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Topic 5: Consumer Choice using Utility Theory Name: Ta Quyet Tien Class: E-BBA 14.3 E-mail: Tienpbe12345@gmail.com Student code: 11226262 Problem 1:
1. From the hypothesis: "A consumer who uses $60 to buy 2 goods: X and Y.
Given that price of the good X is $3 per unit and price of the good Y is $1 per
unit", we have the budget line equation for this customer: 3X + Y = 60 Y = 60 - 3X
2. The utility function of this consumer is TU=XY. => MUX = (TU)X’ = Y. => MUY = (TU)Y’= X .
=> MRSXY = MUX / MUY = Y / X . 3.
- In order to maximize his utility: I = PXX+ PYY and MUX/PX = MUY/PY (=>
MUX /MUY = PX /PY Y/X = 3/1= 3) 3X + Y =60 and Y = 3X.
=> X=10 ( units) and Y=30 ( units).
- So, optimal quantity of good X (X*) and optimal quantity of good Y (Y*) is 10
units and 30 units respectively in order to maximize his utility. Problem 2:
1, Identify Lan’s budget line equation and draw that BL curve.
Lan’ s budget line equation: 20000x + 5000y = 1000000 Or: y = 200 – 4x
1, We have Lan’ s budget line equation: 20,000X + 5,000Y = 1,000,000. Or: Y = 200 – 4X. 2.
- We have the utility function for patato and meat is: TU= (X-2)Y.
So the marginal utility for meat is: MUX = (TU)’X = Y. and MUY = (TU)’Y = X-2.
- To calculate the amount of goods to maximize Ms.Lan’s total utility, we based on
budget line and indifference curve.
=> In order to maximize her utility: I = PXX+ PYY and MUX/PX = MUY/PY (=>
MUX /MUY = PX /PY Y/(X-2) = 20,000/5,000 = 4).
20,000X + 5,000Y = 1,000,000 and 4X – Y = 8.
=> X= 26 ( kg) and Y=96 (kg).
- So, optimal quantity of good X (X*) and optimal quantity of good Y (Y*) is 26
kilograms and 96 kilograms respectively in order to maximize her utility.