa. Tính xác suất để mỗi toa ít nhất
1
hành khách
bước lên tàu.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
1. Câu hi trc nghim:
u 88.(THPT Số 1 Tư Nghĩa 2019) Có 8 học sinh nam, 5 học sinh nữ 1 thầy giáo được sắp xếp
ngẫu nhiên đứng thành một vòng tròn. Tính xác suất để thầy giáo đứng giữa 2 học sinh nam.
A.
7
.
39
P
B.
14
.
39
P
C.
28
.
39
P
D.
7
.
13
P
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 89.(Chuyên KHTN 2019) hai dãy ghế đối diện nhau, mỗi dãy 5 ghế. Xếp ngẫu nhiên 10
học sinh, gồm 5 nam 5 nữ ngồi vào hai dãy ghế đó sao cho mỗi ghế có đúng một học sinh ngồi.
Tính xác suất để mỗi học sinh nam đều ngồi đối diện một học sinh nữ.
A.
1
252
. B.
1
945
. C.
8
63
. D.
4
63
.
Li gii
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
169
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 90. (Liên Trưng Ngh An) 3 quyn sách toán, 4 quyn sách 5 quyn sách hóa khác
nhau được sp xếp ngu nhiên lên một giá sách 3 ngăn, các quyển sách được sp dựng đứng
thành mt hàng dc vào một trong 3 ngăn (mỗi ngăn đủ rộng để cha tt c các quyn sách).
Tính xác suất để không có bt k hai quyển sách toán nào đứng cnh nhau.
A.
36
91
. B.
37
91
. C.
54
91
. D.
55
91
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 91. Có 8 người khách bước ngu nhiên vào mt ca hàng có 3 quy. Tính xác suất để 3 người
cng đến quy th nht.
A.
32
85
8
.
3
CA
. B.
35
82
8
3
.CC
A
. C.
35
82
8
3
.CA
A
. D.
35
8
8
2
.
3
C
Li gii
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
170
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 92.(THPT Qúy Đôn 2019) Sp ngu nhiên
5
hc sinh nam
3
hc sinh n thành mt
hàng ngang. Tính xác suất để không có hc sinh n nào đứng cnh nhau.
A.
5
12
. B.
5
14
. C.
5
42
. D.
1
112
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 93. Trong một phòng học,
36
cái bàn rời nhau được đánh số từ
1
đến
36
, mỗi bàn dành
cho
1
học sinh. Các bàn được xếp thành một hình vuông có kích thước
6
x
6
. Cô giáo xếp tuỳ ý
36
học sinh của lớp vào các bàn, trong đó có hai bạn
A
B
.
Xác suất để
A
B
ngồi ở hai bàn xếp
cạnh nhau bằng (theo chiều ngang hoặc chiều dọc).
A.
2
21
. B.
2
7
. C.
4
35
. D.
6
35
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 94. hai dãy ghế đối diện nhau, mỗi dãy năm ghế. Xếp ngẫu nhiên 10 học sinh, gồm 5
nam và 5 nữ ngồi vào hai dãy ghế đó sao cho mỗi ghế đúng một học sinh ngồi. Xác suất để mỗi
học sinh nam đều ngồi đối diện với một học sinh nữ bất hai học sinh ngồi liền kề nhau thì
khác phái bằng
A.
4
315
. B.
1
252
. C.
1
630
. D.
1
126
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
171
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 95.(THPT Mai Anh Tun Thanh 2019) Xếp 4 người đàn ông, 2 người đàn một đứa trẻ
được xếp ngồi vào 7 chiếc ghế đặt quanh một bàn tròn. Xác suất để xếp đứa trẻ ngồi giữa hai
người đàn ông là
A.
1
15
B.
1
5
C.
2
15
. D.
2
5
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 96.(THPT Chuyên Nguyễn Huệ 2019)
15
cuốn sách gồm
4
cuốn sách Toán,
5
cuốn sách Lý
6
cuốn sách Hóa. Các cuốn sách đôi một khác nhau. Thầy giáo chọn ngẫu nhiên
8
cuốn sách để
làm phần thưởng cho một học sinh. Tính xác suất để số cuốn sách còn lại của thầy còn đủ
3
môn
A.
54
715
. B.
2072
2145
. C.
661
715
. D.
73
2145
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 97.(Gang Thép Thái Nguyên) Xếp ngu nhiên 2 qu cu xanh, 2 qu cầu đỏ, 2 qu cu trng
(các qu cầu y đôi một khác nhau) thành mt hàng ngang. Tính xác suất để 2 qu cu màu
trng không xếp cnh nhau?
A.
2
3
P
. B.
1
3
P
. C.
5
6
P
. D.
1
2
P
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
172
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 98.(THPT Đô Lương 2019) Trong chương trình giao lưu gồm người ngi vào ghế
theo mt hàng ngang. Gi s người dẫn chương trình chọn ngu nhiên người trong người
để giao lưu với khán gi. Xác suất để trong người được chọn đó không người ngi k
nhau là
A. . B. . C. . D. .
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 99.(THPT Chuyên T Trng 2019) hai dãy ghế đối din nhau, mi dãy 3 ghế. Xếp
ngu nhiên 6 hc sinh, gm 3 nam 3 n, ngi vào hai dãy ghế đó sao cho mỗi ghế đúng một
hc sinh ngi. Xác suất để mi học sinh nam đều ngồi đối din vi mt hc sinh n bng:
A. B. C. D.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 100.(THPT Ba Đình 2019) quyển sách Văn học khác nhau, quyn sách Toán hc khác
nhau quyn sách Tiếng Anh khác nhau được xếp lên mt k ngang. Tính xác suất để hai
cun sách cùng môn không cnh nhau
15
15
3
15
3
2
2
5
13
35
22
35
3
5
2
5
1
10
3
5
1
20
3
4
7
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
173
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
A. . B. . C. . D. .
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 101. (THPT Chuyên Ni 2019) Xếp ngu nhiên 5 bạn An, Bình, Cường, Dũng, Đông ngồi
vào mt dãy 5 ghế thng hàng (mi bn ngi 1 ghế). Xác sut ca biến c “hai bạn An Bình
không ngi cạnh nhau” là:
A. . B. . C. . D.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 102.(THPT NQuyn 2019) Sp xếp quyn sách Toán quyển sách Văn lên một k
sách dài. Tính xác suất để các quyn sách cùng mt môn nm cnh nhau.
A. . B. . C. . D. .
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
19
12012
19
1012
19
1202
5
8008
3
5
2
5
1
5
4
5
5
4
1
181440
125
126
1
63
1
126
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
174
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 103.(THPT Chuyên Thái Nguyên 2019) học sinh lớp A, học sinh lớp B học sinh
lớp C xếp thành một ng ngang sao cho giữa hai học sinh lớp A không có học sinh lớp B. Hỏi
bao nhiêu cách sắp xếp như vậy?
A. . B. . C. . D. .
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 104.(THPT Nhân Tông 2019) Trước thi hc sinh giỏi, nhà trường t chc bui gp mt
em học sinh trong đi tuyn. Biết các em đó số th t trong danh sách lp thành cp s
cng. Các em ngi ngẫu nhiên vào hai dãy bàn đối din nhau, mi dãy ghế mi ghế ch
đưc ngi mt hc sinh. Tính xác suất để tng các s th t ca hai em ngồi đối din nhau
bng nhau.
A. . B. . C. . D. .
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 105.(THPT Chuyên Lê Quý Đôn 2019) Xếp chỗ cho 6 học sinh trong đó có học sinh A và 3 thầy
giáo vào 9 ghế thành hàng ngang (mỗi ghế xếp một người). Tính xác suất sao cho mỗi thầy
giáo ngồi giữa 2 học sinh và học sinh A ngồi ở một trong hai đầu hàng.
A. . D.
5
136
. C. . D.
5
48
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
2
3
4
108864
80640
145152
217728
10
5
954
1
126
1
945
1
252
1
5
252
5
42
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
175
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 106.(THPT Thun Thành-Bc Ninh) Mt bàn dài hai dãy ghế đối din nhau, mi dãy
ghế. Người ta mun xếp ch ngi cho học sinh trường học sinh trường vào bàn nói
trên. Tính xác suất để bt c hai hc sinh nào ngồi đối diện nhau đều khác trường vi nhau.
A. . B. . C. . D. .
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 107.(THPT Chuyên Bc Giang 2019) 4 người xếp thành hàng ngang mỗi người gieo 1
đồng xu cân đối đồng cht. Xác suất để tn tại hai người cnh nhau có cùng kết qu
A. . B. . C. . D. .
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 108.(THPT ISCHOOL Nha Trang) Có hai dãy ghế đi din nhau, mi dãy có bn ghế. Xếp ngu
nhiên 8 hc sinh, gm 4 nam và 4 n, ngi vào hai dãy ghế sao cho mi ghế đúng một hc sinh
ngi. Xác suất để mi học sinh nam đều ngồi đối din vi mt hc sinh n không hai hc
sinh cùng gii ngi cnh nhau bng
A. . B. . C. . D. .
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
5
5
X
5
Y
2
63
4
63
8
63
5
63
7
8
5
8
3
8
1
8
8
35
1
35
2
35
4
35
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
176
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 109.(Chuyên Đại Hc Vinh) Trong L tng kết Tháng thanh niên, 10 đoàn viên xuất sc
gm 5 nam và 5 n được tuyên dương khen thưởng. Các đoàn viên này được sp xếp ngu nhiên
thành mt hàng ngang trên sân khấu để nhn giy khen. Tính xác suất để trong hàng ngang trên
không có bt kì bn n nào đứng cnh nhau.
A. . B. . C. . D. .
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 110.(Chuyên Đại Hc Vinh) 4 quyn sách Toán, 6 quyn sách 8 quyn sách Hóa
khác nhau được xếp lên giá sách theo mt hàng ngang. Tính xác sut để không bt k hai
quyển sách Hóa đứng cnh nhau.
A. . B. . C. . D. .
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 111.(Chuyên Đại Hc Vinh) quyn sách toán, quyn sách quyn sách hóa
khác nhau được sp xếp ngu nhiên lên mt giá sách gm ngăn, các quyển sách được sp
1
7
1
42
1
252
25
252
5
663
1
663
1
1326
5
1326
3
4
5
3
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
177
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
dựng đng thành mt hàng dc vào một trong ba ngăn (mỗi ngăn đ rộng để cha tt c quyn
sách). Tính xác suất để không có bt kì hai quyển sách toán nào đứng cnh nhau.
A. . B. . C. . D.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 112.(THPT Chuyên Sơn La 2019) Một nhóm gồm học sinh lớp , học sinh lớp
học sinh lớp được xếp ngồi vào một hàng ghế, mỗi học sinh ngồi ghế. Tính xác suất để
học sinh lớp không ngồi ghế liền nhau.
A. . B. . C. . D. .
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
36
91
37
91
54
91
55
91
3
10
3
11
3
12
9
1
3
10
3
5
12
1
12
7
12
11
12
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 4. Xác Suất
178
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
u 113.(THPT Thanh Chương Nghệ An) Mt nhóm hc sinh gm bn nam bn n
trong đó cặp sinh đôi gm nam n. Xếp ngu nhiên hc sinh này vào dãy ghế đối
din, mi dãy ghế, sao cho mi ghế đúng một hc sinh ngi. Xác suất để cặp sinh đôi ngồi
cnh nhau và nam n không ngồi đối din nhau bng
A. . B. . C. . D. .
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
8
4
4
1
1
1
8
2
4
3
70
2
35
2
105
3
140
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 5. Quy Tắcnh Xác Suất
179
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
A L THUY󰈸T
I. Quy tc công xác sut.
1. Biến c hp.
Cho hai biến cố
A
B
. Biến cố
'' A
hoặc
B
xảy ra
''
, hiệu
AB
, được gọi hợp của hai
biến cố
A
B
.
2. Biến cố xung khắc.
Cho hai biến cố
A
B
. Hai biến cố
A
B
được gọi xung khắc nếu biến cố này xảy ra thì
biến cố kia không xảy ra.
3. Quy tắc cộng xác suất.
Nếu hai biến cố
A
B
xung khắc thì xác suất để
A
hoặc
B
xảy ra là
P A B P A P B
.
4. Biến cố đối.
Cho
A
là một biến cố. Khi đó biến cố
''
Không xảy ra
''A
, kí hiệu là
A
, gọi là biến cố đối của
A
.
Cho biến cố
A
. Xác xuất của biến cố đối
A
1P A P A
.
II. Quy tc nhân xác sut.
1. Biến cố giao.
Cho hai biến cố
A
B
. Biến cố
''
Cả
A
B
cùng xảy ra
''
, hiệu
AB
, được gọi giao của
hai biến cố
A
B
.
2. Biến cố độc lập.
Hai biến cố
A
B
được gọi là độc lập với nhau nếu việc xảy ra hay không xảy ra của biến cố này
không làm ảnh hưởng tới xác suất xảy ra của biến cố kia.
3. Quy tắc nhân xác suất.
Nêu hai biến cố
A
B
độc lập với nhau thì
.P AB P A P B
.
4. Công thức Bernoulli.
a). Định nghĩa. Dãy phép thử Bernoulli là dãy
n
phép thử thỏa mãn ba điều kiện sau đây
Các phép thử của dãy độc lập với nhau. Nghĩa là, kết quả của phép thử sau không phụ thuộc
vào các phép thử trước đó.
Trong mỗi phép thử chỉ có hai biến cố
A
hoặc
A
xảy ra.
Xác suất để biến cố
A
xảy ra trong mọi phép thử của dãy là như nhau và
P A p
với
01p
nên
1P A p
.
b) Công thức.
Xác suất để trong
n
phép thử, biến cố
A
xảy ra
k
lần với xác suất mỗi lần
A
xảy ra là
p
.
Được kí hiệu là
k k n k
nn
P k C p q
0;kn
gọi là công thức Bernoulli.
dụ 1. Một trò chơi xác suất thắng mỗi ván
0,3
. Nếu một người chơi tám ván thì xác
suất để người này thắng ít nhất một ván là bao nhiêu ?
Lời giải
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
§BI 5. C QUY TC TÍNH XÁC SUT
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 5. Quy Tắcnh Xác Suất
180
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
B PHÂN DNG D MINH HA.
Dng 1. c quy tc cng xác sut.
1. Phương pháp
Nếu hai biến c
A
B
xung khc thì
( ) ( ) ( )P A B P A P B
M rng quy tc cng xác sut: cho
k
biến c
12
, ,...,
k
A A A
đôi một xung khc.
Khi đó:
1 2 1 2
( ... ) ( ) ( ) ... ( )
kk
P A A A P A P A P A
.
Biến c đối
( ) 1 ( )P A P A
Gii s
A
B
là hai biến c tùy ý cùng liên quan đến mt phép th. Khi đó
()P A B P A P B P AB
.
2. Bài tp minh ha .
Bài tp 1. Mt hp đựng 4 viên bi xanh, 3 viên bi đỏ và 2 viên bi vàng. Chn ngu nhiên 2 viên
bi:
1). Tính xác suất để chọn được 2 viên bi cùng màu.
2). Tính xác suất để chọn được 2 viên bi khác màu.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 2. Mt hộp đựng 10 viên bi trong đó có 4 viên bi đỏ ,3 viên bi xanh,2 viên bi vàng,1 viên
bi trng. Ly ngu nhiên 2 bi tính xác sut biến c : A: “2 viên bi cùng màu”
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 3. Có 10 hc sinh lp A, 9 hc sinh lp B và 8 hc sinh lp C. Chn ngu nhiên 5 hc
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 5. Quy Tắcnh Xác Suất
181
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
sinh t các hc sinh nói trên. Tính xác sut sao cho lớp nào cũng học sinh được chn ít
nht hai hc sinh lp A.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 4.T I có 5 hc sinh nam, 6 n. T II có 7 n, 4 nam. Chn ngu nhiên mi t 2 hc sinh
để đưc 4 hc sinh. Tính xác sut ca các biến c sau:
a). 4 học sinh được chn gm 2 nam, 2 n.
b). Trong 4 học sinh được chọn có đúng 1 học sinh n.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 5. Mt con súc sắc không đồng cht sao cho mt bn chm xut hin nhiu gp 3 ln
mt khác, các mt còn lại đồng kh năng. Tìm xác suất để xut hin mt mt chn
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 5. Quy Tắcnh Xác Suất
182
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
3. Câu hi trc nghim .
Mc độ 1. Nhn biết.
u 1.(THPT Hai Trưng-Vĩnh Pc 2019) Trong các khẳng định sau đây, khẳng định nào sai?
A. Không gian mẫu là tập hợp tất cả các kết quả có thể xảy ra của phép thử.
B. Gọi
PA
là xác suất của biến cố
A
ta luôn có
01PA
.
C. Biến cố là tập con của không gian mẫu.
D. Phép thử ngẫu nhiên phép thử ta không biết được chính xác kết quả của nhưng ta
có thể biết được tập hợp tất cả các kết quả có thể xảy ra của phép thử.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 2.(THPT Chuyên Tĩnh 2019) Cho
A
,
B
hai biến cố xung khắc. Đẳng thức nào sau đây
đúng?
A.
P A B P A P B
. B.
.P A B P A P B
.
C.
P A B P A P B
. D.
P A B P A P B
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 3.(SGD Thanh Hóa 2019) Cho
A
B
là hai biến c xung khc. Mệnh đề nào dưới đây đúng?
A.
1P A P B
.
B. Hai biến c
A
B
không đồng thi xy ra.
C. Hai biến c
A
B
đồng thi xy ra.
D.
1P A P B
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Câu 4.(Sở GD-ĐT Kiên Giang-2019) Gieo một con súc sắc cân đối đồng chất. Tính xác suất để
xuất hiện mặt có số chấm chia hết cho
3
.
A.
1
. B.
1
3
. C.
3
. D.
2
3
.
Li gii
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 5. Quy Tắcnh Xác Suất
183
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 5.(THPT Hồng Lĩnh- Tĩnh 2018) Một hộp đựng
10
viên bi có kích thước khá nhau, trong đó
7
viên bi màu đỏ và
3
viên b màu xanh. Chọn ngẫu nhiên
2
viên. Xác suất để
2
viên bi được
chọn có ít nhất một viên bi màu xanh bằng
A.
1
15
. B.
2
15
. C.
7
15
. D.
8
15
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 6.(THPT Đặng Thúc Hứa 2019) Một hộp đựng
5
viên bi đỏ,
4
viên bi xanh. Lấy ngẫu nhiên
3
viên bi từ hộp đó. Tính xác suất lấy được ít nhất
1
viên đỏ.
A.
37
42
. B.
1
21
. C.
5
42
. D.
20
21
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 7.(THPT Hoàn-Thanh Hóa 2019)Một túi đựng
6
bi xanh
4
bi đỏ. Lấy ngẫu nhiên
2
bi.
Xác suất để cả hai bi đều đỏ là.
A.
7
15
. B.
7
45
. C.
8
15
. D.
2
15
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 8.(THPT Yên Lc-Vĩnh Phúc 2019) Mt t hc sinh
7
nam
3
n. Chn ngu nhiên
2
người. Tính xác sut sao cho
2
người được chọn đều là n.
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 5. Quy Tắcnh Xác Suất
184
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
A.
1
15
. B.
7
15
. C.
8
15
. D.
1
5
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 9.(THPT Chuyên Thái Bình 2019) Mt t hc sinh
6
nam
4
n. Chn ngu nhiên
2
người. Tính xác suất sao cho hai người được chọn đều là n.
A.
2
15
. B.
7
15
. C.
8
15
. D.
1
3
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 10.(THPT Chuyên Vĩnh Phúc 2019) Trong trò chơi “Chiếc nón diệu” chiếc kim ca bánh xe
th dng li mt trong
7
v trí vi kh năng như nhau. Tính xác suất để trong ba ln quay,
chiếc kim của bánh xe đó lần lượt dng li ba v trí khác nhau.
A.
5
49
. B.
3
7
. C.
30
343
. D.
30
49
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 11.(THPT Can Lc- Tĩnh-2019)
7
tm bìa ghi
7
ch “HỌC”, “TẬP”, “VÌ”, “NGÀY”, “MAI”,
“LẬP”, “NGHIỆP”. Một người xếp ngu nhiên
7
tm bìa cnh nhau. Tính xác suất để khi xếp c
tấm bìa được dòng ch “HC TP VÌ NGÀY MAI LP NGHIỆP”.
A.
1
720
. B.
1
24
. C.
1
120
. D.
1
5040
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 12.(THPT y Đôn-2019) Mt lô hàng có
20
sn phẩm, trong đó
4
phế phm. Ly tùy ý
6
sn phm t lô hàng đó. Hãy tính xác suất để trong
6
sn phm ly ra không quá
1
phế phm.
A.
91
323
. B.
637
969
. C.
7
9
. D.
91
285
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 5. Quy Tắcnh Xác Suất
185
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Mc độ 2. Thông hiu.
u 13.(THPT Chuyên Thái Bình 2019) Mt lp có 20 nam sinh và 15 n sinh. Giáo viên chn
ngu nhiên 4 hc sinh lên bng gii bài tp. Tính xác suất để 4 học sinh được chọn có c nam và
n.
A.
4615
.
5236
B.
4651
.
5236
C.
4615
.
5263
D.
4610
.
5236
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 14.(Chuyên Bc Ninh 2018) Mt cái hp cha
6
viên bi đỏ
4
viên bi xanh. Ly lần lượt
2
viên bi t cái hộp đó. Tính xác suất để viên bi được ly ln th
2
là bi xanh.
A.
2
5
. B.
7
24
. C.
11
12
. D.
7
9
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 15.(SGD Ra Vũng Tàu 2018)
9
chiếc th được đánh số t
1
đến
9
, người ta rút ngu
nhiên hai th khác nhau. Xác suất để rút được hai th tích hai s được đánh trên thẻ là s
chn bng
A.
2
3
. B.
5
18
. C.
1
3
. D.
13
18
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 5. Quy Tắcnh Xác Suất
186
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 16.Một lớp
đoàn viên trong đó
15
nam
20
nữ. Chọn ngẫu nhiên
3
đoàn viên
trong lớp để tham dự hội trại
26
tháng
3
. Tính xác suất để trong
3
đoàn viên được chọn cả
nam và nữ.
A.
90
119
. B.
30
119
. C.
125
7854
. D.
6
119
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 17.(THPT Bình Xuyên-2018) Trong t đồ chơi của bn An
5
con thú bông gm: vt, chó,
mèo, gu, voi. Bn An mun ly ra mt s thú bông. Xác sut để trong nhng con thú bông An ly
ra không có con vt.
A.
16
31
. B.
1
2
. C.
15
32
. D.
15
31
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 18.(THPT Kim Liên - HN - L1 - 2018) Việt Nam chơi cờ. Trong một ván cờ, xác suất Việt
thắng Nam
0,3
và Nam thắng Việt
0,4
. Hai bạn dừng chơi khi người thắng, người thua.
Tính xác suất để hai bạn dừng chơi sau hai ván cờ.
A.
0,12
. B.
0,7
. C.
0,9
. D.
0,21
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 19.(THPT Bình Xuyên-2018) Một tổ
6
học sinh nam
4
học sinh nữ. Chọn ngẫu nhiên
4
học sinh. Xác suất để trong
4
học sinh được chọn luôn có học sinh nữ là:
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 5. Quy Tắcnh Xác Suất
187
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
A.
1
14
. B.
1
210
. C.
13
14
. D.
209
210
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 20.(THPT Hoàng Hoa Thám-2018) Một hộp đựng
9
tấm thẻ được đánh số từ
1
đến
9
. Hỏi phải
rút ít nhất bao nhiêu thẻ để xác suất “có ít nhất một thẻ ghi số chia hết cho
4
” phải lớn hơn
5
6
.
A.
7
. B.
6
. C.
5
. D.
4
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 21. Có hai chiếc hộp
A
B
. Hộp
A
chứa
6
viên bi trắng,
4
viên bi đen. Hộp
B
chứa
7
viên
bi trắng,
3
viên bi đen. Người ta lấy ngẫu nhiên một viên bi từ hộp
A
bỏ vào hộp
B
rồi sau đó t
hộp
B
lấy ngẫu nhiên ra hai viên bi. Tính xác suất để hai viên bi lấy được từ hộp
B
hai viên bi
trắng.
A.
126
275
. B.
21
55
. C.
123
257
. D.
37
83
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Mc độ 3. Vn dng.
u 22.(Tp chí THTT 2018) Một túi đựng
10
tm th được đánh s t
1
đến
10
. Rút ngu nhiên
ba tm th t túi đó. Xác suất để tng s ghi trên ba th rút được là mt s chia hết cho
3
bng
A.
1
3
. B.
3 3 1 1 1
3 4 3 3 4
3
10
2C C C C C
C

. C.
33
34
3
10
2CC
C
. D.
111
3 3 4
3
10
2CCC
C
.
Li gii
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 5. Quy Tắcnh Xác Suất
188
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 23.(THPT Chuyên Nguyn Quang Diu 2018) Kết qu
,bc
ca vic gieo mt con súc sc cân
đối hai ln liên tiếp, trong đó
b
là s chm xut hin ln gieo th nht,
c
là s chm xut hin ln
gieo th hai được thay vào phương trình bc hai
2
0x bx c
. Tính xác suất để phương trình
bậc hai đó vô nghim:
A.
5
36
. B.
7
12
. C.
23
36
. D.
17
36
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 24.(SGD Ninh Bình2018) Gieo một con súc sắc cân đối đồng chất. Giả sử con súc sắc xuất
hiện mặt
b
chấm. Tính xác suất sao cho phương trình
2
10x bx b
(
x
ẩn số) nghiệm
lớn hơn
3
.
A.
1
3
. B.
5
6
. C.
2
3
. D.
1
2
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 25.(ĐHQG TPHCM 2018) Gi
S
là tp hp các s t nhiên có
6
ch s. Chn ngu nhiên mt
s t
S
, tính xác suất để các ch s ca s đó đôi một khác nhau và phi có mt ch s
0
1
.
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 5. Quy Tắcnh Xác Suất
189
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
A.
7
125
. B.
7
150
. C.
189
1250
. D.
7
375
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Dng 2. Tính xác sut bng quy tc nhân
1. Phương pháp:
Ta chng t hai biến c A và B độc lp nếu s xy ra (hay không xy ra) ca A không làm nh
ởng đến xác sut ca B.
Hai biến c A và B độc lp khi và ch khi .
2. Bài tp minh ha.
Bài tp 6. Xác sut sinh con trai trong mi ln sinh là 0,51 .Tìm các sut sao cho 3 ln sinh có ít
nht 1 con trai
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 7. Hai cu th sút phạt đền .Mỗi nười đá 1 lần vi xác suất làm bàm tương ứng là 0,8 và
0,7.Tính xác suất để có ít nht 1 cu th làm bàn
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.P AB P A P B
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 5. Quy Tắcnh Xác Suất
190
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
Bài tp 8.Một đề trc nghim gm 20 câu, mi u 4 đáp án ch một đáp án đúng. Bạn
An làm đúng 12 câu, còn 8 câu bạn An đánh hú họa vào đáp án An cho đúng. Mỗi câu đúng
được 0,5 điểm. Hi An có kh năng được bao nhiêu điểm?
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 9.Mt cp v chng mong mun sinh bằng đựơc sinh con trai (Sinh được con trai ri
thì không sinh nữa, chưa sinh được thì s sinh na). Xác suất sinh được con trai trong mt ln
sinh là
0,51
. Tìm xác sut sao cho cp v chồng đó mong muốn sinh được con trai ln sinh th
2.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 10.Gieo mt con xúc sc 4 ln. Tìm xác sut ca biến c
A: “ Mặt 4 chm xut hin ít nht mt ln”
B: “ Mặt 3 chm xut hiện đúng một ln”
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 5. Quy Tắcnh Xác Suất
191
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 11. Chn ngu nhiên mt vé x s có 5 ch s đưc lp t các ch s t 0 đến 9. Tính
xác sut ca biến c X: “lấy được vé không có ch s 2 hoc ch s 7”
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 12. Cho ba hp ging nhau, mi hp 7 bút ch khác nhau v màu sc
Hp th nhất : Có 3 bút màu đỏ, 2 bút màu xanh , 2 bút màu đen
Hp th hai : Có 2 bút màu đỏ, 2 màu xanh, 3 màu đen
Hp th ba : Có 5 bút màu đỏ, 1 bút màu xanh, 1 bút màu đen
Ly ngu nhiên mt hp, rút hú ha t hộp đó ra 2 bút
1). Tính xác sut ca biến c A: “Lấy được hai bút màu xanh”
2). Tính xác sut ca xác suất B: “Lấy được hai bút không có màu đen”
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 13.C hai x th cùng bn vào bia. Xác suất ngưi th nht bắn trúng bia 0,8; ngưi
th hai bn trúng bia là 0,7. Hãy tính xác suất để :
1). C hai người cùng bn trúng ;
2). C hai người cùng không bn trúng;
3). Có ít nht một người bn trúng.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 5. Quy Tắcnh Xác Suất
192
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 14. Mt chiếc máy hai động I II hoạt động độc lp vi nhau. Xác suất để động
cơ I và động cơ II chạy tt lần lượt là
0,8
0,7
. Hãy tính xác suất để
1). C hai động cơ đều chy tt ;
2).C hai động cơ đều không chy tt;
3). Có ít nht một động cơ chạy tt.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 15. Có hai x th I và x tám x th II. Xác sut bn trúng ca I là 0,9 ; xác sut ca II là
0,8 ly ngu nhiên mt trong hai x th, bn một viên đạn. Tính xác suất để viên đạn bn ra trúng
đích.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 16. Bn khu pháo cao x A,B,C,D cùng bắn độc lp vào mt mc tiêu .Biết xác sut bn
trúng ca các khẩu pháo tương ng
1 2 4 5
. , ,
2 3 5 7
P A P B P C P D
.Tính xác suất để
mc tiêu b bn trúng
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 5. Quy Tắcnh Xác Suất
193
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
Bài tp 17. Mt hộp đựng 10 viên bi trong đó 4 viên bi đ ,3 viên bi xanh, 2 viên bi vàng,1
viên bi trng .Ly ngu nhiên 2 bi tính xác sut biến c
1). 2 viên lấy ra màu đỏ
2). 2 viên bi một đỏ ,1 vàng
3). 2 viên bi cùng màu
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 18. Gieo ngu nhiên mt con xúc xc 6 ln .Tính xác suất để mt s lớn hơn hay bng 5
xut hin ít nht 5 ln trong 6 ln gieo
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 19. Một người bn liên tiếp vào mt mục tiêu khi viên đạn trúng mc tiêu thì thôi (các
phát súng độc lp nhau ). Biết rng xác sut trúng mc tiêu ca mi ln bắn như nhaubng 0,6
.Tính xác suất để bắn đến viên th 4 thì ngng bn
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 20. Chn ngu nhiên mt vé x s có 5 ch s đưc lp t các ch s t 0 đến 9. Tính
xác sut ca biến c X: “lấy được vé không có ch s 1 hoc ch s 2” .
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 5. Quy Tắcnh Xác Suất
194
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 21. Mt máy 5 động gồm 3 động bên cánh trái hai động bên cánh phi.
Mỗi động bên cánh phải xác sut b hng
0,09
, mỗi động bên cánh trái có xác sut b
hng là
0,04
. Các động cơ hoạt động độc lp vi nhau. Máy bay ch thc hiện được chuyến bay an
toàn nếu ít nhất hai động làm việc. Tìm xác suất đ máy bay thc hiện được chuyến bay an
toàn.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 22. Ba cu th sút phạt đến 11m, mỗi người đá một ln vi xác suất làm bàn tương ứng
x
,
y
0,6
(vi
xy
) . Biết xác suất để ít nht mt trong ba cu th ghi bàn
0,976
xác
suất để c ba cu th đều ghi ban là
0,336
. Tính xác suất để có đúng hai cầu th ghi bàn.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Bài tp 23. Mt bài trc nghim 10 câu hi, mi câu hỏi 4 phương án lựa chọn trong đó
1 đáp án đúng. Giả s mi câu tr lời đúng được 5 điểm mi câu tr li sai b tr đi 2 điểm.
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 5. Quy Tắcnh Xác Suất
195
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
Mt hc sinh không học bài nên đánh họa mt câu tr li. Tìm xác suất để hc sinh này nhn
đim i 1.
Li gii.
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
3. Câu hi trc nghim .
Mc độ 2. Thông hiu.
u 26.(THPT Chuyên ĐH KHTN 2018) Cho
A
B
hai biến cố độc lập với nhau.
0,4PA
,
0,3PB
. Khi đó
P AB
bằng
A.
0,58
. B.
0,7
. C.
0,1
. D.
0,12
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 27.(SGD Nam Định 2018) Giải bóng chuyền VTV Cúp gồm
12
đội bóng tham dự, trong đó có
9
đội nước ngoài
3
đội của Việt Nam. Ban tổ chức cho bốc thăm ngẫu nhiên để chia thành
3
bảng
A
,
B
,
C
mỗi bảng
4
đội. Tính xác suất để
3
đội bóng của Việt Nam ở
3
bảng khác nhau
A.
16
55
. B.
133
165
. C.
32
165
. D.
39
65
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 28.(THPT Hoa -2018) Ba x th
1
A
,
,
3
A
độc lp vi nhau cùng n súng bn vào mc
tiêu. Biết rng xác sut bn trúng mc tiêu ca
1
A
,
,
3
A
tương ứng
0,7
;
0,6
0,5
. Tính xác
suất để có ít nht mt x th bn trúng.
A.
0,45
. B.
0,21
. C.
0,75
. D.
0,94
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 5. Quy Tắcnh Xác Suất
196
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 29.(THPT Triệu Sơn 12018) Xác sut bn trúng mc tiêu ca mt vận động viên khi bn mt
viên đạn là
0,6
. Người đó bắn hai viên đạn mt cách độc lp. Xác suất để mt viên trúng mc tiêu
và một viên trượt mc tiêu là
A.
0,45
. B.
0,4
. C.
0,48
. D.
0,24
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 30.(THPT Tây Thụy Anh 2018) Hai xạ thủ cùng bắn, mỗi người một viên đạn vào bia một
cách độc lập với nhau. Xác suất bắn trúng bia của hai xạ thủ lần lượt
1
2
1
3
. Tính xác suất của
biến cố có ít nhất một xạ thủ không bắn trúng bia.
A.
1
2
. B.
1
3
. C.
2
3
. D.
5
6
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Mc độ 3. Vn dng.
u 31.(THPT Tam Phước-2018) Trong mt cuc thi 10 câu hi trc nghim, mi câu 4
phương án trả lời, trong đó chmột phương án đúng. Vi mi câu, nếu chọn phương án trả li
đúng thì thí sinh được cộng 5 điểm, nếu chọn phương án trả li sai s b tr 1 điểm. Tính xác sut
để mt thí sinh làm bài bng cách la chn ngẫu nhiên phương án được 26 điểm, biết thí sinh
phi làm hết các câu hi và mi câu hi ch chn duy nht một phương án trả li.
(chn giá tr gn
đúng nhất)
A.
0,016222
. B.
0,162227
. C.
0,028222
. D.
0,282227
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 32.(Chuyên Thái Bình) Một đề thi trc nghim gm
câu, mi câu
4
phương án tr li
trong đó chỉ
1
phương án đúng, mỗi câu tr lời đúng được
0,2
đim. Mt thí sinh làm bài bng
cách chn ngu nhiên
1
trong
4
phương án ở mi câu. Tính xác suất để thí sinh đó được
6
đim.
A.
30 20 20
50
0,25 .0,75 .C
. B.
20 30
1 0,25 .0,75
. C.
20 30
0,25 .0,75
. D.
30 20
0,25 .0,75
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 5. Quy Tắcnh Xác Suất
197
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 33.(THPT Hoài Ân-Hải Phòng 2018) Một đ thi trắc nghiệm gồm
câu, mỗi câu
4
phương án trả lời trong đó chỉ có
1
phương án đúng, mỗi câu trả lời đúng được
0,2
điểm. Một thí
sinh làm bài bằng cách chọn ngẫu nhiên
1
trong
4
phương án ở mỗi câu. Tính xác suất để thí sinh
đó được
6
điểm.
A.
20 30
1 0,25 .0,75
. B.
30 20
0,25 .0,75
. C.
20 30
0,25 .0,75
. D.
30 20 20
50
0,25 .0,75 C
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 34.(THPT Chuyên Lam Sơn-2018) An Bình cùng tham gia thi THPTQG năm
2018
, ngoài
thi ba môn Toán, Văn, Tiếng Anh bt buộc thì An Bình đều đăng thi them đúng hai môn tự
chn khác trong ba môn Vt lí, Hóa hc Sinh học dưới hình thc thi trc nghiệm để xét tuyn
Đại hc. Mi môn t chn trc nghim
8
đề thi khác nhau, đề thi ca các môn khác
nhau là khác nhau. Tính xác suất để An và Bình có chung đúng mt môn thi t chn và chung mt
mã đề.
A.
1
9
. B.
1
10
. C.
1
12
. D.
1
24
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 35.(THPT Chuyên Quý Đôn-2018) Thầy Bình đặt lên bàn
tm th đánh số t
1
đến
.
Bn An chn ngu nhiên
10
tm th. Tính xác sut để trong
10
tm th ly ra
5
tm th mang
s l,
5
tm mang s chẵn trong đó chỉ có mt tm th mang s chia hết cho
10
.
A.
99
667
. B.
. C.
. D.
99
167
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 5. Quy Tắcnh Xác Suất
198
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 36.(THPT Chuyên Hoàng n Thụ-2018) Một con súc sắc không cân đối, đặc điểm mặt u
chấm xuất hiện nhiều gấp hai lần c mặt còn lại. Gieo con súc sắc đó hai lần. Xác suất đtổng số
chấm trên mặt xuất hiện trong hai lần gieo lớn hơn hoặc bằng
11
bằng:
A.
8
49
. B.
4
9
. C.
1
12
. D.
3
49
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 37.Gọi
A
tập hợp tất cả các số tự nhiên
5
chữ số. Chọn ngẫu nhiên một số từ tập
A
.
Tính xác suất để chọn được số chia hết cho
11
và chữ số hàng đơn vị là số nguyên tố
A.
2045
13608
. B.
409
90000
. C.
409
3402
. D.
409
11250
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 38.(Sở GD-ĐT Trà Vinh-2018) Trong thi thử THPT Quốc Gia, An làm để thi trắc nghiệm
môn Toán. Đề thi gồm
câu hỏi, mỗi câu
4
phương án trả lời, trong đó chỉ một phương
án đúng; trả lời đúng mỗi câu được
0,2
điểm. An trả lời hết các câu hỏi và chắc chắn đúng
45
câu,
5
câu còn lại An chọn ngẫu nhiên. Tính xác suất để điểm thi môn Toán của An không dưới
9,5
điểm.
A.
9
22
. B.
13
1024
. C.
2
19
. D.
53
512
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 5. Quy Tắcnh Xác Suất
199
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 39.(Chuyên Thái Nguyên-2018) Một hộp đựng
40
tấm thẻ được đánh số thứ tự từ
1
đến
40
.
Rút ngẫu nhiên
10
tấm thẻ. Tính xác suất để lấy được
5
tấm thẻ mang số lẻ và
5
tấm thẻ mang số
chẵn, trong đó có đúng một thẻ mang số chia hết cho
6
.
A.
252
1147
. B. .
26
1147
. C.
12
1147
. D.
126
1147
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 40.(Chuyên Thái Nguyên-2018) Chn ngu nhiên mt x s
5
ch s đưc lp t các
ch s t
0
đến
9
. Tính xác suất để lấy được vé không có ch s
1
hoc ch s 2.
A.
0,8533
. B.
0,5533
. C.
0,6533
. D.
0,2533
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 41. Chn ngu nhiên mt s t nhiên có năm ch s. Tính xác suất để s đưc chn dng
abcde
trong đó
19a b c d e
.
A.
143
10000
. B.
138
1420
. C.
11
200
. D.
3
7
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 5. Quy Tắcnh Xác Suất
200
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Dng 3. Phi hp quy tc cng xác sut và quy tc nhân.
u 42.(THTT Số 2-485 2018) Một người bắn súng, để bắn trúng vào tâm, xác suất tầm ba phần
bảy
3
7



. Hỏi cả thảy bắn ba lần, xác suất bắn trúng tâm đúng một lần là bao nhiêu?
A.
48
343
. B.
144
343
. C.
199
343
. D.
27
343
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 43.(THPT Chuyên Trần Phú-2018) Ba xạ thủ cùng bắn vào một tấm bia, xác suất trúng đích
lần lượt là
0,5
;
0,6
0,7
. Xác suất để có đúng 2 người bắn trúng bia là:
A.
0,29
. B.
0,44
. C.
0,21
. D.
0,79
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 44.(THPT Chuyên Trần Phú 2018) Ba xạ thcùng bắn vào một tấm bia một cách độc lập, xác
suất bắn trúng đích lần lượt là
0,5
;
0,6
0,7
. Xác suất để có đúng hai người bắn trúng bia là:
A.
0,21
. B.
0,29
. C.
0,44
. D.
0,79
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 5. Quy Tắcnh Xác Suất
201
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 50. (THPT Chuyên Vĩnh Phúc-2018)
20
tấm thẻ được đánh số từ
1
đến
20
. Chọn ngẫu
nhiên
8
tấm, tính xác suất đchọn được
5
tấm mang số lẻ,
3
tấm mang số chn trong đó ít nhất
2
tấm mang số chia hết cho
4
, kết quả gần đúng là
A.
12 %
. B.
23%
. C.
3%
. D.
2%
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 45.(THPT Kim Liên- Nội 2018) Việt và Nam chơi cờ. Trong một ván cờ, xác suất Việt thắng
Nam là
0,3
và Nam thắng Việt là
0,4
. Hai bạn dừng chơi khi có người thắng, người thua. Tính xác
suất để hai bạn dừng chơi sau hai ván cờ.
A.
0,12
. B.
0,7
. C.
0,9
. D.
0,21
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Câu 46.(THPT Chuyên Ti Bình-2018) Trong mt đợt kiểm tra vệ sinh an tn thực phẩm ca ngành
y tế tại chợ X, ban quản lý chợ lấy ra 15 mẫu thịt lợn trong đó 4 mẫu ở quầy A, 5 mẫu ở quầy B, 6
mẫu ở quầy C. Đoàn kiểm tra lấy ngẫu nhiên 4 mẫu đpn tích xem trong thịt lợn có chứaa chất
tạo nạc hay không. Xác suất đmẫu thịt của cả 3 quầy A, B, C đều được chọn bằng
A.
43
91
. B.
4
91
. C.
48
91
. D.
87
91
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 5. Quy Tắcnh Xác Suất
202
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 47.(THPT Quãng Xương 1-2018) Trong phòng làm việc có hai máy tính hoạt động độc lập với
nhau, khả năng hoạt động tốt trong ngày của hai máy này tương ứng là
75%
85%
. Xác suất để
có đúng một máy hoạt động không tốt trong ngày là
A.
0,425
. B.
0,325
. C.
0,625
. D.
0,525
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 48.(Chuyên Đại Học Vinh-2018) Đầu tiết học, giáo kiểm tra bài bằng cách gọi lần lượt
từng người từ đầu danh sách lớp lên bảng trả lời câu hỏi. Biết rằng học sinh đâu tiên trong danh
sách lớp An, Bình, Cường với xác suất thuộc bài lần lượt
0,9;
0,7
0,8.
giáo sẽ dừng
kiểm tra sau khi đã 2 học sinh thuộc bài. Tính xác suất giáo chỉ kiểm tra bài đúng 3 bạn
trên.
A.
0,504
. B.
0,216
. C.
0,056
. D.
0,272
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 49.(THPT Chuyên Lam Sơn-2018) Một hộp đựng
9
viên bi trong đó có
4
viên bi đỏ và
5
viên
bi xanh. Lấy ngẫu nhiên từ hộp
3
viên bi. Tìm xác suất để
3
viên bi lấy ra có ít nhất
2
viên bi màu
xanh.
A.
10
21
. B.
5
14
. C.
25
42
. D.
5
42
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 50.(Sở GD&ĐT Bắc Giang 2018) Một lô hàng gồm
sản phẩm trong đó
20
sản phẩm tốt
10
sản phẩm xấu. Lấy ngẫu nhiên
3
sản phẩm trong hàng. Tính xác suất đ
3
sản phẩm lấy
ra có ít nhất một sản phẩm tốt.
A.
6
203
B.
197
203
C.
153
203
D.
57
203
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 5. Quy Tắcnh Xác Suất
203
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 51.(Tạp chí THTT 2018) Một người bỏ ngẫu nhiên ba lá thư vào ba chiếc phong đã ghi địa
chỉ. Xác suất để có ít nhất một lá thư được bỏ đúng phong bì là
A.
1
2
. B.
2
3
. C.
1
3
. D.
5
6
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 52.(Tạp c THTT 2018) Một nhóm học sinh gồm
a
lớp
A
,
b
lớp
B
c
lớp
C
,
b
,
c
;
a
,
b
,
c
4
. Chọn ngẫu nhiên ra
4
bạn. Xác suất để chọn được
4
bạn thuộc cả ba lớp là
A.
1 1 1 1
3
4
a b c a b c
a b C
C C C C
C

. B.
4 4 4
4
1
a b b c a c
a b C
C C C
C


.
C.
2 1 1 1 2 1 1 1 2
4
a b c a b c a b c
a b C
C C C C C C C C C
C


. D.
4 4 4 4 4 4
44
1
a b b c a c a b c
a b C a b C
C C C C C C
CC

.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 53.(THPT Chuyên Hùng Vương Gia Lai Lần 2 năm 2017 2018) Giả sử rằng, trong Đại hội
thể dục thể thao tỉnh Gia Lai năm
2018
16
đội bóng đăng tham gia giải, được chia thành
4
bảng
A
,
B
,
C
,
D
, mỗi bảng gồm
4
đội. Cách thức thi đấu như sau:
Vòng
1
: Các đội trong mỗi bảng thi đấu vòng tròn một ợt, nh điểm chọn ra đội nhất của mỗi
bảng.
Vòng
2
(bán kết): Đội nhất bảng
A
gặp đội nhất bảng
C
; Đội nhất bảng
B
gặp đội nhất bảng
D
.
Vòng
3
(chung kết): Tranh giải ba: Hai đội thua trong bán kết; tranh giải nhất: Hai đội thắng
trong bán kết.
Biết rằng tất cả các trận đấu đều diễn ra trên sân vận động Pleiku vào các ngày liên tiếp, mỗi ngày
4
trận. Hỏi Ban tổ chức cần mượn sân vận động trong bao nhiêu ngày?
A.
5
. B.
6
. C.
7
. D.
8
.
Li gii
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 5. Quy Tắcnh Xác Suất
204
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 54.(Chuyên Đại Học Vinh-2018) Một quân vua được đặt trên một ô giữa bàn cờ vua. Mỗi
bước di chuyển, quân vua được chuyển sang một ô khác chung cạnh hoặc chung đỉnh với ô đang
đứng (xem hình minh họa). Bạn An di chuyển quân vua ngẫu nhiên
3
bước. Tính xác suất sau
3
bước quân vua trở về ô xuất phát.
A.
1
16
. B.
1
32
. C.
3
32
. D.
3
64
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 55.(THPT Lê Qúy Đôn-2018) Tung một đồng xu không đồng chất
2020
lần. Biết rằng xác suất
xuất hiện mặt sấp là
0,6
. Tính xác suất để mặt sấp xuất hiện đúng
1010
lần.
A.
1
2
. B.
1010
0,24
. C.
2
3
. D.
1010
1010
2020
. 0,24C
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 56.(THPT Hoa 2018) Cho hai đường thẳng song song
a
b
. Trên đường thẳng
a
lấy
6
điểm phân biệt; trên đường thẳng
b
lấy
5
điểm phân biệt. Chọn ngẫu nhiên
3
điểm trong các
điểm đã cho trên hai đường thẳng
a
b
. Tính xác xuất để
3
điểm được chọn tạo thành một tam
giác.
A.
. B.
60
169
. C.
. D.
.
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 5. Quy Tắcnh Xác Suất
205
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 57.(THPT Hậu Lộc 2-Thanh Hóa-2018) Một mạch điện gồm
4
linh kiện như hình vẽ, trong đó
xác suất hỏng của từng linh kiện trong một khoảng thời gian
t
nào đó tương ứng
0,2
;
0,1
;
0,05
0,02
. Biết rằng các linh kiện làm việc độc lập với nhau các dây luôn tốt. Tính xác suất
để mạng điện hoạt động tốt trong khoảng thời gian
t
.
A.
0,37
. B.
0,67032
. C.
0,78008
. D.
0,8
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 58.(THPT Chuyên Vĩnh Phúc-2018) Trong một hình tứ diện ta màu các đỉnh, trung điểm
các cạnh, trọng tâm các mặt trọng m tứ diện. Chọn ngẫu nhiên 4 điểm trong số các điểm đã
tô màu, tính xác suất để 4 điểm được chọn là bốn đỉnh của một tứ diện.
A.
188
.
273
B.
1009
.
1365
C.
245
.
273
D.
136
.
195
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.
.
1
2
4
3
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 5. Quy Tắcnh Xác Suất
206
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 59.(THPT Thạch Thành 2-2018) Hai người ngang tài ngang sức tranh chức địch của cuộc
thi cờ tướng. Người giành chiến thắng người đầu tiên thắng được
5
ván cờ. Tại thời điểm
người chơi thứ nhất đã thắng
4
ván người chơi thứ hai mới thắng
2
ván, tính xác suất để
người chơi thứ nhất giành chiến thắng?
A.
4
5
. B.
3
4
. C.
7
8
. D.
1
2
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 60.(THPT Chuyên ĐH KHTN-2018) Cho tập hợp
1,2,3,...,10A
. Chọn ngẫu nhiên ba số từ
A
. Tìm xác suất để trong ba số chọn ra không có hai số nào là hai số nguyên liên tiếp.
A.
7
90
P
. B.
7
24
P
. C.
7
10
P
. D.
7
15
P
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 61.(THPT Chuyên Phan Bội Châu-2018) Cho đa giác đều
20
đỉnh. Lấy ngẫu nhiên
3
đỉnh.
Tính xác suất để
3
đỉnh đó là
3
đỉnh của
1
tam giác vuông không cân.
A.
2
35
. B.
17
114
. C.
8
57
. D.
3
19
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 5. Quy Tắcnh Xác Suất
207
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 62.(THPT Chuyên Quốc Học-Huế 2018) Có ời cái ghế (mỗi ghế chngồi được một người)
được sắp trên một hàng ngang. Xếp ngẫu nhiên
7
học sinh ngồi vào, mỗi học sinh ngồi đúng một
ghế. Tính xác suất sao cho không có hai ghế trống nào kề nhau.
A.
0,25
. B.
0,46
. C.
0,6 4
. D.
0,4 6
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 63.(THPT Chuyên Biên a-2018) Đội thanh niên xung kích của trường THPT Chuyên Biên
Hòa
12
học sinh gồm
5
học sinh khối
12
,
4
học sinh khối
11
3
học sinh khối
10
. Chọn
ngẫu nhiên
4
học sinh để làm nhiệm vụ mỗi buổi sáng. Tính xác suất sao cho
4
học sinh được
chọn thuộc không quá hai khối.
A.
. B.
. C.
22
21
. D.
22
15
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 64.(SGD Rịa Vũng u 2018) Số giá trị nguyên của tham số
m
để phương trình
4 3cos sin 2 1 0x x m
có nghiệm là
A.
8
. B.
6
. C.
9
. D.
7
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 65.(SGD Rịa ng Tàu 2018) Lớp 11A
40
học sinh trong đó
12
học sinh đạt điểm
tổng kết môn Hóa học loại giỏi
13
học sinh đạt điểm tổng kết môn Vật loại giỏi. Biết rằng khi
chọn một học sinh của lớp đạt điểm tổng kết môn Hóa học hoặc Vật loại giỏi xác suất
0,5
.
Số học sinh đạt điểm tổng kết giỏi cả hai môn Hóa học và Vật lí là
A.
6
. B.
5
. C.
4
. D.
7
.
Li gii
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 5. Quy Tắcnh Xác Suất
208
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 66.(THPT Xoay-Vĩnh phúc 2018) Tập
S
gồm các số tự nhiên
6
chữ số khác nhau được
thành lập từ các chữ số
0; 1; 2; 3;
4; 5;
6; 7; 8
. Chọn ngẫu nhiên một số từ tập
S
. Xác suất để số
được chọn không có hai chữ số chẵn đứng cạnh nhau là
A.
11
70
. B.
29
140
. C.
13
80
. D.
97
560
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 67.(THPT Quỳnh u 2018) Một hộp đựng
10
thẻ được đánh số từ
1
đến
10
. Phải rút ra ít
nhất
k
thẻ để xác suất có ít nhất một thẻ ghi số chia hết cho
4
lớn hơn
13
15
. Giá trị của
k
bằng
A.
9
. B.
8
. C.
7
. D.
6
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 5. Quy Tắcnh Xác Suất
209
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 68.(SGD Quảng Nam năm 2017 2018) Một tổ gồm
9
học sinh gồm
4
học sinh nữ và
5
học
sinh nam. Chọn ngẫu nhiên từ tổ đó ra
3
học sinh. Xác suất để trong
3
học sinh chọn ra có số học
sinh nam nhiều hơn số học sinh nữ bằng:
A.
17
42
. B.
5
42
. C.
25
42
. D.
10
21
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 69.(THPT Trần Phú Đà Nẵng 2019) Gọi
S
tập hợp các tự nhiên
9
chữ số đôi một
khác nhau. Chọn ngẫu nhiên một số trong tập
S
. Tính xác suất để số được chọn đúng bốn chữ
số lẻ sao cho số
0
luôn đứng giữa hai chữ số lẻ.
A.
5
54
. B.
5
648
. C.
5
42
. D.
20
189
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 70.(Chuyên Đại Học Vinh 2018) Chia ngẫu nhiên
9
viên bi gồm
4
viên màu đỏ và
5
viên màu
xanh cùng kích thước thành ba phần, mỗi phần
3
viên. Xác xuất để không phần nào gồm
3
viên cùng màu bằng
A.
9
14
. B.
2
7
. C.
3
7
. D.
5
14
.
Li gii
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 5. Quy Tắcnh Xác Suất
210
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 71. (THPT Trần Nhân ng 2018) Một thí sinh tham gia thi THPT Quốc gia. Trong bài thi
môn Toán bạn đó làm được chắc chắn đúng
40
câu. Trong
10
câu còn lại chỉ
3
câu bạn loại
trừ được mỗi câu một đáp án chắc chắn sai. Do không còn đủ thời gian nên bạn bắt buộc phải
khoanh bừa các câu còn lại. Hỏi xác suất bạn đó được
9
điểm là bao nhiêu?
A.
0,079
. B.
0,179
. C.
0,097
. D.
0,068
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 72. (THPT Trần Nhân Tông 2018) Học sinh A thiết kế bảng điều khiển điện tử mở cửa phòng
học của lớp mình. Bảng gồm
10
nút, mỗi nút được ghi một số từ
0
đến
9
và không có hai nút nào
được ghi cùng một số. Để mở cửa cần nhấn
3
nút liên tiếp khác nhau sao cho
3
số trên
3
nút
theo thứ tự đã nhấn tạo thành một dãy số tăng tổng bằng
10
. Học sinh B chỉ nhớ được chi
tiết
3
nút tạo thành dãy số tăng. Tính xác suất để B mở được cửa phòng học đó biết rằng để nếu
bấm sai
3
lần liên tiếp cửa sẽ tự động khóa lại.
A.
631
3375
. B.
189
1003
. C.
1
5
. D.
1
15
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 5. Quy Tắcnh Xác Suất
211
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 73.(Chuyên Hùng Vương-P Thọ ) Hai người ngang i ngang sức tranh chức địch của
một cuộc thi cờ tướng. Người giành chiến thắng người đầu tiên thắng được năm ván cờ. Tại
thời điểm người chơi thứ nhất đã thắng
4
ván người chơi thứ hai mới thắng
2
ván, tính c
suất để người chơi thứ nhất giành chiến thắng.
A.
3
4
. B.
4
5
. C.
7
8
. D.
1
2
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 74.(THTT Số 3-486-2018) Mỗi lượt, ta gieo một con súc sắc (loại
6
mặt, cân đối) một
đồng xu (cân đối). Tính xác suất để trong
3
lượt gieo như vậy, ít nhất một lượt gieo được kết
quả con xúc sắc xuất hiện mặt
1
chấm, đồng thời đồng xu xuất hiện mặt sấp.
A.
397
1728
. B.
1385
1728
. C.
1331
1728
. D.
1603
1728
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 75.(THPT Quý Đôn-Hải Phòng 2018) Tung một đồng xu không đồng chất
2020
lần. Biết
rằng xác suất xuất hiện mặt sấp là
0,6
. Tính xác suất để mặt sấp xuất hiện đúng
1010
lần.
A.
1
2
. B.
1010
0,24
. C.
2
3
. D.
1010
1010
2020
. 0,24C
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 5. Quy Tắcnh Xác Suất
212
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 76.(THPT Chuyên nh-2018) Trong một lớp
n
học sinh gồm ba bạn Chuyên, Hà, Tĩnh
cùng
3n
học sinh khác. Khi xếp tùy ý các học sinh này vào dãy ghế được đánh số từ
1
đến
n
mỗi học sinh ngồi một ghế thì xác suất để số ghế của bằng trung bình cộng số ghế của Chuyên
và số ghế của Tĩnh là
13
675
. Khi đó
n
thỏa mãn
A.
35;39n
. B.
40;45n
. C.
30;34n
. D.
25;29n
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 77. (SGD Quảng Nam 2018) Hai bạn Bình Lan cùng dự thi trong Kỳ thi THPT Quốc Gia
năm
2018
hai phòng thi khác nhau. Mỗi phòng thi
24
thí sinh, mỗi môn thi
24
đề
khác nhau. Đề thi được sắp xếp phát cho thi sinh một cách ngẫu nhiên. Xác suất để trong hai
môn thi Toán và Tiếng Anh, Bình và Lan có chung đúng một mã đề thi.
A.
32
235
. B.
46
2209
. C.
23
288
. D.
23
576
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 5. Quy Tắcnh Xác Suất
213
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 78. (THPT Chuyên Hùng Vương 2018) Một người gọi điện thoại nhưng quên mất chữ số cuối.
Tính xác suất để người đó gọi đúng số điện thoại mà không phải thử quá hai lần.
A.
1
5
. B.
1
10
. C.
19
90
. D.
2
9
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 79. Gọi
A
tập các số tự nhiên
8
chữ số đôi một khác nhau. Chọn ngẫu nhiên một số
thuộc
A
. Tính xác suất để số được chọn chia hết cho
45
.
A.
5
162
. B.
2
81
. C.
1
36
. D.
53
2268
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
u 80.(Chuyên Thái Bình-2018) Cho một đa giác
H
có
60
đỉnh ni tiếp một đường tròn
O
.
Người ta lp mt t giác tùy ý có bốn đỉnh là các đỉnh ca
H
. Xác suất để lập được mt t giác
có bn cạnh đều là đưng chéo ca
H
gn vi s nào nht trong các s sau?
A.
85,40%
. B.
13,45%
. C.
40,35%
. D.
80,70%
.
Li gii
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
Trung Tâm Luyện Thi Đại Học Amsterdam Chương II-Bài 5. Quy Tắcnh Xác Suất
214
Lớp Toán Thầy-Diệp Tuân Tel: 0935.660.880
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
..........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
.........................................................................................................................................................................................................
| 1/214