Experimental Report 3
INDUCTOR AND FREE OSCILLATION IN RLC CIRCUIT
Full Name: Pham Mai Anh
Student ID: 20210053
Class: CTTT Cơ điện tử 03 - K66
Group: 1
Verification of the instructors
I. Experiment Motivations
- Understanding the current across an inductor-resistor and RLC circuit.
- Calculating the energy of the oscillation RLC circuit.
II. Experimental result
1. Resistance and Inductance of the coil
a. Without core
VS = 1.00 (V)
I0 = 0.11 (A)
Slope S = 1139.51036w/o
The resistance of the coil:
Coil inductance :
RL=VS
IO
=1.00
0.11=9.09(Ω)
LW/O=VS
IO×S=1.00
0.11×1139.51036=0.008(H)
b. With core
VS = 1.00 (V)
I0 = 0.09 (A)
Slope So= 265.94063
Coil inductance :
Explain: After putting the core inside the coil, the coil’s inductance is significantly increase (from
0.008 H to 0.042 H). This phenomenon occurred because the core has higher permeability than the air,
so magnetic field can be transferred through the core easier, thus the coil inductance increase.
LWO=VS
IO×S =1.00
0.09×265.94063=0.042(H)
2. Free oscillation of the RLC circuit
a. Frequency
The current in RLC circuit:
T = t - t2 1
t1 = 0.0157 (s)
t2 = 0.0176 (s)
T = 0.0019 (s)
Lw/o = 0.008 (H)
C = 10 x 10 (F)-6
The frequency based on the graph:
The frequency based on theoretical calculation:
fmeasured=1T=1
0.0019=526.32(Hz)
fprediction=1
2π
LC=562.70(Hz)
Comparison:
b. Energy
The total energy in RLC circuit:
U=Uc+UL=1 2CV2+1
2Li2
Comment:
- After stopping the electric power, the energy of the circuit does not decrease rapidly to zero, it
reduces to zero over a short period of time.
- The energy of oscillations of the coil and the capacitor are damped oscillations.
Explain:
The energy of the circuit loses by the heat of the resistor at rate i2R
Δf=fpredictionfmeasured=562.70 526.32 36.38 = (Hz)
The graph of total energy is steepest at the time that the magnetic energy reaches a local maximum
because in these times, the current through the coil is highest, and the loss of energy is mainly due to
the resistance of the coil (
ΔQ R=i2
).

Preview text:

Experimental Report 3
INDUCTOR AND FREE OSCILLATION IN RLC CIRCUIT Full Name: Pham Mai Anh Student ID: 20210053
Class: CTTT Cơ điện tử 03 - K66 Group: 1
Verification of the instructors
I. Experiment Motivations
- Understanding the current across an inductor-resistor and RLC circuit.
- Calculating the energy of the oscillation RLC circuit. II. Experimental result
1. Resistance and Inductance of the coil a. Without core VS = 1.00 (V) I0 = 0.11 (A) Slope Sw/o = 1139.51036
The resistance of the coil: RL=VS =1.00 0.11=9.09(Ω) IO Coil inductance : LW/O=VS IO×S=1.00
0.11×1139.51036=0.008(H) b. With core VS = 1.00 (V) I0 = 0.09 (A) Slope So= 265.94063 Coil inductance : LWO=VS IO×S =1.00
0.09×265.94063=0.042(H)
Explain: After putting the core inside the coil, the coil’s inductance is significantly increase (from
0.008 H to 0.042 H). This phenomenon occurred because the core has higher permeability than the air,
so magnetic field can be transferred through the core easier, thus the coil inductance increase.
2. Free oscillation of the RLC circuit a. Frequency
The current in RLC circuit: T = t - t 2 1 t1 = 0.0157 (s) t2 = 0.0176 (s) T = 0.0019 (s) Lw/o = 0.008 (H) C = 10 x 10-6 (F)
The frequency based on the graph:
fmeasured=1T=10.0019=526.32(Hz)
The frequency based on theoretical calculation: fprediction=1 LC=562.70(Hz) 2π √ Comparison:
Δf=fpredictionfmeasured=562.70 526.32 36.38 − = (Hz) b. Energy
The total energy in RLC circuit:
U=Uc+UL=1 2CV2+1 2Li2 Comment:
- After stopping the electric power, the energy of the circuit does not decrease rapidly to zero, it
reduces to zero over a short period of time.
- The energy of oscillations of the coil and the capacitor are damped oscillations. Explain:
The energy of the circuit loses by the heat of the resistor at rate i2R
The graph of total energy is steepest at the time that the magnetic energy reaches a local maximum
because in these times, the current through the coil is highest, and the loss of energy is mainly due to
the resistance of the coil (ΔQ=i2R ).