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Experimental report 6 Determination of specific heat ratio of air Based on clement desorme's method môn Vật lý đại cương 2 | Học viện Công Nghệ Bưu Chính Viễn Thông

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We can calculate theoretically the specific heat ratio of air by usingthe  equation γ= i +2 where i = 5 is the Degree of Freedom (DOF). Tài liệu giúp bạn tham khảo, ôn tập và đạt kết quả cao. Mời đọc đón xem! 

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Experimental Report 6
DETERMINATION OF SPECIFIC HEAT RATIO OF AIR
BASED ON CLEMENT DESORME'S METHOD
Name: Bùi Hoàng Quang Huy
Student ID: 202414727
Class: 760048
Group: 5
Verificationofthe
instructors
I. Purpose of experiment
- To determine the specific heat ratio = for air.𝛾 𝐶𝑝/𝐶𝑣
II. LAB Report
- The measurement results:
H=260mm
Trials L1 (mm) L (mm) h (mm) = L - L2 2 1
1 265 205 60
2 267 203 64
3 265 205 60
4 265 205 60
5 265 205 60
6 265 205 60
7 265 205 60
8 265 205 60
9 267 203 64
10 265 205 60
The mean value of h:
i
h=1
10∑
i=1
10
hi
= 60.8 (mm)
The uncertainty of h:
Δh=
√
∑
i=1
10
(
hi−h
)
2
10
=
4
√
10
25
= 0.5 (mm)
Therefore:
h± Δh ±=60.8
0.5 (mm)
The mean value of gamma and its uncertainty in equation:
γ=H
H−h
=
H1
(H−h )
−1
γ=H
H−h
=
260
260 60.8−
= 1.305
Δγ
γ=
√
(
ΔH
H
)
2
+
(
√
(ΔH)2+(Δh)
2×1
H−h
)
2
Since H is a constant value =>
ΔH
= 0
Δγ
γ=Δh× 1
H−h
Δγ
=
γ(Δh×1
H−h)
=
1.31
(
0.5
260 60.8−
)
= 3
×10−3
Therefore:
γ± Δγ=¿
1.305
±0.003
We can calculate theoretically the specific heat ratio of air by using the
equation where = 5 is the Degree of Freedom (DOF) of ideal gas γ= 2 i + i
(in this case it is air). Hence, we get:
γ= i 2 + =5
+
2=1.40
i5
The discrepancy between the measured value and the true value:
1.400-1.305 = 0.095
=>Relative error versus theory:
0.095
1.40
= 6.8%
The experimental result is different from the theoretical result due to
instrumental errors, observational errors and environmental
uncertainties.

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Experimental Report 6
DETERMINATION OF SPECIFIC HEAT RATIO OF AIR
BASED ON CLEMENT DESORME'S METHOD
Verification of the Name: Bùi Hoàng Quang Huy instructors Student ID: 202414727 Class: 760048 Group: 5
I. Purpose of experiment
- To determine the specific heat ratio 𝛾 = 𝐶𝑝/ 𝐶𝑣 for air.
II. LAB Report - The measurement results: H=260mm Trials L1 (mm) L2 (mm) h (mm) = L2 - L1 1 265 205 60 2 267 203 64 3 265 205 60 4 265 205 60 5 265 205 60 6 265 205 60 7 265 205 60 8 265 205 60 9 267 203 64 10 265 205 60 The mean value of h: 10 h=110∑ hi = 60.8 (mm) i=1 The uncertainty of h: √10∑(h i−h )2 = 4 √10 = 0.5 (mm) Δh= i=1 25 10 Therefore: h± Δh=60.8± 0.5 (mm)
The mean value of gamma and its uncertainty in equation: γ=H H−h =H1 (H−h )−1 γ=H 260 = = 1.305 H−h 260−60.8 Δγ γ= √(ΔH)2+(√(ΔH) )2 H 2+ (Δh)2×1H−h Since H is a constant value ΔH = => 0 Δγ γ=Δh× 1 H−h
Δγ =γ(Δh×1H−h) = 1.31( 0.5 ) 260−60.8 = 3 ×10−3 Therefore: γ± Δγ=¿ 1.305 ±0.003
We can calculate theoretically the specific heat ratio of air by using the
equation γ= i +2 where i = 5 is the Degree of Freedom (DOF) of ideal gas i
(in this case it is air). Hence, we get: γ= i +2 =5 + 2=1.40 i5
The discrepancy between the measured value and the true value: 1.400-1.305 = 0.095 =>Relative 0.095 error versus theory: 1.40 = 6.8% The experimental
result is different from the theoretical result due to
instrumental errors, observational
errors and environmental uncertainties.

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