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Bionomial-1
Tài liệu học tập môn Biochemistry (BT005) tại Trường Đại học Quốc tế, Đại học Quốc gia Thành phố Hồ Chí Minh. Tài liệu gồm 8 trang giúp bạn ôn tập hiệu quả và đạt điểm cao! Mời bạn đọc đón xem!
Biochemistry (BT005) 5 tài liệu
Trường Đại học Quốc tế, Đại học Quốc gia Thành phố Hồ Chí Minh 695 tài liệu
Bionomial-1
Tài liệu học tập môn Biochemistry (BT005) tại Trường Đại học Quốc tế, Đại học Quốc gia Thành phố Hồ Chí Minh. Tài liệu gồm 8 trang giúp bạn ôn tập hiệu quả và đạt điểm cao! Mời bạn đọc đón xem!
Môn: Biochemistry (BT005) 5 tài liệu
Trường: Trường Đại học Quốc tế, Đại học Quốc gia Thành phố Hồ Chí Minh 695 tài liệu
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Tài liệu khác của Trường Đại học Quốc tế, Đại học Quốc gia Thành phố Hồ Chí Minh
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lOMoARcPSD|364 906 32 Practice Problems #4
PRACTICE PROBLEMS FOR HOMEWORK 4
(1) Read section 2.5 of the text.
(2) Solve the practice problems below.
(3) Open Homework Assignment #4, solve the problems, and submit multiple-choice answers.
In each exercise, use the appropriate distribution. Binomial and Poisson probabilities can be
computed directly by their PMF formulas or by using distribution tables, such as Tables C.1 and C.2 on pp. 781-788 of the text.
1. (10 marks) Ten percent of computer parts produced by a certain supplier are defective. What is
the probability that a sample of 10 parts contains more than 3 defective ones?
2. (10 marks) On the average, two tornadoes hit major U.S. metropolitan areas every year. What is
the probability that more than five tornadoes occur in major U.S. metropolitan areas next year?
(As you probably saw in the news, a real tornado occurred near downtown Dallas on Sep 8, 2010.)
3. (10 marks) A lab network consisting of 20 computers was attacked by a computer virus. This
virus enters each computer with probability 0.4, independently of other computers.
a) Find the probability that the virus enters at least 10 computers.
b) A computer manager checks the lab computers, one after another, to see if they were
infected by the virus. What is the probability that she has to test at least 6 computers to find the first infected one?
4. (10 marks) On the average, 1 computer in 800 crashes during a severe thunderstorm. A certain
company had 4,000 working computers when the areawas hit by a severe thunderstorm.
a) Compute the expected value and variance of the number of crashed computers.
b) Compute the probability that less than 10 computers crashed.
c) Compute the probability that exactly 10 computers crashed.
(You may use a suitable approximation.)
5. (10 marks) A baker put 500 raisins into dough, mixed well, and made 100 cookies. You take a
random cookie. What is the probability of finding at least 4 raisins in it?
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(Hint: use Poisson approximation to the Binomial distribution of the number of raisins in one cookie.)
6. (10 marks) (Sec 2.5, p. 91, #3)
A mischievous student wants to break into a computer file, which is password-protected. Assume
that there are n passwords only one of which is correct, and that the student tries possible
passwords in a random order. Let N be the number of trials required to break into the file. Determine the pmf of
a) if unsuccessful passwords are not eliminated from further selections, and b) if they are eliminated.
c) If n = 10, what is the expected number of trials in each case (a) and (b)? 7.
(10 marks) An internet search engine looks for a certain keywordin a sequence of independent
web sites. It is believed that 20% of the sites contain this keyword.
a) Let X be the number of websites visited until the first keywordis found. Find the distribution of X.
b) Compute the expected value and the standard deviation of X.
c) Out of the first 10 websites, let Y be the number of sites that contain the keyword. Find the distribution of Y .
d) Compute the expected value and the standard deviation of Y .
e) Compute the probability that at least 5 of the first 10 websites contain the keyword.
f) Compute the probability that the search engine had to visit at least 5 sites inorder to find
the first occurrence of a keyword. 8.
(10 marks) Identical computer components are shipped in boxes of 5. About 15% of components
have defects. Boxes are tested in a random order.
a) What is the probability that a randomly selected box has only non-defective components?
b) What is the probability that at least 8 of randomly selected 10 boxes have only non-defective components?
c) What is the distribution of the number of boxes tested until a box without defective components is found? 9.
(10 marks) A master file consists of 150,000 records. When a transaction file is run against the
master file, approximately 12,000 records are updated.The records to be updated are assumed
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to be distributed uniformly over the master file. A program reads all the records one by one and
updates those which are necessary to update. What is the probability that
a) the first record is to be updated?
b) at least 20 records are read before the first record to be updated is found?
c) exactly 20 records are read before the first record to be updated is found?
10. (10 marks) The Stanley Cup winner is determined in the final series between two teams. The
first team to win 4 games wins the Cup. Suppose that Dallas Stars advance to the final series,
and they have a probability of 0.55 to win each game, and the game results are independent of
each other. Find the probability that
a) Dallas Stars wins the Stanley Cup
b) seven games are required to determine the Cup winner
(Hint: Without loss of generality, you can assume that the series continues until 7 games are
played, even if the Cup winner is determined earlier. This ”change of Stanley Cup rules” will not
change the answer to the problem!)
11. (10 marks) (The previous problem continued...)
Suppose that the series continues until Dallas Stars win 4 games, even if the other rival wins the Cup earlier.
a) What is the expected number of games to be played?
b) Find the probability that the series consists of less than 10 games.
c) Find the probability that by the end of the series, the other rival wins at least 3 games.
12. (10 marks) Suppose that the number of inquiries arriving at a certain interactive system follows
a Poisson distribution with arrival rate of 12 inquiries per minute.
Find the probability of 10 inquiries arriving a) in a 1-minute interval; b) in a 3-minute interval.
c) What is the expectation and the variance of the number of arrivals during each of these intervals?
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We need to find P(X > 3), where X is the number of defective parts in a sample of 10 parts. This
X is the number of ”successes” in 10 trials, therefore, it has Binomialdistribution with parameters
n = 10 and p = 0.1.
From the Table of Binomial distribution,
P(X > 3) = 1 − F(3) = 1 − 0.9872 = 0.0128
Or, by the formula of Binomial PMF, 2.
We need to find P(X > 5), where X is the number of tornadoes in major U.S. metropolitan areas
next year. Tornadoes are rare events, therefore, this X has Poisson distribution with parameter λ = 2 years−1.
From the Poisson Table, P(X > 5) = 1 − F(5) = 1 − 0.983 = 0.017 3. a.
Let X be the number of computers entered by the virus. Each of the 20 computers is
either entered or not, thus X is the number of ”successes” in n = 20 Bernoulli trials. Hence, X has
Binomial distribution with n = 20 and p = 0.4. From the Table of Binomial distribution,
P(X ≥ 10) = 1 − P(X ≤ 9) = 1 − 0.7553 = 0.2447 b.
We need to find P(Y ≥ 6), where Y is the number of computers tested until the first
infected computer is found. This is the number of trials required to see the first success, therefore,
Y has Geometric(p = 0.4) distribution. Using Geometric PMF (and geometric series),
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Another solution... The computer manager has to check at least 6 computers if the first five were
not infected. The first five computers are not infected with probability (1 − 0.4)5 = 0.0778. 4.
Let X be the number of crashed computers. This is the number of ”successes” (crashed computers)
out of 4,000 ”trials” (computers), with the probability of success 1/800. Thus, it has Binomial
distribution with parameters n = 4,000 (large) and p = 1/800 (small). a. Using Binomial
distribution with n = 4,000 and p = 1/800,
E(X) = np = 5 and V ar(X) = np(1 − p) = 5(1 − 1/800) = 4.994
This distribution is approximately Poisson with parameter λ = np = 5.
Using the Table of Poisson distribution with parameter 5,
b. P(X < 10) = F(9) = 0.968
c. P(X = 10) = F(10) − F(9) = 0.986 − 0.968 = 0.018 5.
The number of raisins X in one cookie is Binomial with n = 500 and p = 0.01. It is approximately Poisson
with parameter np = 5. The probability of finding at least 4 raisins is
P(X ≥ 4) = 1 − F(3) = 1 − 0.265 = 0.735 from the Poisson Table. 6.
a) N has Geometric distribution with p = 1/n because it is the number of independent Bernoulli
trials until the first success, and each trial is a success (correct password) with probability 1/n. Therefore,
P(N = x) = (1/n)(1 − 1/n)x−1 for x = 1,2,3,...
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b) Here, the probability of success increases after each failure, therefore, the distribution of N
is not Geometric. Since the order is random, the correct password has the same chance to
appear first, second, etc., in a sequence of trials. Therefore, P(N = x) = 1/n for x = 1,2,...,n
(this is called Discrete Uniform distribution).
c) In (a), the distribution is Geometric, so
In (b), the distribution is Discrete Uniform, so
Certainly, a smarter strategy (b) yields a smaller expected number of trials. 7.
a) X is Geometric(p = 0.2).
b) E(X) = 1/p = 5 and Std(X) = √1 − p/p = √0.8/0.2 = 4.47.
c) Y is Binomial(n = 10,p = 0.2).
d) E(Y ) = np = 2 and Std(Y ) = pnp(1 − p) = √2 · 0.8 = 1.265
e) From the Binomial Table, P(X ≥ 5) = 1 − F(4) = 1 − 0.9672 = 0.0328 .
f) P(Y ≥ 5) = (1 − p)4 = 0.4096 . 8.
a) In a given box, let X be the number of non-defective components. This X is Binomial, n =
5, p = 0.85. The probability of a box with five non-defective components is
P(X = 5) = (0.85)5 = 0.44 .
b) Now, let Y be the number of boxes with only non-defective components. This Y is also
Binomial. Its parameters are n = 10 and p = 0.44, where p is calculated in (a).
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c) This is precisely the number of trials needed to get the firstsuccess. Therefore, the
distribution is Geometric with p = 0.44. 9.
a) 12,000/150,000 = 0.08
b) Let X be the number of records read to find the first record tobe updated. Then X has the Geometric
distribution with p = 0.08, and P(X ≥ 20) = (0.92)19 = 0.2051 (Use the
Geometric PMF and compute the geometric series)
c) P(X = 20) = (0.92)19(0.08) = 0.0164 10.
a) Let the series continue till 7 games are played, and let X be the number of games won by
Dallas Stars. X has Binomial distribution with parameters n = 7, p = 0.55.
P( Dallas wins ) = P(X ≥ 4) = 1 − F(3) = 0.6083
b) LetY be the number of games won by Dallas among the first 6 games. Then Y has a
{ Binomial} distribution with parameters n = 6, p = 0.55.
P( 7 games required ) = P(Y = 3) = F(3) − F(2) = 0.3032 11.
a) The number of games played until the first Dallas Stars victory is Geometric with parameter
p = 0.55 and expected value E(X) = 1/p = 20/11. Then, the expected number of games until the 4-th victory is games
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We need to find the probability that Dallas Stars wins at least 4 of the first 9 games, and
it equals 0.8342 . Use Binomial(n = 9,p = 0.55) distribution. c.
This is the probability that the series lasts at least 7 games,which means that 6 games
weren’tenough, so Dallas had no more than 3 wins after 6 games. Using Binomial distribution
with n = 6, p = 0.55, we find that
P(X ≤ 3) = 0.5585 12.
a) Let X be the number of inquiries in a 1-min interval. Then X is a Poisson random variable with the parameter 12.
b. Let X be the number of inquiries in a 3-min interval. Then X is a Poisson random variable with the parameter 36.
c. For Poisson distribution with parameter λ, we have E(X) = V ar(X) = λ.
Therefore, for a 1-min interval, E(X) = V ar(X) = 12, and for a 3-min interval, E(X) = V ar(X) = 36.
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Document Outline
- PRACTICE PROBLEMS FOR HOMEWORK 4
- P(X ≤ 3) = 0.5585